Wait, I'm confused. When you did 'r', you said false false means false. (@4:54) But then when you did 'p implies r', you said false false means true (@5:25)... why is that?
@@deeparawat7424 minute 5:02 the compound proposition called r that implies 7q ^ 7p. Both values are False so why is the compound proposition r=F . it should be r=T , shouldn't it? If we go to the earlier lessons all the truth table when both values are equal to false then the compound proposition is true. I was this doubt 👆🏻 but with your explication i could see the logic.. however so difficult it is so abstract to see but there is an interesting logic behind that abstraction
1:18 It's not a well formed formula ( wff) because there is ambiguity because of no bracket. Logically this expression will be rejected for any further analysis in PL (propositional logic) .
minute 5:02 the compound proposition called r that implies 7q ^ 7p. Both values are False so why is the compound proposition r=F . it should be r=T , shouldn't it? If we go to the earlier lessons all the truth table when both values are equal to false then the compound proposition is true. it's to confused this part for me. 🙏🏻 I hope someone can help to me with this little doubt !
This is just a convention right? I mean, it is a very usefull and very stable convention, but I think it is still important to say that this a “just” a convention
Actually biconditional operator is just like XNOR gate instead of XOR gate.The output is true except only one of the inputs is false,so the precedence of these two cannot be the same.
minute 5:02 the compound proposition called r that implies 7q ^ 7p. Both values are False so why is the compound proposition r=F . it should be r=T , shouldn't it? If we go to the earlier lessons all the truth table when both values are equal to false then the compound proposition is true. it's to confused this part for me. 🙏🏻 I hope someone can help to me with this little doubt !
Excellent video. Makes things look relatively easy. Thank you!
Short and very easy to understand . Thanks!
This was a perfect explanation. Thank you for making my day easier.
Very helpful thanks !
Is this magic
Thank yoh for your efforts sir....
But kindly recheck P ---->r values in truth table....
thank you you ve been very clear about it
Wait, I'm confused. When you did 'r', you said false false means false. (@4:54)
But then when you did 'p implies r', you said false false means true (@5:25)... why is that?
Because in false false means false case there was conjunction and in false false true case there was implication
@@deeparawat7424 BUT Bioconditional is only True when Both p and q has the same truth values
@@deeparawat7424 minute 5:02 the compound proposition called r that implies 7q ^ 7p. Both values are False so why is the compound proposition r=F . it should be r=T , shouldn't it? If we go to the earlier lessons all the truth table when both values are equal to false then the compound proposition is true.
I was this doubt 👆🏻 but with your explication i could see the logic.. however so difficult it is so abstract to see but there is an interesting logic behind that abstraction
there is a mistake in this calculation, i believe, final answer will be all false
1:18 It's not a well formed formula ( wff) because there is ambiguity because of no bracket.
Logically this expression will be rejected for any further analysis in PL (propositional logic) .
Smoothly explained, thank you!
minute 5:02 the compound proposition called r that implies 7q ^ 7p. Both values are False so why is the compound proposition r=F . it should be r=T , shouldn't it? If we go to the earlier lessons all the truth table when both values are equal to false then the compound proposition is true.
it's to confused this part for me. 🙏🏻 I hope someone can help to me with this little doubt !
This is just a convention right?
I mean, it is a very usefull and very stable convention, but I think it is still important to say that this a “just” a convention
Well, I wouldn't trust a programming language where this convention is not complied.
Thank you🙏
I love Neso Academy ❤️
Negation
conjunction
disjunction
implication
biconditional
What is the precedence of XOR?
thank you sir, you help me a lot
Thanks
Thanks ☺️
OMG! Thanks for this video tho..
Thank you so much sir
How about XOR (Exclusive OR) related to this topic?Is its precedence only higher than biconditional operator?
Actually biconditional operator is just like XNOR gate instead of XOR gate.The output is true except only one of the inputs is false,so the precedence of these two cannot be the same.
Get rid of "only" ,the correct one should be "The output is true except one of the inputs is false"
xor is a complex operator. It is made up of negation, conjunction, and disjunction
bro it ^ implies conjuction operation not xor
5:33 p->r it should be true
no its correct always remember true implies false is false ...visit that timing again
thank you
I have question to convery to CNF, the compound state is (a and b or c) and (b or ~c)..... can this be done without precedence for the first bracket?
I don't think so, since AND takes precedense to OR. Without the bracket the calculation will be executed like this
(a and b) or (c and (b or ~c))
minute 5:02 the compound proposition called r that implies 7q ^ 7p. Both values are False so why is the compound proposition r=F . it should be r=T , shouldn't it? If we go to the earlier lessons all the truth table when both values are equal to false then the compound proposition is true.
it's to confused this part for me. 🙏🏻 I hope someone can help to me with this little doubt !
^ operator is used in 7q and 7p... in ^ operation the next value is T when both p and q are T otherwise it will always F...
For more details I suggest you that you may visit some last videos
In biconditional This is True when both p and q are same
Thank you! But I have to ask what is the precedence for exclusive or?
Disjunction bro
sir what about precedence of X-or operator?
xor is a complex operator. It is made up of negation, conjunction, and disjunction
why is your "not" like that?
isn't there a mistake at 5:55
for biconditional, the double head arrow, if p and q are both true or both false, then the result will be true. Otherwise, the result will be false.
Yes. This will be True not False
@@mijbulbaharjibon8262 No it is false.
I think you are mistakenly seen the table for not p instead of not q. I was doing that mistake.
@@mijbulbaharjibon8262No.... it is correct there is no mistake
thanks