THE MOST BEAUTIFUL RESULT IN ALL OF CALCULUS!!!

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  • Опубліковано 20 жов 2024
  • THIS IS IT!!!
    THIS WHAT MATH IS ALL ABOUT!!!
    SUIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII
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КОМЕНТАРІ • 53

  • @maths_505
    @maths_505  Рік тому +1

    If you like the videos and would like to support the channel:
    www.patreon.com/Maths505
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  • @Fiinix_
    @Fiinix_ Рік тому +35

    In physics, conventional superconductors described by BCS theory also show this exact beautiful fraction of (pi/e^gamma). The ratio between their gap function and critical temperature for the transition gives you this number.

    • @lennyface2586
      @lennyface2586 6 місяців тому +3

      Better Call Saul theory

    • @yashmehta9299
      @yashmehta9299 5 днів тому

      It is an ‘approximate’ formula (which I find even more intriguing) at zero temperature. Also interesting is that the ratio near critical temperature becomes of the order pi/sqrt(zeta(3)), which if you for once forget the derivation for, feels almost supernatural!

  • @OpsAeterna
    @OpsAeterna Рік тому +28

    this channel is so chill and good. love your work boss

  • @gonzus1966
    @gonzus1966 Рік тому +33

    This is indeed extremely beautiful!

    • @Arneauxtje
      @Arneauxtje Рік тому

      It would be, if I could read it. The handwriting sucks.

  • @fartoxedm5638
    @fartoxedm5638 Рік тому +11

    As a generating function enjoyer I SIMPLY CANNOT HELP BUT NOTICE that this looks like a derivative of zeta gf boi at 1/2
    LOVELY RESULT

  • @MrWael1970
    @MrWael1970 Рік тому +1

    Awesome Proof. Thank you for your innovative video.

  • @insouciantFox
    @insouciantFox Рік тому +25

    Very beautiful.
    The integral of fractional part of tanx from 0 to π/2 has gotta be my fave though.

    • @maths_505
      @maths_505  Рік тому +11

      I remember integrating {tanx}/tanx but just the {tanx} sounds like a good idea.
      Noted. Thanks mate.

    • @applealvin9167
      @applealvin9167 Рік тому +3

      I remember the result looks quite terrifying, right?

  • @michaelihill3745
    @michaelihill3745 5 місяців тому

    That was absolutely awesome!

  • @starhacker6411
    @starhacker6411 Рік тому +1

    It is beautiful to see e gamma 2 and tau in one place

  • @DavidFMayerPhD
    @DavidFMayerPhD Рік тому +19

    Slight error. One may switch the order of summation of two infinite series if each series is ABSOLUTELY convergent. Mere convergence is insufficient.
    Also capital "S" looks almost exactly like Zeta.

  • @coda6702
    @coda6702 Рік тому +2

    Bro it is indeed a pure gold. Where did you find this?

  • @endersteph
    @endersteph Рік тому +2

    F*CKING BEAUTIFUL

  • @xBiggs
    @xBiggs Рік тому +4

    Been a while for me, but can't you rewrite exp ^ series to be an infinite product?

    • @maths_505
      @maths_505  Рік тому +3

      Yes ofcourse and that would be pretty cool too

  • @monsterhunter8595
    @monsterhunter8595 Рік тому +1

    Very nice

  • @eduardoeller183
    @eduardoeller183 Рік тому

    Very satisfying indeed!

  • @digxx
    @digxx Рік тому

    Convergent is not enough to interchange the order of summation. You need absolute convergence.

  • @Titurel
    @Titurel Рік тому

    Lovely!

  • @Chris_387
    @Chris_387 Рік тому

    Nice video, in which app are you writing?

  • @user-io8sd7mp6x
    @user-io8sd7mp6x Рік тому +1

    What software is this with the black screen and the icons at the bottom?

  • @ruffifuffler8711
    @ruffifuffler8711 6 місяців тому

    A transcendental node and dimensional orientation relative aspect sign?

    • @ruffifuffler8711
      @ruffifuffler8711 6 місяців тому

      Better yet;
      A transcendental node with a dimensional orientation and relative aspect ordinal space formation suitable for blueprinting serial numerical architecture.

    • @ruffifuffler8711
      @ruffifuffler8711 6 місяців тому

      Even Better; Standing wave of the product of the zeta primes?
      Just a guess by exclusion of the remaining rational possibilities, and, an excape from humiliating exaction on the re-ordered spindle of confined charme.

  • @parthhooda3713
    @parthhooda3713 9 днів тому

    8:08 can someone tell me the difference between zeta and s

    • @yashmehta9299
      @yashmehta9299 5 днів тому

      Zeta is the sum of reciprocal powers, for example zeta(3)= 1 + 1/8 + 1/27 + 1/64 + …
      S includes the sum of all integer zeta functions, zeta(2)+zeta(3)+zeta(4)+… (of course, each term divided by n 2^n)
      So S is essentially a double summation, and zeta is a single summation.

  • @o0QuAdSh0t0o
    @o0QuAdSh0t0o Рік тому +2

    Bernoulli boyz

  • @lyricalch1
    @lyricalch1 Рік тому +3

    It would be easier to see the beauty if there were some more motivation for the lengthy derivation, and some explanation for what insights it gives. Even in its final form it looks very complicated on the left-hand side. The fact that an exponential of an infinite series on the left equals the inverse of an exponential (i.e., another infinite series) on the right hardly seems remarkable without more context.

  • @newwaveinfantry8362
    @newwaveinfantry8362 10 місяців тому

    7:40 - You forgot the (-1)^n in the sum.

  • @nikko2505
    @nikko2505 Рік тому

    Cool

  • @Maths_3.1415
    @Maths_3.1415 Рік тому +2

    Noice :)

  • @hassanhassane3663
    @hassanhassane3663 Рік тому +1

    Amazing result thank you Sir❤❤❤

  • @robertsandy3794
    @robertsandy3794 Рік тому

    A+++++++++++

  • @__hannibaal__
    @__hannibaal__ Рік тому

    Yeah, there too much, explore mathematic constant, and some book of encyclopedias of Series and Integral like … there to many, what i surprise why there are no beautiful mathematical and physical book like old time. Bull…shit internet media.

  • @morchel332
    @morchel332 Рік тому

    schwifty

  • @karma_kun9833
    @karma_kun9833 Рік тому

    Let x=1

    • @maths_505
      @maths_505  Рік тому +1

      On the way to deriving the result, I specifically mentioned that abs(x)

    • @karma_kun9833
      @karma_kun9833 Рік тому +1

      ​@@maths_505yeah I forgot then I will try 1/2 this must work?

    • @maths_505
      @maths_505  Рік тому +1

      @@karma_kun9833 yes 1/2 will work perfectly

    • @ΙΗΣΟΥΣΧριστος-θ2γ
      @ΙΗΣΟΥΣΧριστος-θ2γ Рік тому

      ​@@maths_505i have a question here is it possible to analytically continue the function beyond (-1,1) using your result here with the log of the gamma function which is of course well defined on the complex numbers?

    • @maths_505
      @maths_505  Рік тому +1

      @@ΙΗΣΟΥΣΧριστος-θ2γ in deriving the result I used the geometric series so one would have to start from scratch using a different approach.

  • @semurgx
    @semurgx Рік тому +4

    “Most” word must be prohibited in youtube titles