Using NSCP 2015 Meron kami ginagawa muna to confirm if singly (Mu < ϕMn) or doubly (Mu > ϕMn) by using a formula ϕMn = (459/1600)(fc)(β)(b)(d^2)[1 - (3/16)(β)]*(10^-6) kN∙m Substituting all the values with (ϕ = 0.90, tension controlled only), ϕMn = 422.776 kN∙m which is lesser than Mu = 428 kN∙m. Therefore doubly na ito. Just for fun lang, Kung pipilitin i-solve ito using singly, then I tried to use an app to solve itong tedious algebra equations at ito ang mga lumabas: ϕ = 0.7185331073299 fs = 575.239 MPa As = 3665.99 mm^2 a = 216.953 mm c = 255.239 mm Rn = 7.9421 ρ = 0.0244399 Conclusion: Nasa transition period talaga pero pagdating sa design, gusto natin na laging tension controlled kaya better to switch na ang ganitong problem to doubly RC beam.
Sir pwedi po ba e recompute nlang po tas e change ang value reduction factor na nka transition region po sa Rn na formula sa nscp 2010/2015 ? Pwede ba yon sir😅
Sir pano pag transition controlled. Ano po gagamiting fs sa reduction factor?
Using NSCP 2015
Meron kami ginagawa muna to confirm if singly (Mu < ϕMn) or doubly (Mu > ϕMn) by using a formula ϕMn = (459/1600)(fc)(β)(b)(d^2)[1 - (3/16)(β)]*(10^-6) kN∙m
Substituting all the values with (ϕ = 0.90, tension controlled only), ϕMn = 422.776 kN∙m which is lesser than Mu = 428 kN∙m. Therefore doubly na ito.
Just for fun lang, Kung pipilitin i-solve ito using singly, then I tried to use an app to solve itong tedious algebra equations at ito ang mga lumabas:
ϕ = 0.7185331073299
fs = 575.239 MPa
As = 3665.99 mm^2
a = 216.953 mm
c = 255.239 mm
Rn = 7.9421
ρ = 0.0244399
Conclusion: Nasa transition period talaga pero pagdating sa design, gusto natin na laging tension controlled kaya better to switch na ang ganitong problem to doubly RC beam.
Is 2010 same procedure and value with 2015?
Sir pwedi po ba e recompute nlang po tas e change ang value reduction factor na nka transition region po sa Rn na formula sa nscp 2010/2015 ? Pwede ba yon sir😅