Thanks for the wind formula. I use MOA adjustments instead of Mils. All I need to do is multiply the answer in Mils by 3.44 to get an MOA adjustment. Accuracy is getting better every day.
So what is the constant for a 30-06 18ogr And how do u get a constant for each Rifle and were do u get this information? Thanks Good class brother. 🇺🇸 2A 🇺🇸
Luke Shave , Get the G1 BC so if your G1 BC is 525 than your constant is 5. If your G1 BC is 400 than it is 4. On the range you can true and find out exactly what MPH your bullet or gun is. Bit late but hope this helps someone out.
The MOA constant is 10. For example here’s the formula for a 10 mph wind at 600 yards: 600 yards divided by 100 equals 6 times 10 mph wind equals 60 divided by 10 constant equals 6 MOA wind drift or 36 inch favor.
Hi sir , can i use this formula with metric système , for the Wind i use m/s and not mph, and should i use the same constance with metric formula , 308win (4) ?
Does this formula really works? I want to see a video of this formula being tested. No physics involve. It's as easy as adding, subtraction, multiplying and dividing.
how can i create a constant for myself? I have a spr in 5.56 that i push out pretty far, I'd like to I use higher B.C bullets but i'm not sure what constant would work for something light like 77gr.
Bruce I'm sure there's some mathematical way to deduce one, but I don't have a clue what it'd be. Best way I know to tell you is trial and error, I'm guessing you'll be around 3-4 inside 600 and you'll probably have to add the 700 yd tenth sooner. Easiest way will be to reverse engineer it at the range, make your results fit the formula, and confirm it on subsequent trips out.
Yeah I think i figured it out, because I recognized your formula. Its based on whats known as the b.c method. so the constant will reflect what the b.c is, so a sierra match king with a .362 b.c you can probably get away with a 3.5 constant or with the new eld-m are in the .4s use 4. So what in theory, if the constant is 3.5, then 100 = .1 200 =.2 etc will be added to every 3.5 mph of wind. I think you're right, adding the .1. i think will probably be at 600 yards or before. reverse engineering and gathering some dope will be the best way to confirm for sure. Thanks for the response.
For 5.56, use 3 and try the formula at the range. You need to get a good measure of the wind though, so I would recommend using a wind measuring device as opposed to using the military sniper estimation methods. That is the only way to know for sure.
ACTION DESIGN SYNDICATE hi sir , let me firstly to thank you for your reply! Actually, I use my data book and my kestel anemometer for all my corrections, ... your tutto will give me a easy solution for my next shoot.
Discourse; 0 Kmph windage at the 800 metre range windage not dialled at 0x at the y axis elevations kentucky windage due to barrel twist per inches Miscellaneous facts; bullets aerodynamic bullet weight atmospheric pressures (measuring a humid) muzzle velocity match grade barrels MIL Scopes rifle mount stability aimed calculations human intervention ☺️
Do the formula in MOA, not mils, for a multitude of reasons, like when your scope or sights are in MOA, or when using irons which will require hold off in inches. Here's the formula: distance to target in yards divided by 100 times wind value in MPH divided by the constant. Now how do you determine the constant? The MOA constant for any distance can be determined through a trajectory calculation produced from an online ballistics service. Just think what the distance in yards divided by 100 times wind value in mph needs to be divided by to produce the trajectory calculation's given MOA adjustment for a 10 mph wind. Using the .308 (175 SMK @2610 fps) at 600 yards for example, 600 / 100 = 6 X 10 mph = 60, so now what would 60 need to be divided by to equal the 5 MOA stated wind favor from the trajectory calculation? The answer is 12. That's the constant you will then use to determine the wind favor in MOA for any wind value at 600 yards for the specified loading. For 1000 yards the constant is 10. This stuff is easy; but, if you have difficulty with wind, seek a credentialed coach/mentor. Most credentialed is a shooter holding an NRA Long Range High Master rating. Ask your coach/mentor what wind constant he uses for 600 or 1000-yard competitions. If you get gobbledygook instead of a straight answer, move on to a more qualified coach. Creds: US Distinguished Rifleman, NRA American High-Power Rifleman, SAFS Coach, and SDM Instructor.
Thanks for the wind formula. I use MOA adjustments instead of Mils. All I need to do is multiply the answer in Mils by 3.44 to get an MOA adjustment. Accuracy is getting better every day.
2.5 seems to be the constant for 556 to get it to 2 mils. what most people say is the 10 mph wind hold at 500 yards.
So what is the constant for a
30-06 18ogr And how do u get a constant for each Rifle and were do u get this information? Thanks
Good class brother. 🇺🇸 2A 🇺🇸
Judging by the constant of the various calibers he quoted, it seems to be roughly equivalent to the ballistic coefficient of the bullet.
Great video my friend. This helped me derive another wind formula I saw, However this one is much easier!
How do i find the constant of my bullet
Luke Shave ,
Get the G1 BC so if your G1 BC is 525 than your constant is 5. If your G1 BC is 400 than it is 4. On the range you can true and find out exactly what MPH your bullet or gun is. Bit late but hope this helps someone out.
@@Bk7820-e3d a bit later than you but thanks for the info. It was my question too.
@@politicallyinsensitive4200a bit later than you but i agree. i needed this answered
What is the constant for 556?
I love the show very nice.
But tell me how do you get the
Numbers for constant for each caliber
So would I have to add .2 for 1400 range
Can you input range in metres for this formula?
What is the constant for 6.5 creedmoor
Where do you get the constant from?
All your calculations add up into Mills. How do you calculate that into MOA? Thanks
Pretty sure you times it by 3.44 if I remember correctly
thats why our constant increases - said no one ever who knows what constant means.
Never tried to determine one honestly, should be very close to that of the .260 though.
DoubleTapLLC
but the dérection of wind is not sime
What would be the constant for a 5.56 ? Like MK 262. And in what distance would add .1 in the formula? Thank you .
The MOA constant is 10. For example here’s the formula for a 10 mph wind at 600 yards: 600 yards divided by 100 equals 6 times 10 mph wind equals 60 divided by 10 constant equals 6 MOA wind drift or 36 inch favor.
Great video, thanks sir
Hi sir , can i use this formula with metric système , for the Wind i use m/s and not mph, and should i use the same constance with metric formula , 308win (4) ?
No. You need to multiply the constant by the conversion factor between mi/h and m/s.
Does this formula really works? I want to see a video of this formula being tested. No physics involve. It's as easy as adding, subtraction, multiplying and dividing.
We dont know how we find the constant of our bullet. Please help us??
What's the formula for metrics though?
I can't seem to find the formula for the metric system either.
Just convert it. 1 yard = .9144 meters. 600 yds x .9144 = 548.64 meters. 1 meter = 1.094 yards. 600 meters x 1.094 = 656.4 yards and so on.
Good method ! Anyone knows the constant for 6.5 creedmoor ?
MOA constant is about 17 at 1000 yards.
how can i create a constant for myself? I have a spr in 5.56 that i push out pretty far, I'd like to I use higher B.C bullets but i'm not sure what constant would work for something light like 77gr.
Bruce I'm sure there's some mathematical way to deduce one, but I don't have a clue what it'd be. Best way I know to tell you is trial and error, I'm guessing you'll be around 3-4 inside 600 and you'll probably have to add the 700 yd tenth sooner. Easiest way will be to reverse engineer it at the range, make your results fit the formula, and confirm it on subsequent trips out.
Yeah I think i figured it out, because I recognized your formula. Its based on whats known as the b.c method. so the constant will reflect what the b.c is, so a sierra match king with a .362 b.c you can probably get away with a 3.5 constant or with the new eld-m are in the .4s use 4.
So what in theory, if the constant is 3.5, then 100 = .1 200 =.2 etc will be added to every 3.5 mph of wind. I think you're right, adding the .1. i think will probably be at 600 yards or before.
reverse engineering and gathering some dope will be the best way to confirm for sure. Thanks for the response.
Hi sir , could i use this formula with metric measurements?
I’ve a steiner optic ( scope turret mrad )
For 5.56, use 3 and try the formula at the range. You need to get a good measure of the wind though, so I would recommend using a wind measuring device as opposed to using the military sniper estimation methods. That is the only way to know for sure.
ACTION DESIGN SYNDICATE hi sir , let me firstly to thank you for your reply!
Actually, I use my data book and my kestel anemometer for all my corrections, ... your tutto will give me a easy solution for my next shoot.
Excellent
Discourse;
0 Kmph windage at the 800 metre range
windage not dialled at 0x at the y axis elevations
kentucky windage due to barrel twist per inches
Miscellaneous facts;
bullets aerodynamic
bullet weight
atmospheric pressures (measuring a humid)
muzzle velocity
match grade barrels
MIL Scopes
rifle mount stability
aimed calculations
human intervention
☺️
Do the formula in MOA, not mils, for a multitude of reasons, like when your scope or sights are in MOA, or when using irons which will require hold off in inches. Here's the formula: distance to target in yards divided by 100 times wind value in MPH divided by the constant. Now how do you determine the constant? The MOA constant for any distance can be determined through a trajectory calculation produced from an online ballistics service. Just think what the distance in yards divided by 100 times wind value in mph needs to be divided by to produce the trajectory calculation's given MOA adjustment for a 10 mph wind. Using the .308 (175 SMK @2610 fps) at 600 yards for example, 600 / 100 = 6 X 10 mph = 60, so now what would 60 need to be divided by to equal the 5 MOA stated wind favor from the trajectory calculation? The answer is 12. That's the constant you will then use to determine the wind favor in MOA for any wind value at 600 yards for the specified loading. For 1000 yards the constant is 10. This stuff is easy; but, if you have difficulty with wind, seek a credentialed coach/mentor. Most credentialed is a shooter holding an NRA Long Range High Master rating. Ask your coach/mentor what wind constant he uses for 600 or 1000-yard competitions. If you get gobbledygook instead of a straight answer, move on to a more qualified coach. Creds: US Distinguished Rifleman, NRA American High-Power Rifleman, SAFS Coach, and SDM Instructor.
What is the constant for 6.5 creedmor ?
Leo Shino 5
@@Mr1OM not 6 or even 6,5 ?
Nice. We'll that's all good for mil guys. What about us MOA guys? Is the math the same still? 🇺🇸 2A 🇺🇸
WTH?