Evaluating Numbers Raised to Fractional Exponents

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  • Опубліковано 5 лис 2024
  • Thanks to all of you who support me on Patreon. You da real mvps! $1 per month helps!! :) / patrickjmt !! Evaluating Numbers Raised to Fractional Exponents - Many examples of evaluating numbers raised to fractional exponents are shown along with the general rules! For more free math videos, visit PatrickJMT.com

КОМЕНТАРІ • 164

  • @nickcolejackson6884
    @nickcolejackson6884 9 років тому +9

    I am in Calculus and had to go back to these exponent rules because I did not understand fractional exponents as well as I do now. Thank You so much for refreshing my knowledge on fractional exponent because I need to know these well to find Critical numbers. My professor loves to add fractional exponents on the quizzes and exams; therefore, if I am not a pro at this concept, even though I know the Calculus, I am defiantly in deep trouble. My answer will be wrong because I have to always simplify to the lowest extent. Thank You for giving me some free education, you do not know how much you have helped me.

  • @DullahOblongata
    @DullahOblongata 13 років тому

    My teacher spent 90 minutes trying to teach this and still failed at it. and now i perfectly get it from your video. thank you so much

  • @antioch112
    @antioch112 13 років тому

    Thank you for helping this teacher prepare for his math certification exam tomorrow! You are an excellent teacher...may God bless you!

  • @plumcrazypurp
    @plumcrazypurp 15 років тому

    you're definetly the best guy making math videos for youtube

  • @patrickjmt
    @patrickjmt  15 років тому

    you have no clue and yet... you post the longest most rambling stuff. i love the internet

  • @patrickjmt
    @patrickjmt  15 років тому

    make sure you have mastered basic arithmetic - most people still can not add fractions with numbers, so when you throw variables in, it is : game over man, game over

  • @alitou001
    @alitou001 12 років тому

    I had to come back to this lesson Eventhough iam a calc2 student . I pinpointed my weaknesses in math and now im using your videos to cover up that. Thank you sir

  • @crockercharlotte
    @crockercharlotte 14 років тому

    You have taught me in 10 minutes what I couldn't grasp in 3 years. THANKYOU

  • @touzongthao9643
    @touzongthao9643 7 років тому +1

    Taught me better than my own teacher! YOU DA BEST!

  • @SenorRamos
    @SenorRamos 15 років тому

    You are a life saver. Its been years since I have had to do this type of math and your video was a great refresher!

  • @gravebutterfly
    @gravebutterfly 14 років тому

    Yo, this was super helpful, i ended up missing a week of class and this really helped prep me for the test.

  • @patrickjmt
    @patrickjmt  13 років тому

    @TheMaaneetLuver no problem, happy to help!

  • @camrynlong1094
    @camrynlong1094 2 роки тому

    so helpful! my teacher didn’t teach us anything like this all year and then it showed up on the final exam review. you really pulled through!

  • @domnacorda
    @domnacorda 13 років тому

    Thank you! You are my only professor in my self-conducted college application review, and yet you make it easy for me. Thanks a lot!

  • @AL3Xmotodude
    @AL3Xmotodude 16 років тому

    thanks alot man. This really helped me out. My math teacher never explained this to us even though we got questions like these on our homework.

  • @1stholly
    @1stholly 16 років тому

    Thanks! you are a life saver. I am not a math gifted person, and my teacher doesn't help much, so I appreciate your help :)

  • @djjoelroche
    @djjoelroche 14 років тому

    I am less stressed out about this upcoming school year because of this thank you Patrick!!! :D

  • @ericaking1223
    @ericaking1223 12 років тому

    I'm always relieved when I don't know something and see your video. Thanks :)

  • @patrickjmt
    @patrickjmt  14 років тому

    @addiktion13 ok, sounds good! : ) also, did not mean to 'call you out', just wanted to clarify things for you and others! it is certainly a common little mistake though, one that i am sure i have also made!!

  • @froggygirl22
    @froggygirl22 15 років тому

    OMG THANK YOU!
    took me long enough time to help me with my math exam review :)
    Your my hero to the max for this

  • @laurenlin2
    @laurenlin2 9 років тому

    This video really helped ! My math teacher didn't go into details on how to do this with negatives, so thanks !

  • @patrickjmt
    @patrickjmt  13 років тому

    @spuddapotato2494 you are very welcome : )

  • @yourmomisfat69
    @yourmomisfat69 13 років тому

    MUCH BETTER THAN MY HIGH SCHOOL MATH TEACHER!!! THANK YOU

  • @MK_ChessPlayz08
    @MK_ChessPlayz08 Місяць тому

    This was the most helpful video for me that is about fractional exponents! Thank you so much!

    • @patrickjmt
      @patrickjmt  28 днів тому

      excellent! glad it helped

  • @patrickjmt
    @patrickjmt  14 років тому

    @deco101 u r very welcome

  • @Aquamissile42
    @Aquamissile42 14 років тому

    @fafase Not exactly. What people don't get is that -x^2 isn't the same as (-x)^2. Since exponents are done before multiplication, and that the negative sign is basically multiplying by negative one, you have to do the x^2 first before giving the x a negative value, in the first one. In the second one, the multiplication by negative one is done before the exponents due to the parenthesis. That's why
    -x^2 is always negative, and that (-x)^2 is always positive.

  • @teritot
    @teritot 13 років тому

    haha. great! i missed two classes this week and we have a test next class. THANKS FOR THE HELP! you explained it so well. I've never done this before and i'll be fine for the test just from watching your video!

  • @patrickjmt
    @patrickjmt  16 років тому

    i am not sure how to help you on the programming end of things... i took a C class, but that was about 10 years ago...

  • @keniangervo8417
    @keniangervo8417 10 років тому +4

    Why is 8^2/3 the same as [8 1/3]^2? What's the reason/logic/rule behind getting that result?

    • @Sam-tf9ip
      @Sam-tf9ip 7 років тому

      Keni Angervo When an exponent is taken to the power of something you can multiply them. Ex : (2'3)'2
      That's 2'3 • 2'3. Instead of writing it out like that though, we can just take the '3 and '2 times each other and get '6. The answer is 2'6 or 64

    • @Sam-tf9ip
      @Sam-tf9ip 7 років тому

      Keni Angervo Now, because you can multiply an exponent multiplied by an exponent, you can see how (2'1/3)'2 is equal to 2'2/3 because 1/3 • 2 is 2/3

  • @freechoas
    @freechoas 11 років тому

    Today I have seen all the exponents , and I have understood everything so thank you teacher :)

  • @sezzafezza
    @sezzafezza 9 років тому +2

    Thank you so much I'm finally able to understand this!!

  • @lexinaut
    @lexinaut 14 років тому

    (like)(like)(like) is like to the third power. Very clearly presented.
    Obey the Laws of Exponents!

  • @yassinel1882
    @yassinel1882 9 років тому

    You are the best teacher nooooooooo doubt !!!!!!!!!!!!!!!

  • @himeparfaitdoll
    @himeparfaitdoll 12 років тому +1

    omigosh that last problem was fun! :D

  • @Crawr1
    @Crawr1 12 років тому

    Thank you so much! I missed this lesson and now i understand. Can you explain how to write a radical expression as a power with positive exponents please!

  • @patrickjmt
    @patrickjmt  16 років тому

    no problem!

  • @patrickjmt
    @patrickjmt  14 років тому

    @PenguinSplash no problem

  • @gunitsniper2700
    @gunitsniper2700 12 років тому

    i'm a senior in college and this saved my ****ing life.

  • @MerajKhandakar
    @MerajKhandakar 10 років тому

    how do you factor quadratic equations with negative exponents or fractional exponents? A video on that would be much appreciated.

  • @patrickjmt
    @patrickjmt  12 років тому

    i have a video on that somewhere

  • @twfoa2329
    @twfoa2329 7 років тому

    In Algebra 1( 9th grade). this helped some. Thanks for posting video.
    Was looking for: Evaluate integers raised to rational exponents.

  • @XDSakuraBlossomXD
    @XDSakuraBlossomXD 14 років тому

    Thank you soo much it really helped and i have a big math test today!

  • @xGUNxBUNNYx
    @xGUNxBUNNYx 14 років тому

    Man all I had to do was break down the expression, thanks for posting this vid.

  • @nfiahxd
    @nfiahxd 9 років тому

    Thank you so much, you are a better teacher than my own.

  • @ewaldjw
    @ewaldjw 15 років тому

    Amazing! Thanks so much!!! I registered for a class that's a little much for me and you're helping me catch up! Thanks!

  • @patrickjmt
    @patrickjmt  14 років тому

    @djjoelroche less stress is always good : ) feel free to visit during the school year... patrickjmt is always here, boring someone : )

  • @iboldvids
    @iboldvids 13 років тому

    This is the value of the internet in modern education.

  • @patrickjmt
    @patrickjmt  14 років тому

    @xGUNxBUNNYx happy to do so - a useful skill in math is taking a big problem and trying to turn it into many smaller problems!

  • @deco101
    @deco101 14 років тому

    wow really didnt realize how fast you forget things ... thanks for the reminder man

  • @patrickjmt
    @patrickjmt  16 років тому

    actually, i would use a taylor series representation to get the desired accuracy. that would work

  • @patrickjmt
    @patrickjmt  12 років тому

    glad i could help :)

  • @mikewhite3778
    @mikewhite3778 10 років тому

    The problem with (-9^3/4)^2 ,a later step, you did (9^3/4)^2/1. The last few steps of the last problem (5/6)^2 to get 5^2/6^2 why are they not the same? Why the last problem isn't (5/6)^2/1 to get 5^2/6^1?

  • @misspoplover
    @misspoplover 13 років тому

    you are are best maaan!!!!
    no one can do this better than u

  • @aquemeni541
    @aquemeni541 14 років тому

    Yes, it is. I can't stand XL. I always end up figuring it out on my own, or watching this guy who knows what he's doing.

  • @ilovemelikeyouall
    @ilovemelikeyouall 12 років тому

    thank you so much omfg I can't even, I missed school a lot bc I was sick and teacher didn't even try to explain me what I had missed so I didn't really understand any of these since they look kinda scary when you first look at them and I tried to understand them for myself but failed miserably, anyway, bless you, ur great!

  • @bravone1
    @bravone1 12 років тому

    thank you so much I finally understand. Your method works. God bless you.

  • @patrickjmt
    @patrickjmt  13 років тому

    @jeleemay97 glad i was able to help you : )

  • @crackphoo
    @crackphoo 13 років тому

    thank you so much for uploading this

  • @mmageek
    @mmageek 12 років тому

    Thanks for the review, it was very helpful.

  • @fmalove2
    @fmalove2 12 років тому

    QUESTION!: If you have a problem that says: x raised to 3/4 PLUS x raised to 5/8, how would you do such a problem?

  • @bryfryable
    @bryfryable 13 років тому

    i was always told that whenever you take a number in the numerator that is attached to a neg. exponent and put it in the denominator, you take away the negetive from the exponent and then flip the powered fraction. for instence 8 to the neg 1/3 squared should be 1 over 8 cubed, squared. i dont get it. i thought you also fliped the fraction when you take its attachment in the numerator and place it down in the denominator. a little help please!

  • @fafase
    @fafase 14 років тому

    @patrickJMT I would have said the same until I checked on my calculator and yes, Juan got over excited. Yet, I don't totally get it. Ex: -3^2=9 but -(3)^2=-9 isn't it?

  • @ObviouslyNik
    @ObviouslyNik 12 років тому +1

    8:09
    "Well, now we have addition"
    Me: Boo you addition! :P
    But thanks a LOT! Your video made so much sense! I was like a mathematical headless chicken running around before I saw your video. Helped me a lot!

  • @1OMJALEX
    @1OMJALEX 12 років тому

    You just made my SAT Math score go a little higher :D

  • @asalamkamal6365
    @asalamkamal6365 2 роки тому

    Thank you so much sir i've completed this series

  • @AZNPINOY345
    @AZNPINOY345 13 років тому

    I just want to say how much you saved my ass... Finals are inbound for me, I learned how to do fractional exponents now. (Shame on me for falling asleep in my 1st period Int. Alg classes)

  • @patrickjmt
    @patrickjmt  15 років тому

    unless you are in second grade, no one uses an 'x' for multiplication

  • @patrickjmt
    @patrickjmt  13 років тому

    @GLORYdubstep i also do not like it, but it was all i had at that time

  • @sarapoitra3320
    @sarapoitra3320 Рік тому

    Super helpful!!! Thank you

  • @TheMothproof
    @TheMothproof 12 років тому

    Your math help is usefull. I still feel like knoosing myself tho after looking at my page after an hour.

  • @AlaskaKace
    @AlaskaKace 13 років тому

    Thank you! That was incredibly helpful!! =)

  • @BubblesTroubles
    @BubblesTroubles 16 років тому

    I need to calculate e raised to various powers of pi, where e = 2.718... and pi = 3.141...
    for example, e^pi, e^pi^2, e^pi^3 ...
    How can I do this? I have tried by writing a Java program, but there is no power function in Java for fractional exponents.

  • @kcrut2003
    @kcrut2003 9 років тому

    patrick, this is by far the best explanation on youtube. other methods arent nearly as clear or simple. thank you. it was my pleasure to watch you do this!

  • @the9461roger
    @the9461roger 13 років тому

    thanks bro this was very helpful

  • @wolfy365
    @wolfy365 14 років тому

    damn, nice straight line

  • @spartanshadow13
    @spartanshadow13 12 років тому

    Nice tutorial. Is it possible you could evaluate (-1)^(2/3). According to the method you shown, the answer should be 1.(Hint) 1 is not the answer!.

  • @sh4d0w4rri0r
    @sh4d0w4rri0r 14 років тому

    do u have a tut. that show fractional exponents power to fractional exponent?
    ex. (2^2/3)2/3 or sumthing like that? or is that even possible?

  • @WuTangThang
    @WuTangThang 14 років тому

    I dominated at this in middle school, I'm now 22 and can't remember ANYTHING. Thanks for the vid man.

  • @AnimedToday
    @AnimedToday 12 років тому

    What if the number is replaced by an 'x'? How would you find the answer for 'x'?

  • @bedfordv
    @bedfordv 12 років тому

    Awesome video!! Thanks!

  • @thebingbongyang
    @thebingbongyang 12 років тому

    you just saved my midterm grade

  • @TheWhisperInside
    @TheWhisperInside 10 років тому

    Super helpful. Thank you.

  • @Kujacku
    @Kujacku 8 років тому

    Your an absolute legend no detention for mes

  • @KingCupcakesfly
    @KingCupcakesfly 12 років тому

    Your drawings are awesome

  • @patrickjmt
    @patrickjmt  13 років тому

    @misspoplover thanks : )

  • @kellsterxoxo
    @kellsterxoxo 15 років тому

    ohmygod. thank you so much! yer my lifesaver!!

  • @mojo232
    @mojo232 15 років тому

    mann you are smart can u give m ejust some general advise to help me with my math because i suck and i need to get better

  • @tamarau4255
    @tamarau4255 10 років тому

    You never fail to please me :)

  • @patrickjmt
    @patrickjmt  12 років тому

    i ran out of paper when i made this ( the non-lined type at least!)

  • @johnfalcon3614
    @johnfalcon3614 11 років тому

    Wait, on this problem 27^5/6*27^-1/3 why did you discard the other 27? Ins't it also part of the problem?

    • @OldHunter_blaidd
      @OldHunter_blaidd 5 років тому

      X^A*X^B = X^A+B
      27^5/6*27^-1/6 = 27^5/6+(-1/6)
      27^(5/6-1/6) = 27^4/6 = 27^2/3 = 9

  • @cloudconnects
    @cloudconnects 15 років тому

    Thank you, very good job

  • @NolPatrol
    @NolPatrol 13 років тому

    Lol, u should be my teacher....soo much better than my algebra teacher...

  • @vaansolidor
    @vaansolidor 14 років тому

    you are my hero

  • @fitzgerald3485
    @fitzgerald3485 9 років тому

    thanks it helps me alot :)

  • @seperoth2769
    @seperoth2769 10 років тому

    Thank You!

  • @yunahwang4956
    @yunahwang4956 8 років тому

    Thank you🙇

  • @mantecarljuleozer7143
    @mantecarljuleozer7143 5 років тому

    What if unknown number raised to 3/4 = 8? How to solve this

  • @MonitorWorks
    @MonitorWorks 12 років тому

    THANK YOU

  • @spuddapotato2494
    @spuddapotato2494 13 років тому

    dude thanks!

  • @Ace4Dice
    @Ace4Dice 12 років тому

    thanks for making this video XD
    now i actually understand fractional indices..lolz