EMF Equation of Transformer
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- Опубліковано 14 вер 2019
- When a sinusoidal voltage is applied to the primary winding of a transformer, alternating flux ϕm sets up in the iron core of the transformer. This sinusoidal flux links with both primary and secondary winding. The function of flux is a sine function.
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Excellent
Tnx for easy explained 🥰
Thank you
Excellent for understanding
Good explanation brother
Please video create on 4th semester AC1 in diploma subjects and also
EED (electrical engineering drawing)
For all problems
Nice ❤
Thank you sir 🤝
Welcome 👍
Good sir
Rate of change should be wrt time not wrt frequency.
Take X-axis as Time axis not as frequency.
Good
Tq sir l
Sir how will come the values of 1.11
Great
The explanation is completely wrong.
Avarage rate of change of flux linkage is the ratio of change in value of flux from t1=0 sec to t2=T/4 sec ( as he had taken one-fourth of complete cycle) and now change in value of flux for this time period is ∆m (I'm representing flux symbol with delta),
Rate of change of flux linkage= ∆m/(T/4)= 4∆m/T Weber's per sec .
Or
= 4f∆m Weber's per sec.
(Since 1/T=f). In this video he had given units as cycles per sec or volts which is wrong.
Now according to Faradays laws of Electro Magnetic Induction EMF, e=N d∆/dt
e= N 4f∆m volts
Average EMF per turn = 4f∆m volts (Since per turn means N=1)
RMS value = form factor × Average value
E = 1.11 × 4f∆m volts per turn
Or
E=4.44 f∆m volts per turn
Now EMF induced in primary winding of Transformer is
E1= emf per turn × no. Of turns in primary winding.
E1= 4.44f∆m N1 volts.
Similarly
E2=4.44f∆m N2 volts.
Super Anna
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