For moment of a couple, the reference point does not matter like in moment about a point. In couple moment we focus only on the two forces and the distance between them. We don't look at the line of action of the force to determine whether or not it has no effect on the resultant moment.
For the first example, why did you decide to choose the second 400N force which will move in an anticlockwise direction and after that, you chose forces that move in a clockwise direction. Couldn't you have chosen all forces that move in a clockwise direction?
this is my solution of using moment of a couple anticlockwise: Mc = 0 anticlockwise Mc = 400(2) -200(0.2) - 300(5) Mc = -740 N/m clockwise is this considered as a correct answer?
It's correct, except that you defined anticlockwise as negative, hence since you have a negative resultant moment, the moment should be anticlockwise and not clockwise. I hope you get it.
Well I get it, usually for moment. We focus on the force and the perpendicular distance. So you look at the line of direction of the force, and the perpendicular distance. For example 1. If the force is directed upwards, and the perpendicular distance is on the left of the force, then the direction is anticlockwise. 2. If the force is directed upwards, and the perpendicular distance is on the right of the force, then the direction is clockwise.
You're too good i understood this in 16 mins❤
Awww thanks so so much
Excellent👏🏾
Thank you.
For question 1, why would the horizontal forces matter? Since they pass through the line of action they shouldn’t matter right
For moment of a couple, the reference point does not matter like in moment about a point. In couple moment we focus only on the two forces and the distance between them. We don't look at the line of action of the force to determine whether or not it has no effect on the resultant moment.
For the first example, why did you decide to choose the second 400N force which will move in an anticlockwise direction and after that, you chose forces that move in a clockwise direction. Couldn't you have chosen all forces that move in a clockwise direction?
this is my solution of using moment of a couple anticlockwise:
Mc = 0 anticlockwise
Mc = 400(2) -200(0.2) - 300(5)
Mc = -740 N/m clockwise
is this considered as a correct answer?
It's correct, except that you defined anticlockwise as negative, hence since you have a negative resultant moment, the moment should be anticlockwise and not clockwise. I hope you get it.
isnt a clockwise rotation of a moment (-) while a clockwise rotation (+)?
Kindly check your question
Thankssss
Please you are most welcome
hi, i still do not get when it is clockwise and when it is anticlock. hope u will see this.
Well I get it, usually for moment.
We focus on the force and the perpendicular distance.
So you look at the line of direction of the force, and the perpendicular distance.
For example
1. If the force is directed upwards, and the perpendicular distance is on the left of the force, then the direction is anticlockwise.
2. If the force is directed upwards, and the perpendicular distance is on the right of the force, then the direction is clockwise.
@@SkanCityAcademy_SirJohn Hello sir,what about the forces that are directed downwards?
I thought clockwise should rather be negative and anti clockwise is positive
No please, any direction can be clockwise or anticlockwise
Isnt the ccw (+) and cw(_) why did u made it positive sir?
Kindly state the exact time in the video so I cross check for you.
10q bro
I think the -2.6 is wrong I think it is -3.5
The right answer is -2.6KNm
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Thanks for your comment Priscy
I thought clockwise should rather be negative and anti clockwise is positive
No please, you can take any direction as clockwise or anticlockwise