its funny that when you write "Boring leactures about fluid statics" you get the most intresting, most enjoyable , most helpful video . Thank you so much for these videos
It can’t be understated how useful your videos are. I genuinely appreciate your channel more than you’ll ever know and wish you all the best, thank you.
At 2:09 the horisontal pressure P*sin(theta) should act on the projected surface perpendicular to it. So Py * delta z * delta x = P * sin(theta) * delta s * cos(theta) * delta x Py * delta z = P * sin(theta) * delta z Py = P * sin(theta) And by same procedure Pz = P * cos(theta)
5:10 you say “in that direction” ( assuming acc.going in the same direction as the force ) but then you draw it facing the opposite direction. Then once it’s in the tube , the acc. moves in the same direction as the force. Can you you clarify it for me please?
CORRECTION: At 10:15, the first term after P_outside, should have h3, not h1.
It doesn't matter... you've earned my Sub👍
You are wrong
Why do you times all the pressure values by 10*m/s^2 btw? what's the reasoning for that as I thought the values was already in Kg/m^3
its funny that when you write "Boring leactures about fluid statics" you get the most intresting, most enjoyable , most helpful video . Thank you so much for these videos
It can’t be understated how useful your videos are. I genuinely appreciate your channel more than you’ll ever know and wish you all the best, thank you.
WOW thank you so much for your work! Now I know when the pressures at the same height would equal to each other!
At 2:09 the horisontal pressure P*sin(theta) should act on the projected surface perpendicular to it.
So Py * delta z * delta x = P * sin(theta) * delta s * cos(theta) * delta x
Py * delta z = P * sin(theta) * delta z
Py = P * sin(theta)
And by same procedure Pz = P * cos(theta)
please add the example videos too
Thank you, You are amazing
the value for p(hg)gh should be. (13600) (10) (1), btw nice video and really helpful
5:10 you say “in that direction” ( assuming acc.going in the same direction as the force ) but then you draw it facing the opposite direction. Then once it’s in the tube , the acc. moves in the same direction as the force. Can you you clarify it for me please?
I believe a mistake was made on the manometer equation written in black at 10:15. The first column of mercury should use h3 not h1, right?
Correct, thank you!
have seen some mistakes:
1) the gravity value is 9.81
2)you used the density of water for the mercury part at the end which made it wrong
I wonder what would be the result if at 8:54 that solid obstacle was a piston.
The density of mercury should be 13600 kg/m^3 right?
Why is it 1000 kg/m^3 in your solution?
You gotta post the examples my man😩
Pressure vector 0:26 seriously.....pls guide
still waiting your example
nc
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