16:30 I'm not sure that's correct regarding the second derivative test. When D > 0 and g_xx < 0, we have a local maximum so g_xx < 0 doesn't immediately disqualify the utility of the test. The second derivative test is inconclusive when D = 0, perhaps that was the intention. In this case, D(-5/3, 0) > 0 and thus the point (-5/3, 0) is a local maximum. Hope this clears up some uncertainty.
all both the calc 3 teachers i have had had doctorates in math and expected us to remember everything in calc 1 and 2, along with algebra, so they never really taught stuff to us very well in a way that was understandable to undergrad students so i just ended up confused. this is an exception.
5:13 its supposed to be -2 because you are multiplying -1i and 2k Edit: Because it’s the J component you have a negative infront of the -2 making it positive 2.
The j component of the resultant vector from doing a cross-multiplication is negative by default. So, by multiplying -1 and 2 you get -2, yes, but since it's the j component you multiply it by -1 again, making it +2.
I just got back from my calc 3 final like 1 hour ago.
What did you get?
16:30 I'm not sure that's correct regarding the second derivative test. When D > 0 and g_xx < 0, we have a local maximum so g_xx < 0 doesn't immediately disqualify the utility of the test. The second derivative test is inconclusive when D = 0, perhaps that was the intention. In this case, D(-5/3, 0) > 0 and thus the point (-5/3, 0) is a local maximum. Hope this clears up some uncertainty.
That's where I feel confused
all both the calc 3 teachers i have had had doctorates in math and expected us to remember everything in calc 1 and 2, along with algebra, so they never really taught stuff to us very well in a way that was understandable to undergrad students so i just ended up confused. this is an exception.
Thank you for reviewing Calculus Three. The Double and Triple Integrals in Calculus Three are problematic from start to finish.
5:13 its supposed to be -2 because you are multiplying -1i and 2k
Edit: Because it’s the J component you have a negative infront of the -2 making it positive 2.
The j component of the resultant vector from doing a cross-multiplication is negative by default. So, by multiplying -1 and 2 you get -2, yes, but since it's the j component you multiply it by -1 again, making it +2.
@@rileyschrader8285make sense I realised I forgot to include the other negative that comes with the J component
Me watching this before taking Calc 3 in 2 weeks so I know what to be scared for
no reason to be scared, calc 3 is easy
At least you survived calc 2
Which grade is this for?
College Level