I typically never comment but I'm a sophomore in high school and i'm supposed to be taking a test on this. My teacher has tried to teach us time after time and no one understood. Here I am 10 minutes into the video and now I understand how to do this from start to finish. Thank you, much appreciated🙏
This was such a helpful video! Thank you for thanking the time and fully explaining every part. You explained better than how my teacher explained, and I mean no offense since he’s a good teacher! I appreciate you!
Thank you!! I'm in quarantine and my school doesn't have online classes so my geometry teacher just assigns us a bunch of work with no explanation of how to do it. This is the first video that really helped me grasp the concept.
You're very welcome- thanks for letting me know! I have many more Geometry videos on the channel so be sure to look around. Also, I'll be adding an entire series on circles in high school Geometry over the next few weeks.
Thanks! I am using smart notebook for the workspace (which unfortunately is kind of pricy), and Screencast-O-matic to record the screen (awesome free tool).
1 year later and this video is still amazing. I still teach my students this method. Something I added in was giving the triangle in the first example 2 angle measures of 70 and 20 degrees so that students can truly be convinced they are similar. After that first example, then I have the students only use angle markings (no degrees)
@@dawsontate2989 That's awesome, I'm so glad to hear it! Yes, starting with numerical values is terrific strategy to really make it concrete, especially for a first example 😄
Thanks very much Jim! I'm working hard to put out 3-4 new Geometry and Pre-Calculus videos a week right now. If you know anyone who may benefit from them please share the channel 😀
all three sides of triangle are initially meters in length , one of the triangles sides is oriented horizontally the triangle is scaled down in size without changing any angles , what is the new height of triangle when area is exactly half of the original triangle area ?
I'm not 100% sure of the question your'e asking, but here's my best shot. If the area of the triangle AFTER the dilation ends up being 1/2 the original area, then the triangle must have been dilated by a scale factor of 1/(sqrt(2)), or rad(2)/2. Therefore, ALL lengths of the new triangle will be that scale factor times the corresponding length in the original triangle. If the original triangle had a height of H, then the new triangle has a height of Hrad(2)/2. Does that answer your question? If not, let me know. If you're interested in learning more about similar triangles in general, check out this video: ua-cam.com/video/TgEhYfkLMDw/v-deo.html
You're good. As long as you set up a valid proportion you will get the same equation when you "cross multiply." Notice that when you "cross multiply" you get 5(54) = x^2, same as me. 👍
Well, I guess I don't truly know. You could have done something wrong, that happened to end up with the right proportion, but I can tell you that your proportion is A valid proportion for this problem. Here's ONE way to arrive at the proportion you have. Starting with 6 in the smaller triangle. 6 is between the right angle and the one tic blue. In the larger triangle, between the right angle and one tic blue you find x. Then, back to the smaller triangle, the hypotenuse is x, which corresponds to the hypotenuse of the larger triangle, 54.
I don't follow your comment. You say THALES, which I presume is meant to invoke THALES' theorem, but that is not needed since we already know it is a right triangle. Your first equation is the one I solved to find x in the video- I am not sure what your second equation is meant to represent (20 + 16 = 36). IF we needed to solve for the remaining sides of the larger triangle (which we don't), I would use Pythag as you suggest in your final two equations. What is the complicated process to which you refer?
Every example is knowledge of the hypotenuse. What if you know nothing about the hypotenuse, but know the 2 legs - “A” & “B”? How do u solve for the altitude?
Thanks for watching. In that case, use Pythag to find the hypotenuse and then proceed as shown in the video. Remember, anytime you have two legs of a rt triangle you can always find the 3rd with Pythag 😄
I typically never comment but I'm a sophomore in high school and i'm supposed to be taking a test on this. My teacher has tried to teach us time after time and no one understood. Here I am 10 minutes into the video and now I understand how to do this from start to finish. Thank you, much appreciated🙏
Oh wow, that's such wonderful feedback, I'm so glad it helped you. Thanks so much for letting me know 😄
finally a video that takes it time and actually explains it. thank u
This was such a helpful video! Thank you for thanking the time and fully explaining every part. You explained better than how my teacher explained, and I mean no offense since he’s a good teacher! I appreciate you!
Thank you so much! Sometimes it just helps to hear it from someone else- it can reinforce what you’ve already learned. So glad you found it helpful 😀
Wow, thanks alott, I've been trying ti find the right video for 3 hours straight. Thankss alottttt
That’s terrific! Glad it helped you out, thanks for watching 😀
you explained everything so clearly and step by step! THX!
Thanks so much! Glad you found it helpful 😄
Great Job!
I'm a student teacher and I'm suppose to teach this topic
You're explanation is what my students need! Thank you for sharing!
Thanks so much, I'm glad you found it useful : )
Student okay STUDENT TEACHER BRUH U NEED GEOMETRY IN UR LIFE
Thank you!! I'm in quarantine and my school doesn't have online classes so my geometry teacher just assigns us a bunch of work with no explanation of how to do it. This is the first video that really helped me grasp the concept.
You're very welcome- thanks for letting me know! I have many more Geometry videos on the channel so be sure to look around. Also, I'll be adding an entire series on circles in high school Geometry over the next few weeks.
@@RealMikeDobbs thank u
@@muskanmeena6963 You're welcome 😄
Thank you so much! You explained it so well. My son and I watched this and it really cleared up this concept for us.
That's terrific! Thanks for letting me know 😄
amazing explanation, will help on my quiz tomorrow!
Thanks so much! Very glad to know it helped you 😀
I completely forgot how to do this stuff. Thanks a lot👍
You’re very welcome 😀
4 years old and it's still helping students, tysm for this, it is really informative and understandable
Thank you so much 😀
It’s always wonderful to hear from people who find my videos helpful.
i finally understand it after 4 other vids ur the best u just earned a sub
That’s great to hear Corey! I’m really glad it helped you out 😀
Super clear and easy to understand. Thanks.
Glad it was helpful!
Really helpful and understandable!! I watched many videos on this and this is the first one I understood
So glad you found it helpful : )
Thanks for letting me know.
@@RealMikeDobbs same here, i watched two three videos, but was still confused. This was really helpful
coól i mean its so clear and easy to understand great work dudë
Thanks so much! I'm glad you found it helpful 😄
I love your work
what is the program you used ?
Thanks! I am using smart notebook for the workspace (which unfortunately is kind of pricy), and Screencast-O-matic to record the screen (awesome free tool).
Thank you SOOOO MUCH u made it so easy for me to understand
That’s awesome- thanks so much for letting me know 😀
It was a really helpful video, thank you so much!!!!!!!
That great to hear, thank you 😄
Thanks a lot. Amazing explanation.
Thank you so much! Glad you found it useful 😀
My good sir I thank you , my zooms aren’t enough teaching and this helped simplify things alot
That's great to hear, thanks so much! 😄
Great video sir! You really helped me learn this topic for math
Thank you so much! Glad to hear it helped 😄
Wow this really helped me thank you so much
I'm so glad, thanks for letting me know 😄
thx so much
Awesome videos. I wish my son got a teacher like you.
Thank you so much ❤️
Nice explanation, thanks
This video was great!!
Thanks so much! Glad you enjoyed it 😄
1 year later and this video is still amazing. I still teach my students this method.
Something I added in was giving the triangle in the first example 2 angle measures of 70 and 20 degrees so that students can truly be convinced they are similar. After that first example, then I have the students only use angle markings (no degrees)
@@dawsontate2989 That's awesome, I'm so glad to hear it! Yes, starting with numerical values is terrific strategy to really make it concrete, especially for a first example 😄
thanks this really helped me understand this topic better
So glad to hear that 😀
Thank you soooo much
You’re very welcome 😀
Thanks for this class
Glad it helped 😄
Thank you so much this helped a lot
That's terrific, so glad it helped you 😄
You are awesome!!!!
Thanks so much- what an awesome comment 😄
fantastic job!
Thanks very much Jim! I'm working hard to put out 3-4 new Geometry and Pre-Calculus videos a week right now. If you know anyone who may benefit from them please share the channel 😀
Sir yours maths videos are very helpful
Thank you
You're very welcome : )
Thanks. 🙏
You’re very welcome 😀
Thank you...
You’re very welcome- glad to know it helped 😀
Nice one 🙏
Thank you 😀
all three sides of triangle are initially meters in length , one of the triangles sides is oriented horizontally the triangle is scaled down in size without changing any angles , what is the new height of triangle when area is exactly half of the original triangle area ?
I'm not 100% sure of the question your'e asking, but here's my best shot. If the area of the triangle AFTER the dilation ends up being 1/2 the original area, then the triangle must have been dilated by a scale factor of 1/(sqrt(2)), or rad(2)/2. Therefore, ALL lengths of the new triangle will be that scale factor times the corresponding length in the original triangle. If the original triangle had a height of H, then the new triangle has a height of Hrad(2)/2. Does that answer your question? If not, let me know. If you're interested in learning more about similar triangles in general, check out this video: ua-cam.com/video/TgEhYfkLMDw/v-deo.html
Thanks brother 😊 new subscriber i am
Thanks so much! Glad you found it helpful 😀
Thanks! This is helping me help my son with his 10th great geometry homework
I'm so glad you both found it helpful!
Which tool do you use to write expressions?
I work in Smart Notebook for the slides and handwriting. The typed equations are made with MathType and screen captured into Smart Notebook.
Also of sides of right tri are given perpendicular to hypotenuse is (perpendicular*base)/hypotenuse
Hey, thanks for watching. I'm not sure what you are saying here. You seem to be defining the altitude in terms of itself. Are you able to clarify?
saved my day
God to hear it- lots more videos on the channel. 👍
Thank you
You’re very welcome 😀
@@RealMikeDobbs you really explained it very well. I saw two other videos as well but you are awesome. Thank you for such great video.
Thanks so much for the feedback! So glad you found it helpful.
20:34 how did you get 64
I'm not sure what you mean, I don't see any questions with 64 as the answer.
My last proportion looks a little different from yours. I wrote 6/x=x/54. Does that matter?
You're good. As long as you set up a valid proportion you will get the same equation when you "cross multiply." Notice that when you "cross multiply" you get 5(54) = x^2, same as me. 👍
@@RealMikeDobbs How do I know that I set up the proportion correctly?
Well, I guess I don't truly know. You could have done something wrong, that happened to end up with the right proportion, but I can tell you that your proportion is A valid proportion for this problem. Here's ONE way to arrive at the proportion you have. Starting with 6 in the smaller triangle. 6 is between the right angle and the one tic blue. In the larger triangle, between the right angle and one tic blue you find x. Then, back to the smaller triangle, the hypotenuse is x, which corresponds to the hypotenuse of the larger triangle, 54.
Nice video
Thanks so much 😀
How do u find the altitude when ur given 20 instead of 18 and 2 for the base??
You’ll need to be a little more specific there, I’m not sure what you’re asking.
THALES, 18×2=X², 20+16=36, x=6. Why do you think it necessary to use the complicated process?
6²+2²=a², 6²+18²=b²
I don't follow your comment. You say THALES, which I presume is meant to invoke THALES' theorem, but that is not needed since we already know it is a right triangle. Your first equation is the one I solved to find x in the video- I am not sure what your second equation is meant to represent (20 + 16 = 36). IF we needed to solve for the remaining sides of the larger triangle (which we don't), I would use Pythag as you suggest in your final two equations. What is the complicated process to which you refer?
perfect
Thanks Johnny 😄
Every example is knowledge of the hypotenuse. What if you know nothing about the hypotenuse, but know the 2 legs - “A” & “B”?
How do u solve for the altitude?
Thanks for watching. In that case, use Pythag to find the hypotenuse and then proceed as shown in the video. Remember, anytime you have two legs of a rt triangle you can always find the 3rd with Pythag 😄