Statistics Questions | CSIR NET Sept 2022 | COMPLETE SOLUTION| Short Cut Tricks

[@statatease7661]

In question no 336 p(x=0) = 1/( 1+ c + c^2), P( x= 1) = c/ ( 1+c + c^2) and P(x = 2) = c^2/ ( 1+ c+ c^2) sir.

[@akhila887]

Wonderful Explanation

[@Shakti1706]

Sir please make more videos on statistics pyq for CSIR NET

[@arvindjoiya9767]

Sir in q 336 sum of prob is greater than one 1+c+c^2 >1

[@bhawanasingh174]

Hello sir, good afternoon
Sir do you teach CSIR NET students??
Aap kisi online platform pe padhate hain?

[@bhawanasingh174]

Sir jha se hum poora course kr ske aapka??!

[@informationnet]

Very useful

[@statatease7661]

In question no. 338 how we can approximate it to a normal distribution sir. If p=1/2 the distribution is only symmetric. And the correct ans is second option, think.

[@PoonamYadav-eq4fb]

Sir there is a mistake in question 338 , it should be greater than half

[@MuSiCLoVeR-yw9pr]

Yes you are right. Here E(z) is negative . So subtracting that value from 0 gives a positive value for Z . So answer will be greater than half.

[@priyaverma1496]

Sir hyothesis based question bhi kraye 16 sept ke pls

[@anowarali668]

Thanks sir, it helps

[@stubbornatom4833]

Thank you sir

[@gopikagsgopikags9936]

Sir, please solve 2021-22 year quesrions

[@sagnikacharyya3137]

sir where can i get the full question paper?

[@helldestroyer]

Sir please tell me about your telegram/whatsapp channel 🙏
& Also please uploaded questions on Isi M.stat and Gate and iit jam last 2/3 year according your preference and choice

[@ShivamKumar-nf2eo]

Sir csir 30 nov 2020 ka stastivs solution daal do

[@DrHarishGarg]

OK. I will do soon

[@gauravalambaine2102]

Sir please solve 446 question

[@shrawankumarpatel2148]

🙏🙏🙏🙏🙏

[@Maths-Stats-By-BB-Sir]

Sir please upload statistics group c 4.75 marks question solution
Please please sir

[@rinkybisht1395]

Plz help me

[@ShivamKumar-nf2eo]

Sir

[@Maths-Stats-By-BB-Sir]

Sir can you please upload statistics solution of June 2021
Please sir

[@DrHarishGarg]

Do you have question paper ?

[@Maths-Stats-By-BB-Sir]

In your last question how could be the expectation of x, x^2, x^3 …. All are same and become equals to p???? How does E(x^3)become p??

[@statatease7661]

In Bernoulli distribution, X^2, X^3, .... are also Bernoulli. Therfore E(X^2) = E( X^3) =... = mean of Bernoulli

[@helldestroyer]

​@@statatease7661thanks yaar