I watched the whole video, and it is not an 8th grade question. Most kids are doing either pre-algebra, or maybe algebra 1. This is quite a bit harder. An 8th grader could probably brute force the answers by trial and error, but that isn't the point of the question. The point is an elegant solution without guess work.
@@Skibbityboo0580 Oh yeah, that could be it. Maybe the point was to see how the participants would solve a relatively simple question with elegance, efficiency, and complete understanding? Personally after finding the quadratic expression, I'd have immediately thrown it into the calculator using the quadratic formula. That's probably not what the judges are looking for...
if u look at the video like it’s the way to solve it it’s very funny, but as a way to practice your algebra its makes sense , OC u won’t solve that way regular but practicing those type of techniques might help u identify things that CAL can’t help u with in a bit more complex situations.
lol what, how is this an olympiad question, this doesn't make any sense. It's like a basic algebra question. I think we did these in like 7th or 8th grade. I recommend blocking this channel.
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If that's an Olympiad question then I am Albert Einstein
it's meant for you. This is a high school Olympiad problem. This is in the lowest weight class for competitive math.
@@lan_9056 highschool? This is at max 9th grade level question.
@@Tajjwar That's a whole a$$ 1st grade
@@lan_9056This material is taught before high school
couldnt find any real info about the equation in japanese. Title is most likely baseless and even if its real, its definitely not meant for you
isn't that 8th grade question?
Exactly what I was wondering. Maybe the problem is graded by how fast it's solved?
I watched the whole video, and it is not an 8th grade question. Most kids are doing either pre-algebra, or maybe algebra 1. This is quite a bit harder.
An 8th grader could probably brute force the answers by trial and error, but that isn't the point of the question. The point is an elegant solution without guess work.
@@Skibbityboo0580 Oh yeah, that could be it. Maybe the point was to see how the participants would solve a relatively simple question with elegance, efficiency, and complete understanding?
Personally after finding the quadratic expression, I'd have immediately thrown it into the calculator using the quadratic formula. That's probably not what the judges are looking for...
It's more 7th grade, when you learn quadratic equations
That's not even complex (pun intended)
y=20-x => x(20-x)=44 => x²-20x+44=0
=> x1/2 = 10 +/- SQRT(56) => y1/2 = 10-/+SQRT(56)
if u look at the video like it’s the way to solve it it’s very funny, but as a way to practice your algebra its makes sense , OC u won’t solve that way regular but practicing those type of techniques might help u identify things that CAL can’t help u with in a bit more complex situations.
If we recognize that this system is Vieta formulas for quadratic
we can immediately write quadratic equation t^2 - 20t + 44 = 0
t^2 - 20t + 44 = 0
(t^2 - 20t + 100) - 56 = 0
(t - 10)^2 - (2sqrt(14))^2 = 0
(t - 10 - 2sqrt(14))(t - 10 + 2sqrt(14)) = 0
(10)+(10)=20 (5^5)+(5^5) (2^3^2^3)+(2^3^2^3) (1^1^1^1)+(2^1^1^3) (23) (y ➖ 3x+2). xy =44 2^2^2^2 1^2^1^2 1 2(xy ➖ 2xy+1).
Sir, Iam really appreciate you. 🇧🇩
Very nice writing! I enjoyed this, i hadnt solved a quadratic equation in years
a line and a hyperbole will always intersect unless the line is 1 of the assymptotes.
Yeah, so... x²-Sx+P. Goodbye.
x*y =(10+z)(10-z) = 100-z^2=44 -->z=Sqrt(56) --> x/y = 10+/- Sqrt(56)
Me encanta que aunque no habla mi mismo idioma lo entiendo a la perfección, eres increíble enseñando
Bro, thats a school program)
I really like algebra questions.
The way he wrote his "x" drove me nuts.
why bro it looks hella cool
x + y = 20
xy = 44
-> x = 20 - y
-> x = 44/y
-> 20 - y = 44/y
-> 20y - y² = 44
-> 20y - y² - 44 = 0
-> y² - 20y + 44 = 0
-> y = {-(-20) ± √[(-20)²-4(1)(44)]}/2
-> y = {20 ± √[400-176]}/2
-> y = {20 ± √224}/2
-> y = {20 ± √(16×14)}/2
-> y = {20 ± 4√14}/2
-> y = 10 ± 2√14
If y = 10 + 2√14,
x = 20 - y = 20 - (10 + 2√14)
x = 10 - 2√14
If y = 10 - 2√14,
x = 20 - y = 20 - (10 - 2√14)
x = 10 + 2√14.
A manicure would make this series so much easier to watch.
I think you doesn't appreciate Maths.
@@SidneiMVi dont think you appreciate english
too easy
Elementary math.... Waste of time.
lol what, how is this an olympiad question, this doesn't make any sense. It's like a basic algebra question. I think we did these in like 7th or 8th grade. I recommend blocking this channel.
Based