I multiplied by 3 to match up the variable b in both equations. So then both bs would have a 3 coefficient. The process is the key to eliminating the b variable. If the top equation had a 4b, I would have multiplied by 4.
nicely done, but what about when you can't reduce when you're trying to eliminate a or b. is it protocol to multiply each equation by a different value to achieve the same a or b value?
If we use the method of elimination, then yes we multiply the two equation by the the number required to make the least common multiple of either a or b
I am sick of doing homework every damn day. I want to enjoy my winter holidays. Sick of these BS teachers to be honest with u. Thank u for this. I understood nothing due to the lack of my brain
@@danielschaben everything is that way my friend. It takes a lot of practice to get past any obstacle or even being rich! I had a terrible mindset when I wrote this
At 3:08 what he did there was multiply the bottom equation by -1, and that is allowed, and what you get for your trouble is all the signs change and the coefficients on the C terms are now opposites or additive inverses.
In your case, (0,4) is the y-intercept. Therefore, c=4. Still unsure? Plug it in! f(0)=ax^2+bx+c. Substitute every instance of x with 0. a(0^2)+b*0+c. What's left after this is c. Since f(0)=4 and f(0)=c, then c=4
Actually that is an amazing question, and one I have had in the back of my mind, but never spent time exploring. It won't work with any three points because the three points have to form a parabola. So if you used (2,1) (2, 3) (5,7) for instance y = ax^2+bx+c would not work however I think x = ay^2 + by + c would work for those three points. You have me thinking. ... Great question. If you stacked three points it would not work in either case (2, 1) (2, 3,) (2, 4). would not work, or any three collinear points would not work. I don't have time right now to explore much more. But what if the three points lie on a circle? What about three points that lie on a hyperbola or trig function? ohhhh so much we could explore with this seemingly silly question. Good work getting my mind working!
Lots of them. Wolfram alpha 3 equation 3 unknown calculator is one I've used. Although when you get into linear algebra and start representing these with matrices there becomes many ways to do it with matrix capable calculators
I love watching different instructors/teachers/professors show the steps in working more complicated algebra topics but I wonder if too much time is spent on the basic arithmetic. If someone is learning algebra and doesn’t get eliminating or moving variables and constants in the solution process then maybe they should be watching basic math videos first. It really slows down the instruction. Just an observation.
I really only make these videos for my students. They will watch them mainly as more practice for those that need it. A way of studying for the test. I only threw them up here as a free place to store them back in 2010. Had no idea that anyone else would even find them valuable. Wish I had time to make more.
god bless you but what happens if I get numbers such as 0.55? Because your tutorial works bad at this case A (-2/22) B (1/7) C (3/2) and at the end, my results are a bit different than the 3 given points like if I use B I get 6.98 instead of 7 or 22,87 instead of 22
Consider yourself lucky. I've seen 30 year olds cry doing this stuff. If your a 6th grader and have a handle on it. I expect nothing less than you creating your own space company and the next mission to Europa (one of Jupiter's moons) :) Thanks for the comment and good luck. What starts out at drudgery could turn into the next thing that changes the world. You never know.
It's a lot to remember, just remember that showing work helps. I hardly ever downgrade for silly errors. If your logic is sound, I am usually pretty happy.
searching4math meanwhile my math teacher gave me a D+ on my quiz because my answer came out positive instead of negative, and didn’t mention something that wasn’t asked in the question
God bless people who post math tutorials on UA-cam.
Shouldn't you be playing zombs royale?
Lead lol
Holy crap. Your a celebrity. I need to get my numbers closer to yours!
@@danielschaben Youre and wdym number
I was stuck on this for a good hour until I watched this video, and I got it first try. Thanks a bunch!
Glad I could help!
This was really helpful! I didn't know how to solve it before, and now, I can get in just one try! Thank you so much!
Amazing!! What a great job at explaining! Bravo and cheers!
this was a bitchin' tutorial, thanks.
Even after 10 years its still useful😭🙏
Thank you, fine sir.
Thank you so much! I have a test tomorrow and you just saved my butt!
thank you sm :,). before this video i struggled so much i cried at my hw. thank you thank you thank youuuuu
mate this was so helpful thankyou sooo much, you made it so easy keep it up man.
thanks for the comment. I'm glad I could help!
Thank you so much, I have my math final today this really helped me out.
@7:59 what if all of my equations are positive? Is there something i need to change?
thank you so much I honestly had the biggest headache doing this. You are a hero.
Fantastic video
Thanks
Thank you for taking the time to make this video, even if it was a few years ago because this video just saved me with my homework!
You're welcome 😊
why did you at 5 minutes and 15 seconds say to multiply the bottom equation by 3. Where did you get the 3 from thanks.
I multiplied by 3 to match up the variable b in both equations. So then both bs would have a 3 coefficient. The process is the key to eliminating the b variable. If the top equation had a 4b, I would have multiplied by 4.
nicely done, but what about when you can't reduce when you're trying to eliminate a or b. is it protocol to multiply each equation by a different value to achieve the same a or b value?
If we use the method of elimination, then yes we multiply the two equation by the the number required to make the least common multiple of either a or b
@@danielschaben right on, thanks for the reply + the very helpful video
I was so close to finding it by myself, thanks for the help! :)
Glad I could help!
Would this work for functions that are not porabolas as well?
Thank you for actually showing how to do it instead of using 0 as one of the x's for an easy variable.
Glad I could help
Bruv, youve saved ma life dawg, thanks homie i gotta mock exam tomorrow
Good Work Sir
sir konsa software use karty hain??
You just saved my a** on the last day of the semester. Thanks bro:)
Any time! If you need anymore math help send me a comment. If I have time I will try and help
I am sick of doing homework every damn day. I want to enjoy my winter holidays. Sick of these BS teachers to be honest with u. Thank u for this. I understood nothing due to the lack of my brain
Just saw this. I know the feeling. Thanks for the comment
@@danielschaben oh. I can't belive I wrote this. What a crybaby I was
@@Drforeverok oh no. Math is that way. It takes a while to get past the pain. Lots of practice
@@danielschaben everything is that way my friend. It takes a lot of practice to get past any obstacle or even being rich! I had a terrible mindset when I wrote this
Thank you so much! Lol this was so helpful I refreshed to watch the ad
At 3:08 what he did there was multiply the bottom equation by -1, and that is allowed, and what you get for your trouble is all the signs change and the coefficients on the C terms are now opposites or additive inverses.
OMG THANK YOU! He was confusing me but i got it now
Excuse me, what do I do if one of my sets of points has a 0? for example (0,4).
In your case, (0,4) is the y-intercept. Therefore, c=4. Still unsure? Plug it in! f(0)=ax^2+bx+c. Substitute every instance of x with 0. a(0^2)+b*0+c. What's left after this is c. Since f(0)=4 and f(0)=c, then c=4
Thank you. This is very helpful.
Helped me get an A thank you so much
Thank you very much this was very helpful
very well explained, thank you !!!!
thanks!!!!
THANK YOU SO MUCH OMG this helped me a lot you are a godsend!
Your welcome glad I could help. Let me know if you need anything specific.
It's the exact same answer if you do a quadratic regression, and it saves a lot of time! But I did enjoy learning this method!
Fantastic tutorial!!
Thanks!
Thank you so much I finally understand this!
Thank you! Very helpful
You're welcome
Hi sir I am from India tq u so much
You are welcome. Glad I could help from Eustis Nebraska
This is probably a stupid question but does it work with any three random points?
Actually that is an amazing question, and one I have had in the back of my mind, but never spent time exploring. It won't work with any three points because the three points have to form a parabola. So if you used (2,1) (2, 3) (5,7) for instance y = ax^2+bx+c would not work however I think x = ay^2 + by + c would work for those three points. You have me thinking. ... Great question. If you stacked three points it would not work in either case (2, 1) (2, 3,) (2, 4). would not work, or any three collinear points would not work. I don't have time right now to explore much more. But what if the three points lie on a circle? What about three points that lie on a hyperbola or trig function? ohhhh so much we could explore with this seemingly silly question. Good work getting my mind working!
@@danielschabenThanks
Wow Thanks that was quite a long steps to follow!
U r awesome
Thanks a lot 👍
This was so helpful!
How can I determine an equation of a line Wich passes through the point 4 ax-axis and 6 y-axis writing it in the form ax+by+c=0? I need help please?
publishing answer now
ua-cam.com/video/Zu2wo6oCU_E/v-deo.html
oh my thank you so much you saved my compression life
Glad I could help
thank you!
You're welcome
Good video! I’ve been lost on how to do this for a week now and my midterm is next week.
Any Javascript function or library that can do this for me.
Lots of them. Wolfram alpha 3 equation 3 unknown calculator is one I've used. Although when you get into linear algebra and start representing these with matrices there becomes many ways to do it with matrix capable calculators
you are the BEST! thank you for this!!!!!!
You're Welcome! Glad it was helpful.
ahhh i had hw and forgot how to do this 😭 tysm!
Your Welcome. Glad it was helpful
Very helpful
What if one of the points is a root-like (30,0) or the origin (0,0). Can I still plug them in?
Zergento Cheeze yes. That actually should simplify things
UA-cam should award me my PhD. It's a million times more efficient than learning in college.
Yes. Everything is here.
Omg so helpful, but your telling me it’s gonna take 14 minutes to do one problem....
in this method. Yes.
Him- *sigh* WOW
me: I FEEL YOU AHAHHAHAA
Thank you so much this helped a lot
Glad it helped!
I love watching different instructors/teachers/professors show the steps in working more complicated algebra topics but I wonder if too much time is spent on the basic arithmetic. If someone is learning algebra and doesn’t get eliminating or moving variables and constants in the solution process then maybe they should be watching basic math videos first. It really slows down the instruction. Just an observation.
I really only make these videos for my students. They will watch them mainly as more practice for those that need it. A way of studying for the test. I only threw them up here as a free place to store them back in 2010. Had no idea that anyone else would even find them valuable. Wish I had time to make more.
god bless you but what happens if I get numbers such as 0.55? Because your tutorial works bad at this case A (-2/22) B (1/7) C (3/2) and at the end, my results are a bit different than the 3 given points like if I use B I get 6.98 instead of 7 or 22,87 instead of 22
do you mean (-2,22) for point A, (1,7) for point B and (3,2) for point C?
@@danielschaben yes
I'll work on it. wish I had my video equipment right now
near as I can tell. havent checked my answer. but a = 0.5, b= -4.5, and c = 11. so the quadratic would be y = 0.5x^2 - 4.5x + 11
I can make a video in about 5 hours. in parent teachers conferences now. so trapped in meetings
soooo helpful.
Is this Gauss elimination?
It is only without the fancy matrices.
Yo i have test and now i have confidence that ima pass it
wait what if the value of a and b is one and you negate those two, it will be cancelled along with C, help?
I would have to see your problem. but if a=1 , b=1, and c =0. then the equation is y = x^2 + x
@@danielschaben like this,
Y=a(1) +b(1) +c
Y=a(1)+b(1)+c
If you negate all, well you cancel all
@@peep0le282 give me your three ordered pairs
@@peep0le282 you need to sub for y as well.
this will help m PSMT thanks pookie
You could've just divided the other equation by 3 so that the b would have no coefficients
Yes! He caught one shortcut, but not the second. He could have pounced at 5:15 Ugh! :-)
Thanks!!
Nice, looking back, the top equation could have been reduced by 3 to simplify even further.
godbless you
THANKYOU!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
YOURWELCOME!!!!!!!!!!!!
thank you so much
your welcome. let me know if there is another math video you might need
When you are a sixth grader and you have to do this again about 5 times for 5 different problems.
Screw advanced math :(
Consider yourself lucky. I've seen 30 year olds cry doing this stuff. If your a 6th grader and have a handle on it. I expect nothing less than you creating your own space company and the next mission to Europa (one of Jupiter's moons) :) Thanks for the comment and good luck. What starts out at drudgery could turn into the next thing that changes the world. You never know.
Oh lol, never thought of it that way, thank you, this has encouraged me to work harder.
When you’re a 9th and have to do 5 of these problems in 7 minutes
Thanks
Ok understand
there is so much room for error, im going to fail
It's a lot to remember, just remember that showing work helps. I hardly ever downgrade for silly errors. If your logic is sound, I am usually pretty happy.
searching4math meanwhile my math teacher gave me a D+ on my quiz because my answer came out positive instead of negative, and didn’t mention something that wasn’t asked in the question
@@arjunyeleshwarapu ya I'm sorry. It's so aggravating when you understand it and then minor errors hold us up.
does a always be 1
No. But often it is on highschool homework to make the problems easier
Yo dis nigga Andy Bernard
e
Too much damn work I’m just gonna fail.
Don't give up man! You can do it! If I can learn this anyone can!
Awful explanation for something rediculously easier
you realize this is so other people can fully learn the topic right? people who already know how to do it don't come here
this shit aint shit