7.39 | Find the useful power output of an elevator motor that lifts a 2500-kg load a height of 35.0

(a) Find the useful power output of an elevator motor that lifts a 2500-kg load a height of 35.0 m in 12.0 s, if it also increases the speed from rest to 4.00 m/s. Note that the total mass of the counterbalanced system is 10,000 kg-so that only 2500 kg is raised in height, but the full 10,000 kg is accelerated.
(b) What does it cost, if electricity is $0.0900 per kW ⋅ h?
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