Moment of Inertia of an Iron Beam's Cross Section
Вставка
- Опубліковано 17 вер 2024
- Download the Manas Patnaik app now: cwcll.on-app.i... Make sure you have seen the video on "How to apply Parallel axis theorem"
Here is the link: • How to apply Parallel ...
In this video, we will determine the #momentofinertia of an Iron Beam's Cross Section.
Watch the video, right till the end to have firm grasp on the concept.
#engineeringmechanics
#appliedmechanics
#fundamentalsofmechanicalengineering
#whatiscentroid
#whatiscenterofgravity
#whatiscentreofgravity
#centroid
#momentofinertiaofcompositeplane
Super super easy explenation, thank u so much sir. 👏
Small correction guys:
At timeline 05:10, I should have written Pi.r^2/2....
But the answer works out as 39.27 cm^2...
Rest is fine...Not to worry...
What would be the changes will happen if we considering another reference axes rather than given reference axes/?
i was just getting mad how come that the value is 39.27.
A2=A3 = (pi * 25 )/2 = 39.2699
x3 = 12-x2=12-2.12=9.88
lmao i questioned my whole life existence for a moment there
thanks G O A T
Excellent explanation. Just missed to write (2) while showing formula for area's of semicircle divided by 2. Also checked answer is matching. Thanks
the way u teach sir,awesome and very easy to learn, thank you i got passed in mos because of ur videos
sir,how to find out centroid of semicircle with axis tilted
Is there any formula like finding out moment of inertia of semicircle..
Sir... Upload some more problems on moment of inertia
Thank you so much you have added alot to my knowledge of mechanics
Thank u ......Keep learning and do share it with your friends.........aLL the best
Sir i, ve heard from my teacher dt if a body is symmetric about x_axis it's y bar is zero... How ❓❓ i, m getting confused... Wt is the right answer?
Thank you so much Manas Patnaik!
two semicircle same distance from centroidal y axis
Thank you, u r a genius
Thanks sir today was my paper and I read complete mechanics before from your videos itself and this was the last question which I saw before entering exam hall .
Thanks a ton ❤️
I am sure you will do well in exams. Good luck
@@ManasPatnaikofficial Yes sir sure.... thanks once again ❤️
why don't you consider symmetric about x. axis or y. axis??? Sir. .
I like the way he speaks...
Please what if the rectangle is labeled abcd and the question ask to find about ab axis
need help....!! where did you get the 0.11 and 0.393 on the semicircle..? I only saw these number in your video... thank you
Thats a formula
Thank you
Sir area of semi circle is pi r^2/2
Yes u r right....I should have written Pi.r^2/2....
But the answer works out as 39.27 cm^2
Manas Patnaik yes sir
Nice explanation thank you very much sir
Amazing video :D
Great job Sir...
keep uploading 😊😊
Great explanation video👍👍😊
Sir area of semicircle is wrong it is pi r^2/2 kk thank you sir
Thank your for your explanation, what about Ixy ? Is it Will always be 0?
Good concept
Sir Thank you. Pass karwa diye.
Thanks sir its helps a lot
Sir please upload a video on derovation of Moment of inertia of shapes like semicircle, quarter circle, triangle etc. Please sir
Even i was thinking about that...
till then u can watch stuff from these playlists.
Topic-wise Playlist of Engineering Drawing / Engineering Graphics in English
1. Orthographic Projection: ua-cam.com/video/WG6H2pISUzQ/v-deo.html
2. Projection of Point: ua-cam.com/video/fK4h5gM73w8/v-deo.html
3. Projection of Line:
OLD:
ua-cam.com/play/PLIhUrsYr8yHz_FkG5tGWXaNbIxVcibQvV.html
NEW:
ua-cam.com/video/pzE0D-Ijxd4/v-deo.html
4. Projection of Plane: ua-cam.com/play/PLIhUrsYr8yHx7TVB51jN3HZVyW3R6RiBg.html
5. Projection of Solid: ua-cam.com/play/PLIhUrsYr8yHxARPzEFz1nXgt8j6xF_tEm.html
6. Section of Solid: ua-cam.com/play/PLIhUrsYr8yHwAbiCATZUbzd_CpF0EHF3v.html
7. Development of Surface: ua-cam.com/play/PLIhUrsYr8yHwdB96ft6c0Uwc4SDCLuG1v.html
8. Auxiliary Plane: ua-cam.com/play/PLIhUrsYr8yHxHWk2TCg1SrphF1vKpHXoB.html
9. Interpenetration of Solids: ua-cam.com/play/PLIhUrsYr8yHyTGceE1TGhCSxxfHyFpnNM.html
10. Isometric Drawings: ua-cam.com/play/PLIhUrsYr8yHxVky7bfrnbRcdXcHjT_K83.html
11. Conic Sections: ua-cam.com/play/PLIhUrsYr8yHx0TuqsY0FUZ7Z24BbKxJoQ.html
12. Cycloidal Curves: ua-cam.com/play/PLIhUrsYr8yHwwA8eBea78pJW1lw9XAv6z.html
13. Involute:
ua-cam.com/play/PLIhUrsYr8yHzu8pqYvGwQoJKVpuS1Jusa.html
14. Plain Scale and Diagonal Scale: ua-cam.com/play/PLIhUrsYr8yHwTgo_zu_ELqOC1ypcp5Gr9.html
15. Complete Engineering Drawing in one single Playlist: ua-cam.com/play/PLIhUrsYr8yHwDUrVYmUNYkEeZgZTvoIfS.html
Topic-wise Playlist of Engineering Drawing / Engineering Graphics in Hindi
1. Orthographic Projection in Hindi: ua-cam.com/play/PLIhUrsYr8yHy3chHVzYA4BMbY9DbhyYSY.html
2. Projection of Point in Hindi: ua-cam.com/play/PLIhUrsYr8yHwinNUxVA1NW0xxLRlDfINH.html
3. Projection of Line in Hindi: ua-cam.com/play/PLIhUrsYr8yHyvWb87YtG3A3jDEnChgzir.html
4. Projection of Plane in Hindi: ua-cam.com/play/PLIhUrsYr8yHxj9N5e1oZA0x_k5ZVssf3U.html
5. Projection of Solid in Hindi: ua-cam.com/play/PLIhUrsYr8yHylYPjrulRGm8DSPiimxP3P.html
6. Scales Hindi-Urdu:
ua-cam.com/play/PLIhUrsYr8yHzJA426HjlEmiRqUkJTkozB.html
Topic-wise Playlist of Engineering Mechanics / Applied Mechanics / Fundamentals of Mechanical Engineering in English
1. Forces:
ua-cam.com/play/PLIhUrsYr8yHzoyUutEK57JzWy1n-vxIS0.html
2. Friction:
ua-cam.com/play/PLIhUrsYr8yHwY1TDraJpyYkU8Zug-kM4m.html
3. Shear Force and Bending Moment: ua-cam.com/play/PLIhUrsYr8yHy1lc0hEhbpEAGsGwNmUWt7.html
4. Trusses:
ua-cam.com/play/PLIhUrsYr8yHwIXEt9cqjEsEO8l83xcIf7.html
5. Centroid and Centre of Gravity: ua-cam.com/play/PLIhUrsYr8yHzZ52dVA3wQ_0IQVl7CKL7p.html
6. Moment of Inertia:
ua-cam.com/play/PLIhUrsYr8yHw8qWxAVOx-5Y2XfGPOmcDy.html
7. Dynamics:
ua-cam.com/play/PLIhUrsYr8yHwOZxmY63A_lURu6c-jNk-z.html
8. Complete Engineering Mechanics / Applied Mechanics in one single Playlist: ua-cam.com/play/PLIhUrsYr8yHxfOmcGIeUThHEr9lQ3IXRS.html
THANK YOU SO MUCH...........
just a doubt that is the formula (y-Ybar)square is applicable for all composite section in case of centroidal axis.
Sir area pi r square by 2 hoga na
sir does removing semicircles dont change the position of centroid?
Hello.at 7:48 you explain iparallel=0.11r² and iperpendicular=0.393r²,I am confused because many textbooks say ix =iy for semicircle is 0.393r².they do not mention 0.11r².please explain why.thank you.
Even this lecturer says ix=iy in this link ua-cam.com/video/idKWlkgKXzM/v-deo.html please skip 5:17.thank you.sorry to bother you
Aman....
Come on FB messenger, lets have a quick chat......
Hi.i messaged you now.thank you again
I have same Question.......plz clear my doubt too
@@faisalnazir9067 in this video Mr.Manas takes MOI from center of semi-circle while many text books give you MOI from edge of semi-circle...BOTH ARE CORRECT, just check if you are at CENTER or EDGE
how to calculate the moment of area for the singly reinforced beam?
Wonderful sir
Tq u so much sir
Can we apply direct method of finding centroid to I,Z,C section of rectangle??
Very nice sir 👌👌👍
I'm getting problem with M.O.I. OF SEMI CIRCLE ABOUT x-x & y-y axis
Plse reply with clear concept hearty request 🙏🙏🙏
Thanq sir
Sir what is the moment of inertia of semi circle along y-axis
Sorry I think that when you are calculating the area of semi-circle you made some eror that is πr square divided by 2 becouse it is semi-circle
Thank you very 😇 much.
Thank you sir
Kindly help us to find the polar moment of inertia and the radius of gyrations
MOI OF semicircle ?? Is there any video ??plz reply
THANK YOUUU!!!!!!!!
Please, where can I find this question in the source?
sir can u pls explain moment of inertia of inverted T section
y the two semicircles are subtracted sir?
0.11 formula If we do not know how can we solve with 0.393
Pls tell about MoI of L section
Area of semi circle =pi r*2/2
nice
area of x2 and x3 is wrong and iyy3 is also wrong becoz of x3 has been changed
Sir small doubt ,can moment of inertia can be negative value ?
No it will never be because area and distance will both always be positive themselves more or less on a plane it wont be negative. I think correct me if i am wrong
12:32 to 12:40
I yy2 and I yy3 values will not be same
sir rolling ka video chahiye pls
1:39 X does not match 6 after verification
In text book taking x1=-6 why
09:40
09:40 to 10:00
Problems on product of inertia
sir pls upload derivation for moment of inertia for rectangle,semi circle,triangle,etc.,
Area of semicircular is wrong
First like
a little bit mistake of figure 2
Wasted my 3 hrs as u was not getting right answer because you had written Area of semi circle wrong..., rest is good..
All things are correct but addition is wrong.
I think he subtracted the value of the rectangle from the values of two semicircles (since it's a hollow in the rect)
Yrr
Faltu
Sir, can you explain how to get 0,11r⁴ for the Inertia of si circle?