the derivative is a LIE

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  • Опубліковано 28 січ 2025

КОМЕНТАРІ • 80

  • @SuperDreamliner787
    @SuperDreamliner787 Рік тому +34

    This reminds me of my quantum mechanics classes a couple of years ago. Now I am teaching how to add fractions. 😂

    • @MH-sf6jz
      @MH-sf6jz 9 місяців тому

      Abstract algebra is a tough course to teach

  • @ddognine
    @ddognine Рік тому +26

    21:10 Minor correction: should be partial wrt y, not x, which allows it to double up as 2e.

  • @chester_m
    @chester_m Рік тому +45

    Michael I extended the playlists on my channel of videos on your channel a bit. In particular there is a playlist with over 90 of your videos that are mentioned in the OEIS. If you like they can be on your channel. I can also send you the list I use to make the playlists. Free of charge, just as a thank you for your work.

  • @theartisticactuary
    @theartisticactuary Рік тому +6

    Never has the line separating pure maths from quantum mechanics looked thinner.

  • @giannisniper96
    @giannisniper96 Рік тому +29

    super excited about a video on the representations of sl_2(C) 😄

  • @martin13423
    @martin13423 Рік тому +5

    I really enjoy these more exploratory and higher level videos, they're really interesting !

  • @jordanraddick505
    @jordanraddick505 Рік тому +7

    Damn you, Penn, your clickbait worked on me! *shakes fist*
    Edit: Damn you, Stephanie!

    • @MichaelPennMath
      @MichaelPennMath  Рік тому +10

      Under no circumstances am I missing this opportunity.
      -Stephanie
      MP Editor

  • @sinecurve9999
    @sinecurve9999 Рік тому +17

    Top tier mathematical themed dad joke.

    • @enisten
      @enisten Рік тому +2

      Click-bait in disguise of a pun (though, I stayed because of the content)

  • @schweinmachtbree1013
    @schweinmachtbree1013 Рік тому +5

    the Penn fact at 7:00 could have done with a comma - it might be confused as "componentwise [addition and multiplication] ..." but what is meant is "[componentwise addition], and multiplication ...". (also it uses an epsilon ε instead of a membership symbol ϵ)

    • @MikeGranby
      @MikeGranby Рік тому

      It could also have some with a graphic that looked vaguely like Penn..

  • @paulkohl9267
    @paulkohl9267 Рік тому +2

    Hey MP, loving the video editing improvements. Excellent. 🙂

  • @georrgy
    @georrgy 2 місяці тому

    These series are perfect! You are the first who gave me some naive idea what Lie algebras are, so now I am mentally ready for the appropriate course. Thank You very much 👍

  • @dodgsonlluis
    @dodgsonlluis Рік тому +4

    I got stuck when the calculation leads to z^(m+n-3) and not z^(m+n-1) as needed for L(m+n). If we set in the definition of L(n) z^(n+1) instead of z^(n-1) then works fine.

    • @krisbrandenberger544
      @krisbrandenberger544 Рік тому

      Actually, shouldn't the commutator of L(m) with L(n) be equal to (m-n)*L(m+n-2)?

    • @dodgsonlluis
      @dodgsonlluis Рік тому +1

      @@krisbrandenberger544 Sorry, the definition corrected leads to z^(m+n+1), as needed for L(m+n).

    • @dodgsonlluis
      @dodgsonlluis Рік тому

      @@krisbrandenberger544 Check his video on the topic. ua-cam.com/video/1MKTsHFE9aA/v-deo.html

    • @krisbrandenberger544
      @krisbrandenberger544 Рік тому

      @@dodgsonlluis Perfect! Thanks!

  • @lexinwonderland5741
    @lexinwonderland5741 Рік тому +19

    This is always my favorite video content! Thanks, professor! Can't wait for more about Lie algebras and VOAs -- i'm always thrilled to hear about your research, but even educational videos about things like representation theory make my entire day!!

  • @MrFtriana
    @MrFtriana Рік тому +9

    Ah yes, conmutators and derivatives, one topic frequently found in physics in quantum mechanics. It's a awesome topic that mix algebra and calculus.

  • @JohannPetrak
    @JohannPetrak Рік тому +2

    Best clickbaity title in the history of UA-cam.

  • @VOLKOV9
    @VOLKOV9 Рік тому +1

    came here to applaud your change away from the clickbait title. a lot fo math/science youtuber are heading the other way. I get why they do that, but I want to celebrate you going this way.

  • @dmytrolevin738
    @dmytrolevin738 Рік тому

    5:40 But if [y, z] = yz, then D(y) = [x, y] = xy, and D([y, x]) = D(y)z + yD(z) = xyz + yxz = 2xyz (if the "multiplication" is a usual multiplication, commutative and associative). What is meant exactly by D and that "multiplication" here?

  • @Wielorybkek
    @Wielorybkek Рік тому +4

    video about representations of sl2 or we riot

  • @00-102
    @00-102 Рік тому

    In the example 2,why there is an alpha(0), it's in span{}; and how can we get m in apan{}?

  • @reinerwilhelms-tricarico344
    @reinerwilhelms-tricarico344 8 місяців тому

    In your Heisenberg Lie algebra starting at 11:05 I can't see how this jives with the more commonly known Heisenberg-algebra or group. I don't recognize any of it.

  • @tubepkn
    @tubepkn Рік тому +8

    I like how he spells Leibnitz's name: LIEbnitz

    • @bjornfeuerbacher5514
      @bjornfeuerbacher5514 Рік тому +6

      Actually, the _real_ spelling is Leibniz. He even made _two_ typos. :/

  • @Etothe2iPi
    @Etothe2iPi Рік тому +6

    Liebnitz instead of Leibniz, ROTFLMAO. At least, there's no magic in this video, when something miraculously changes on the blackboard.

    • @MichaelPennMath
      @MichaelPennMath  Рік тому

      There's magic in every video. Math is magical. :)
      -Stephanie
      MP Editor

  • @mtaur4113
    @mtaur4113 10 місяців тому

    Title is straight out of the 19th century math flame wars.

  • @ultrametric9317
    @ultrametric9317 8 місяців тому

    I think I will go through your entire course - do you get to the part where translation groups come in? I never had a course in Lie theory and my memory is foggy.

  • @mokouf3
    @mokouf3 Рік тому

    When you see "lie" in mathematics...

  • @CamEron-nj5qy
    @CamEron-nj5qy Рік тому

    That is one strange way to write "g"

  • @pizzamidhead2183
    @pizzamidhead2183 Рік тому +3

    22:12 good place to stop

  • @APaleDot
    @APaleDot Рік тому

    I've always wondered why the cross product reminded me so much of the product rule. It all comes back to that damned Jacobi Identity!
    I would love a video on some sort of intuition about the Jacobi Identity. It seems to show up a lot when discussing rotations, but what the hell does it have to do with rotations? And what the hell do rotations have to do with the product rule?

    • @MrFtriana
      @MrFtriana Рік тому

      Maybe it is because if you work with finite rotations you don't get the same result when you change the order of the rotations. At least i think that this is a plausible explanation.

    • @APaleDot
      @APaleDot Рік тому

      @@MrFtriana
      Not sure what you mean by this.

    • @joshuagrumski7459
      @joshuagrumski7459 Рік тому

      Well, I don’t know toooooo much, but Lie Groups are groups that are manifolds as well, and Lie Algebras, from what I know, are the tangent spaces of the Lie groups. SO3, the group of rotations, has a corresponding Lie algebra, so3 (lowercase), and so3’s standard basis vectors obeys a Lie bracket relation using the standard commutator. So, from my understanding, the reason why there is such a big connection is because Lie algebras tend to be tangent spaces to a Lie group, which means that the algebras tend to be highly related to derivatives in some sense. As for cross products, I believe that (R3,x) is isomorphic to so3, and so the two are highly related in that sense? But idk for sure, others may add/correct me

  • @cmilkau
    @cmilkau Рік тому

    When I first learned about the derivative, I always felt unhappy about it. I wanted something that I would now call tangential space (on the graph of a function). I guess it made sense at the time of Newton and Leibniz, but with the advent of special relativity, I again get the feeling a tangential space is the better abstraction.

  • @davidgo3759
    @davidgo3759 Рік тому

    Hello Michael. I really love all your videos. In this one there is something that I don’t get. Is D: J->J / D(v)=[x,v], for any alternating bilinear map [ , ] satisfying the Jacobi identity, a well defined map? What is up with the other vector ‘x’? Besides, I think you cannot go beyond the expression D([y,z])=[D(y),z]+[y,D(z)] since when you take later [a,b]=a·b, firstly [ , ] is not anticommutative, so [ , ] is no longer alternating, and secondly, by the previous definition of D, now becomes D(y)=x·y(x) automatically (we have to assume at that point that J is the vector space of real functions and ‘y’ is a function of the real variable ‘x’) and there is not a derivative operator anywhere that allows you to get to the expresion D(y·z)=D(y)·z+y·D(z).... can you explain me where I’m wrong? Thank you.

  • @AnCoSt1
    @AnCoSt1 Рік тому

    the way you misspelled "liebnitz" could be construed as a clever pun... 6:10

  • @jossarian
    @jossarian Рік тому

    A general Lie Algebra may be represented(!) by the set of nxn matrices over a field, here gl(n).
    Further, certain restrictions like trace zero, upper triangel, skew symmetric and many more .... , these subclasses of nxn matrices represent also Lie Algebras.
    Next, these Lie-Algebras may act as endomorphisms of some n-tuple vectorspaces.

  • @nathansmith2168
    @nathansmith2168 Рік тому

    Wait but with the example of the derivative operator and [a,b]=ab, this bilinear map isn't alternating, right? So it isn't really a lie algebra

  • @AJ-et3vf
    @AJ-et3vf Рік тому +1

    Awesome video. Thank you

  • @JCCyC
    @JCCyC Рік тому +4

    Shamelessly clickbaity title but I just can't get mad about it. 🤣

  • @edwardlulofs444
    @edwardlulofs444 Рік тому +1

    Good one, thanks.

  • @paulkohl9267
    @paulkohl9267 Рік тому

    I hope you get to q-deformable Lie algebra's one day. Did an undergrad math paper on the topic. I would really like to grock the topic better. Then one day Homotopy Type Theory (HOTT) too!

  • @kilianklaiber6367
    @kilianklaiber6367 Рік тому

    Just one question for the examples. Do these differential operators form a vector space?

  • @tw5718
    @tw5718 Рік тому

    Just to clarify, is this the video formerly known as Derivatives vs Lie groups, 2 sides of the same thing? Added this to watch later, and now its different, I think.

    • @tw5718
      @tw5718 Рік тому

      After watching it is. First off, interesting video. I would like to provude my 2 cents about the name change.
      I think this title might be better for getting clicks in general. However, I'm not sure that many of those extra clicks will necessarily be your target audience. If I was a calc 1 student I would click instantly, but not really follow any of this video.
      I am currently trying to work through QFT and as such Lie groups are of very high importance to me, particularly ones that offer intuition, as opposed to definitions and calculations.
      The old title promised insight and intuition, which is why I saved it, and the video delivered. However, had I not seen the old title and known the content of the video, it's quite likely that the pun would have gone over my head, causing me to just write it off as a click baity video, and not watch it.
      All said and done, I'm really glad I watched it, and maybe the pun would have occured to me, but sometimes I'm slow on those things.
      Take that for what it's worth, just keep giving more Lie videos (and other high quality educational content). But more Lie videos.

    • @MichaelPennMath
      @MichaelPennMath  Рік тому +1

      welcome to the wonderful world of A/B testing.
      -Stephanie
      MP Editor

    • @tw5718
      @tw5718 Рік тому

      I most definitely understand it. I simply wanted to offer my take on this particular title selection. I could very well be the minority.
      I'm not sure what it looks like on your end, but I saved the video when it was the OG title, but didn't watch it until it had changed. Not sure if you get that statistic or not.

  • @tomholroyd7519
    @tomholroyd7519 Рік тому +8

    LOL yeah it's Leibniz. In German, when you have "ie" or "ei", it's pronounced like the second letter. "Lei" is "lye". "Lie" is "Lee"

    • @Toranx
      @Toranx Рік тому +1

      Actually it's "Leibnitz".

  • @jamesfortune243
    @jamesfortune243 Рік тому

    BTW, the math symbology of TeX/LaTeX is the official representation of mathematical equations and formulae by the American Mathematical Society.

  • @jafetriosduran
    @jafetriosduran Рік тому

    Very useful in control theory

  • @catbertsis
    @catbertsis Рік тому +1

    10/10 clickbait, love it

  • @giorgiobarchiesi5003
    @giorgiobarchiesi5003 Рік тому +4

    Liebnitz? Was this typo made on purpose?

    • @MichaelPennMath
      @MichaelPennMath  Рік тому +3

      Yes. That's my story and I'm sticking to it.
      -Stephanie
      MP Editor

  • @izzettechpriest255
    @izzettechpriest255 Рік тому

    Liebnitz rule? seems like Lie + Leibnitz, nice mix.

  • @NewtonMD
    @NewtonMD Рік тому +3

    The title 💀

  • @theelk801
    @theelk801 Рік тому +3

    commenting to say I want that representation video, also commenting to ask for more differential forms videos

  • @NarutoSSj6
    @NarutoSSj6 Рік тому

    Science is a lie. Sometimes.

  • @williamrhys5015
    @williamrhys5015 Рік тому +1

    William Rhys likes fire truck

  • @ax_tube
    @ax_tube Рік тому

    Leibnitz rule

  • @aron8999
    @aron8999 Рік тому

    that is not how you draw a g bro

  • @sunritpal1037
    @sunritpal1037 Рік тому +1

    The name of the guy teaching is Michael Penn.

  • @shafin3365
    @shafin3365 Рік тому +3

    Hi

  • @Andbovi
    @Andbovi Рік тому +2

    The solution of the golden sequence video is wrong! Read the comments!