Thank u sir at first I was not able to decide which type of engineering I should take but after watching ur videos I decided to take mechanical engineering
The direction b/w rocket and fuel is opposite, according to relative motion we know when two objects like train go in negative direction both , we use Vr=v1-(-v2)
2:15 this ques can be done in by momentum conservation take final position to be at time 't' Consider . as not M.V. = (M. + lambdaT)V V=M.V./M.+lambdaT i hope this helped
Sir, I have been to Bangalore for Residential based Coaching after my class 10th ICSE exam in which I got 95%.That place didnt suited me and I came back after 4 months and joined my school back.Then I got to know about Unacademy JEE live and literally that helped me in completing my backlogs of 4 months. Love you Sir for this inspirational Channel.❤❤❤❤❤❤❤❤❤
It has to be perceived in the manner that at a particular time t, there would be a particular constant mass characteristic of that moment or time. It has not been used for a duration, and thus stands correct.
Sir hamari coaching mein bola hai variable mass is out of JEE syllabus and thus they didn't teach it. Sir is it in syllabus or out of syllabus, please confirm sir. Thank you sir and love your videos. 😊♥️♥️
Collision topic collided with my head elastically,I hope there will be no loss of energy and I will nvr forget the topic the lectures were amazing namo sir🤩u r grt💖
aree bolo ki perfectly inelastic collision hua dimaag see chipka gya elastic collision hoga to dimag se takra ke chala jaiga durr kya collison sikha re baba
1st questions was a simple question of Conservation of linear momentum. In time t mass of drop fallen =xt So total mass of cart a time=t is M+xt Mv=(M+xt)v' And now v' can be calculated
OMG!!! How you observed that!!! It's so detailed method to solve with integration! One page of solution! And you gave answer In just 5 lines!!!! Just amazing!!!! 🤩
Sir I am in class 11th preparing for IIT JEE how to make my physics strong kyuki meri physics weak h I can't score gud in test always having half of the total marks
@@payalsingh624 don't expect anything from institute this year was hell for average students ....like me ......they only focused on toppers whole year ......I'm going for individual tuitions in plus two .......get yourself a good teacher instead of institutes who has some experience with neet exam ......LASTLY .......self study is only way YOU CAN CLEAR NEET you can cover up 11 th syll in class 12th side by side . GOOD LUCK .....ILL BE GIVING NEET 2022 WITH YOU TOO 👍
37:44 could have been found by using conservation of momentum directly Initial momentum =Mv Final momentum=(M+lambda( t))v' Equating we get v' (velocity as a function of time)
BRO WOH CONCEPTUALLY WRONG HO JAAYEGA...COLM CAN ONLY BE APPLIED WHEN THE NET EXT FORCE ON THE SYSTEM IS ZERO...BUT IS CASE ME F(THRUST) PICHE LAG RHA HAI JISKO CANCEL OUT KARNE WAALA KOI FORCE NHI HAI...SO COLM SE BHALE HI ANS. AA JAAYE BUT WOH CONCEPTUALLY WRONG HAI
@Namo Kaul.... I just wanted to take a moment to thank you for being such an wonderful guide for all of us.... In this few months journey you did such a thing which we weren't able to do for the last one and a half year... You made my journey of JEE extremely wonderful in one word awesome.... Just as me....all others have the same feeling I guess and I on behalf of all the students want to thank you and the whole team of unacademy JEE for taking such an initiative for us.... Thanks a lot again☺️☺️
30:30 matlab kuck vi😒😒 Relative velocity ki sare formula mazak hai Ap galat bol rahe ho. Actually x direction mai relative velocity v hai.kuki cart sirf x axis pe move kar sakti hai islia ham log water ka velocity ka sirf x axis wala component lete hai jo ki 0 hai.
Namooo sirr ki jayyyy hoooo.....🙏 Just bcuz of u great teachers we gain confidence to really appear such difficulties or to face such 🙏 Thank u so much dear JEE unacademy team for ur blockbuster performances in teaching ...........
I think you need to provide more clear explanation of both accretion/ablation because there are many average students who find it difficult to grab your lecture . But overall ,Lecture was nice.
Please help can anyone explain the meaning of external force in conservation of momentum, in rocket propulsion mass is decreasing and velocity is increasing then how can we say momentum is conserved
brother see, if there is no external foce aplied, the total momentum of the system remains constant, i.e., conservation of momentum. Also, "external force" here means that no force acts from outside. It is clear from the concept, rocket is losing its own mass on its own, nothing else from outside is applying this force. This happens internally in the rocket due to combustion, hence the conservation of linear momentum can be applied.
I think you went by flow in 1st questions As when rain is dropping on the cart how can thrust be in that direction as nothing is going in left direction to provide thrust in right direction. Plz clear this doubt
I am a student which has opted PCM with Economics in class 11, but I am not interested in neither Engineering nor medical.. I want to do economics honours from Delhi School of Economics. So, I want to know that is Unacademy just for JEE, NEET, CLAT and UPSC???
Sir at t=t time par jab velocity v hai us time bhi to gases bahar aarahi hongi to tab humne exhaust gases ka momentum rocket ke momentum mai add kyun nahi kiya
![Lp. Сердце Вселенной #60 РОЖДЕНИЕ ЛОЛОЛОШКИ [Финал] • Майнкрафт](http://i.ytimg.com/vi/YoR0pAV9FVQ/mqdefault.jpg)
Video starts at 8:30
I was searching for this comment only
Me 2
Tqq
Thanks
Thanks
Thank u sir at first I was not able to decide which type of engineering I should take but after watching ur videos I decided to take mechanical engineering
i got interest in physics because of Namo sir .........!!!!!!!!!!!!!!!
True yaar...
Chl jhutha
18:55 , Why not -ve sign for relative motion between v1 & v + dv?
The direction b/w rocket and fuel is opposite, according to relative motion we know when two objects like train go in negative direction both , we use Vr=v1-(-v2)
8:32 lecture starts😉😉😉😉👍👍👍
study well..
Directly we can apply law of conservation of momentum to get answers as It is short than this method sir
Rocket , eject , move (forward) wow nice lecture
Really inspired by you sir
Thank you for making this quality education possible..
2:15
this ques can be done in by momentum conservation take final position to be at time 't'
Consider . as not
M.V. = (M. + lambdaT)V
V=M.V./M.+lambdaT
i hope this helped
Although Namo Sir has less views than other teachers on You Tube but still he has got the best content for us🔥
Sir, I have been to Bangalore for Residential based Coaching after my class 10th ICSE exam in which I got 95%.That place didnt suited me and I came back after 4 months and joined my school back.Then I got to know about Unacademy JEE live and literally that helped me in completing my backlogs of 4 months.
Love you Sir for this inspirational Channel.❤❤❤❤❤❤❤❤❤
Deeksha?
@@pavanbhat3861 No
@@khalidbinamir7240 Oh ok. Where?
@@pavanbhat3861 BTM stage 2
@@khalidbinamir7240 Nice nice.
8:32 lecturer start
Ty
#NamoSir ki jai!!
Namo Sir zindabaad ☺️😎
Jai ho
Unacademy ki Jay 🏴
Sir 1st question can be done by momentum conservation initial momentum= MV
final momentum= (M+lambda*t)*V final
yup net force on the system is zerro.
Fast growing channel in IIT 😍😍😍😍😍😍
I think its ur channel on utube with which u have started ur studies
31:37 using F=ma in variable mass system 🙌🙌🙌👏👏👏👏👏
Correct way to solve- Apply momentum conservation
I think they didn't used the momentum conservation Because thrust force is acting in horizontal direction
It has to be perceived in the manner that at a particular time t, there would be a particular constant mass characteristic of that moment or time. It has not been used for a duration, and thus stands correct.
Sir aap hi class 12 physics bhi lijiye aisa killer visualisation nahi dekha
35:00 the question can be solved in a shorter way using conservation of momentum along x direction
Exactly. But we must assume that there is no external force in horizontal direction.
@@ujjwalnarayan07 Right 😏
Sir hamari coaching mein bola hai variable mass is out of JEE syllabus and thus they didn't teach it. Sir is it in syllabus or out of syllabus, please confirm sir. Thank you sir and love your videos. 😊♥️♥️
It is in the syllabus
Nahi hai
I think it is in the syllabus of advance not mains
It’s not even in HCV
@@sonit9707 it is in hcv
I am a neet aspirant and I was having a bit of difficulty in this type of integration but now it's crystal 🔮 clear Thank u so much sir 🥰
Namo sir when we complete our syllabus plz replu
Best team of teachers
sir rotation dynamics kab start hoga???//pls tell
sir momentum conservation se even more simply solve ho ja raha hai.. thanku sir ji
Bas First question hi hoga conservation se , last wala kaise kar paoge usse ???
Sir aapne rocket science pe v lecture bnaya...aisa content kisi v iit jee channel pe milna asambhav hai...thankyou very much sir 😊
Collision topic collided with my head elastically,I hope there will be no loss of energy and I will nvr forget the topic the lectures were amazing namo sir🤩u r grt💖
I hope the same ✌️🔥😎
aree bolo ki perfectly inelastic collision hua dimaag see chipka gya
elastic collision hoga to dimag se takra ke chala jaiga durr
kya collison sikha re baba
elastic collision there is no loss of energy and body regain their original shape whereas in inelastic collision there is a loss of energy.
@@AB-gq2he yes it inelastic aur chipak gaya Teri dimag me Are '
Elastic collision lmao
Thankyou Sir ..l was searching this concept everywhere...now l got it...very well explained.
1st questions was a simple question of Conservation of linear momentum.
In time t mass of drop fallen =xt
So total mass of cart a time=t is M+xt
Mv=(M+xt)v'
And now v' can be calculated
OMG!!! How you observed that!!!
It's so detailed method to solve with integration! One page of solution!
And you gave answer In just 5 lines!!!!
Just amazing!!!! 🤩
Itna a66a kahi par nahi prhayajata thank you ☺️ to The best faculty of physics
You don't know about Salim sir
👍👍👍👍👍👍👍👍
Shandar😊😊
Thank you so much for explaining ✌️✌️
At 43 :50 so can we say that the thrust force is independent of time and just depends upon mass and u relative?
Sir bohot achha laga...ab toh numericals rocket ke speed me solve karunga 🚀🚀🚀
😂😂😂😂😂
😂😂😂🤣
hahaaha
Sir I am in class 11th preparing for IIT JEE how to make my physics strong kyuki meri physics weak h I can't score gud in test always having half of the total marks
See alakh sir videos
Physics is not studied but learnt and felt which we don't do thus it become difficult to go through it
solve maximum no. of question. it will clear all your doubt and built up ur concept
Bhai understanding of concept is must
Just fall in love with subject
Dont take it as a burden
Sir can I ask you a question
"do you to watch Alakh Pandey videos?"
I do
Shi bola bro
Sahi h
Best physics teacher 😍😍😍
superb comment😂
best lecture on variable mass system!!
Best lecture ever on unacademy jee
What happen if there is rebounding in the chain in the last question sir.
Please Reply.
Are these type questions necessary for neet also
Sir I'm an neet aspirant right now in 11th and watching you're vedios
just because I can't go for highly expensive online coaching .
You saved money ......everyone wasted their money this year on shitty institutes like me ........
@@freakygrandma4626 but what about this year that I've wasted and wanted to clear neet in 2022
@@payalsingh624 don't expect anything from institute this year was hell for average students ....like me ......they only focused on toppers whole year ......I'm going for individual tuitions in plus two .......get yourself a good teacher instead of institutes who has some experience with neet exam ......LASTLY .......self study is only way YOU CAN CLEAR NEET you can cover up 11 th syll in class 12th side by side . GOOD LUCK .....ILL BE GIVING NEET 2022 WITH YOU TOO 👍
@@freakygrandma4626 Great, best of luck for you too.
Kam samaj may aya sir
Yes
37:44 could have been found by using conservation of momentum directly
Initial momentum =Mv
Final momentum=(M+lambda( t))v'
Equating we get v' (velocity as a function of time)
One of the best teacher of physics for iit jee. Sir you have killer method of teaching
Thank u so much sir all cleared❤❤!
Sir telegram link is not working
I m preparing for iit jee free only bcoz of u and your team 🥰❤
Ykkj kkkubokjb
Great job....
Ad ends at 8:32
Sir first question to bahut easy tha. Ham use momentum conservation se kar sakte the but aapne use lengthy bana diya
We are very thankful to you
The first question could be done in one step using Momentum Conservation.
BRO WOH CONCEPTUALLY WRONG HO JAAYEGA...COLM CAN ONLY BE APPLIED WHEN THE NET EXT FORCE ON THE SYSTEM IS ZERO...BUT IS CASE ME F(THRUST) PICHE LAG RHA HAI JISKO CANCEL OUT KARNE WAALA KOI FORCE NHI HAI...SO COLM SE BHALE HI ANS. AA JAAYE BUT WOH CONCEPTUALLY WRONG HAI
@@theanalyzer2390 ok thanks
Best lecture ever ❤️
You know I was looking for teacher of mechanics. And I got you today. ☺️
@Namo Kaul.... I just wanted to take a moment to thank you for being such an wonderful guide for all of us.... In this few months journey you did such a thing which we weren't able to do for the last one and a half year... You made my journey of JEE extremely wonderful in one word awesome.... Just as me....all others have the same feeling I guess and I on behalf of all the students want to thank you and the whole team of unacademy JEE for taking such an initiative for us.... Thanks a lot again☺️☺️
thank you very much sir you way of teaching physics awesome
Vid starts at 8:40
Cleared all my doubts. Thank you very much sir. Love your spirit.
Sir is yoga helpful in preparation
Certainly not if haven't did it before...
No you still have to study 😂😂
In a way it is.
You can focus and concentrate more if you do yoga
Sir, you are best ❤❤❤
At 37:30 problem per momentum conserve karthe tho sir ek step me ajatha sir
Sahi baat h bhai😂
30:30 matlab kuck vi😒😒
Relative velocity ki sare formula mazak hai
Ap galat bol rahe ho. Actually x direction mai relative velocity v hai.kuki cart sirf x axis pe move kar sakti hai islia ham log water ka velocity ka sirf x axis wala component lete hai jo ki 0 hai.
Namooo sirr ki jayyyy hoooo.....🙏
Just bcuz of u great teachers we gain confidence to really appear such difficulties or to face such 🙏 Thank u so much dear JEE unacademy team for ur blockbuster performances in teaching ...........
Wtw this video quality kyu nahi aa rahi hai
In F= mdv/dt + vdm/dt, does m and velocity both varii
Can we skip to the good part 8:55 😂😂
I think you need to provide more clear explanation of both accretion/ablation because there are many average students who find it difficult to grab your lecture . But overall ,Lecture was nice.
Er Abhinav Kumar u r right
❤️ Well explained sir!
Sir can't we apply momentum conservation in rocket propulsion
No because mass is not constt.
The formula is derived from momentum conservation so this is another way of writing linear momentum
We can apply
If we consider the main mass and ejected mass as a system at an instant
And sir has done the same in derivation
Yes in 1st question i done with momentum conservation
I did in less than 10 sec
creativators s if u dont know anything then don’t provide wrong information
Waah sir waah..
Sab clear ho gya...
Unacademy hai toh sab fit hai boss!!@
Please help can anyone explain the meaning of external force in conservation of momentum, in rocket propulsion mass is decreasing and velocity is increasing then how can we say momentum is conserved
brother see, if there is no external foce aplied, the total momentum of the system remains constant, i.e., conservation of momentum. Also, "external force" here means that no force acts from outside. It is clear from the concept, rocket is losing its own mass on its own, nothing else from outside is applying this force. This happens internally in the rocket due to combustion, hence the conservation of linear momentum can be applied.
GREAT SESSION
Unacademy ki Jay 🏴
Still namo sir...is fav. and his killer visualisation too...luv you namo sir🙋♀️🙌
☺very good
You are my ideal sir I want to become like you
Are sir maza hi aa gaya.
Teacher unacadmey pe sabhi achhe hai magar they are too jealous to other platform that makes them underrated channel nowadays
sir agar cart mein paani daalne se velocity change ho jati hai toh paani nikaalne se velocity constant
Sir Newton's 3rd law 8s only applicable for places where there is no friction ?
Sir unacademy plus subscription lene ke liye total money ek bar me hi pay karna hota hai kya
Ya Unacdemy wale osm word Bhut use karta hai
In one word : Awesome @namokaul
When do u start rotation motion
Sir plz do the video on this concept
Sir why is trust force acting downward in last question and in 2nd last question Thrust is acting in backward direction??
Reason ?.
Unacademy zindabad 🔥🔥🔥
sir kon se class hai
55:00 this question can also be done by work energy theoram na??
No bro
Nahi
Why can't we simply use the law of conservation of momentum for q1..I got the ans. in less than 10 seconds rather than 10 mins...
Ikr
Sir is it in syllabus or not plz confirm?
Love from Bangladesh❤
Can the first question be done simply with the help of conservation of momentum?
No, because this is a variable Mass system
Yes definitely
I done with that in less than 10 seconds
Naomie Mredha momentum conservation can be done in variable mass system
Cant we apply momentum conservation at 34:00 ?
Thanks
Sir you are best in all the world in teaching
Yes
Starts at 8:34
I think you went by flow in 1st questions
As when rain is dropping on the cart how can thrust be in that direction as nothing is going in left direction to provide thrust in right direction.
Plz clear this doubt
Yes bro iam really confused
I have the same doubt
I am a student which has opted PCM with Economics in class 11, but I am not interested in neither Engineering nor medical.. I want to do economics honours from Delhi School of Economics. So, I want to know that is Unacademy just for JEE, NEET, CLAT and UPSC???
Sir first example me hum direct conservation of momentum in x direction se bhi to answer find kar sakte h
Salute to you teachers❤❤
22:26
Sir Mdv/dt =force kaise ho gya hai
I mean aapne usse phle btaya ki F=vdm/dt+Mdv/dt
To phir 🤨😒😓😓😓😓😓😓😓😢😞😖😖
Sir at t=t time par jab velocity v hai us time bhi to gases bahar aarahi hongi to tab humne exhaust gases ka momentum rocket ke momentum mai add kyun nahi kiya
Plz reply sir