@@viditrawat1074 Not only helpful it's the right way! ships head in true degrees + relative bearing = true bearing. N.B.: You may have to subtract 360...For example, Ship heading 250 true + rel bearing of 315 degrees = 565 degrees - 360 = true bearing of 205 degrees. that can now be plotted.
Hello Mr Sailorstube. I would like to thank you very much as all of your videos have been extremely helpful for my studies for my Master under 500GT/ Second Mates Ticket. Especially the Celestial Navigation and the Stability. Thank You Thank You Thank You :)
I thinks there's a little mistake there in the end.. True Bearing= 100 deg. T/Co= 250. That makes the relative bearing -150 plus 360 to make it positive which makes 210 deg. but still a very good lesson, cheers!
+John Kenneth Mercolita Thank you very much for noticing the same. Well, you are right and same has been corrected using speech bubble. Appreciate your attentiveness.
I agree with that case... It supposed to -150 is the value of Relative Bearing... But anyway, we have learned for this video... Thanks and credit to the owner...
3:50 What do you call on this part? 2:15 The relative bearing in this part is wrong right? It should start from the ship's head in a clockwise direction to the line of sight of an object as what you have said.
Great job done. Kindly compare in the last part of the video about conversion of bearing from True bearing to Relative bearing and vice versa. Thank you.
Thanks for the appreciation. The last example has some typo error which was corrected with UA-cam annotation, which may not show on all devices. Nevertheless, correct relative bearing is 210 instead 200 .
Sir any video how to calculate eta.when speed and distance between two places is given.and journey starts.time also given. Like, start journey at 11 am 0340 hrs dist.1888nm spd 10 kt
Hello sailorstube, i'd like to tell you that you are doing a great job and i strongly appreciate your efforts. I have a small doubt and would be grateful if you clear it. My question to you is :- How can i find true north on a ship and also the true direction of my ship's head?
You can find true north with the help of correct gyro compass. Alternatively you can establish north direction with the help of Polaris or Pole star , which approximately ( with in a degree) lies in north direction. So ships true direction is the clock wise angle from north direction to the ship heading or fore and aft line of ship .
Please help me to solve the problem, finding abeam,true bearing and relative bearing? I don't know how to solve the problem sir kindly please personalized message.
A small trick I would like to share, just remember “SHIRT”. Ship’s head (SHI)+ Relative bearing (R) = True bearing (T)
It's really helpful,thanks alot .
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@@viditrawat1074 Not only helpful it's the right way! ships head in true degrees + relative bearing = true bearing. N.B.: You may have to subtract 360...For example, Ship heading 250 true + rel bearing of 315 degrees = 565 degrees - 360 = true bearing of 205 degrees. that can now be plotted.
Hello Mr Sailorstube. I would like to thank you very much as all of your videos have been extremely helpful for my studies for my Master under 500GT/ Second Mates Ticket. Especially the Celestial Navigation and the Stability. Thank You Thank You Thank You :)
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I thinks there's a little mistake there in the end.. True Bearing= 100 deg. T/Co= 250. That makes the relative bearing -150 plus 360 to make it positive which makes 210 deg. but still a very good lesson, cheers!
+John Kenneth Mercolita
Thank you very much for noticing the same. Well, you are right and same has been corrected using speech bubble. Appreciate your attentiveness.
Relative bearings are measured clock-wise or anti-clockwise and up to 180 degrees only, in this case it is -150 or 150 degrees R to the port.
Ive noticed the same
I agree with that case... It supposed to -150 is the value of Relative Bearing... But anyway, we have learned for this video... Thanks and credit to the owner...
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Bearings can only be calculated on a flat stationary plane, thank you for proving this point, excellent!
Wrong.. flattard
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Thanks
Although i was studying for aviation.It helped me understanding concept.
Geet Sapra the same for me hahah, the video helped me a lot as well
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Sir you explained very nicely. Feeling very satisfied
Thanks.
very nice video ........... very helpfful ....... just a small correction @ 6:48 mins - the relative bearing = 150 deg and not 160 deg.
Danish Pawne yea, I noticed as well. Cos was not matching with my maths kkk
Nice video though
Thanks I thought I was going mad
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The art of complicating something simple.
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@@KUNDANKUMAR-ik7ft What the hell kind of an answer is this ?
at 5:28 how'd you get the 210 degrees? is it given?
yes it is bro
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-150+360=210
3:50 What do you call on this part?
2:15 The relative bearing in this part is wrong right? It should start from the ship's head in a clockwise direction to the line of sight of an object as what you have said.
Im also confused. Additional question. If the object is 45 degree on your portside. Is it not a relative bearing 45 degree?
Very well explained ♥
Great job done. Kindly compare in the last part of the video about conversion of bearing from True bearing to Relative bearing and vice versa. Thank you.
Thanks for the appreciation. The last example has some typo error which was corrected with UA-cam annotation, which may not show on all devices. Nevertheless, correct relative bearing is 210 instead 200 .
Thank you very much and more power.
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Please explain me about course and heading in detail
Please How did you get -160? Instead of -150
Ie 100-250
Demonstrate the proper procedure in reporting bearings and sightings of objects on the compass repeaters?
Is relatively bearing always given? 210 during the last part of the video
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If the object is on your port bow, is it 45 degree relative bearing?
Tb100-tc250= -150+360=rb210 ?
Yeah thats correct
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Sir any video how to calculate eta.when speed and distance between two places is given.and journey starts.time also given. Like, start journey at 11 am 0340 hrs dist.1888nm spd 10 kt
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how do you get the relative bearing 210°?
that's my question too!
relative bearing can be obtained with the help of gyro compass in ship.
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@@ferdinandmichael6338 yes,
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@@mrchristian8782 For 2nd mate/DNS/Bsc NS prepration join kundan patna #kundanpatna
Hello sailorstube, i'd like to tell you that you are doing a great job and i strongly appreciate your efforts.
I have a small doubt and would be grateful if you clear it.
My question to you is :-
How can i find true north on a ship and also the true direction of my ship's head?
You can find true north with the help of correct gyro compass. Alternatively you can establish north direction with the help of Polaris or Pole star , which approximately ( with in a degree) lies in north direction. So ships true direction is the clock wise angle from north direction to the ship heading or fore and aft line of ship .
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How.to.get relative bearing if the given is true.heading
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it cleared my concept. thnx
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Relative BRG= ( (-)160° )
How does that came?
Kindly Explain
It suppose to be -150° right
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Excelllent
Exceptional!
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Thank you sir
Can you explain homing.pls
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Please help me to solve the problem, finding abeam,true bearing and relative bearing? I don't know how to solve the problem sir kindly please personalized message.
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Last One You Say Wrong
True Bearing = 100°
True Course = 250°
= -150° + 360°
Relative Bearing = 210°
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Thanks for the help
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Thanks
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Eyvallah
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Couldn’t take it seriously with that heavy accent 😂
100-250= -160?
what???
Yes there is typo error.Pls read correction in the description. Difficult to edit in UA-cam
@@sailorstube3259 I do sir, that and you for the video by the way!
52098/ESQUISSE.
P.C.P. '1997/'2007, S.E.A.
HP 4927 SCOOLARSHIPS.
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PAMMA
sk noob
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