Hi! Thanks for making these informative videos !! They really help. But I am getting stuck on one concept. How do we know when to use which centroid formula for a triangle ? Why didn't we use the 1/3 b for the centroid as opposed to the 2/3b? What is the main difference? Thanks for all your help.
Thanks, but yeah that was my bad. I didn't bother because at the time when I made this it was a just precursor to simple distributed loading problems wihh vertical loads in which the y bar is never needed, but it could be for sloped members or wind/pressure loading etc... So whoops sorry!
The center of area of a full circle is in "the middle." Just draw a semicircle by itself and try to locate the "middle." You wouldn't draw the middle touching an edge, it would be about where I have drawn it in this video. Make sense? circles and semicircles are different shapes.
The shape on the right is a semi circle. It is 3 units tall (see y axis). That means the diameter of the (would be full circle) semicircle is 3. Radius is 1/2 diameter, = 3/2 =1.5
The the centroid of a semicircle is 4r/3π away from the flat edge, and halfway between the top and bottom when it's oriented like this. y coordinate is therefore r away from both the top and the bottom
Yes whoops, I should have also demonstrated ybar. I didn't, because in most statics problems like this, you only need xbar, but ybar is the same, just swap all the x's for y's. so ybar=ΣyiAi/ΣAi
Thanks dude. Explained it better than the education I'm PAYING for.
UA-cam University FTW :)
wow same. I'm currently studying all the modules the night before my midterms. And I can say i learned a lot more than months worth at school
@@Engineer4Free hii
Jesus private highshools suck that bad?
@@Luka_c123 colleg ;(
This 9 minute video was better than the 3 hours worth of lectures in my statics class. Thank you!
Thanks bruh. You can check out all the free statics videos I made at engineer4free.com/statics cheers!
@@Engineer4Free understandable
Wow!! I was able to watch the proofs and examples in less time than one lecture. Thank U!!
Glad it was helpful!!! =)
First off I appreciate the audio and video quality, and thanks for making it so simple!
Hey thanks! I do try to keep it professional 👌👌
There is special place in heaven for such teachers....
Thanks Sohaib 🙌
A lovely little tutorial. Very well explained, good example used. Ten out of ten. Thank you.
Thanks a lot James =) =)
wow great explanation, i guess i can become an engineer on youtube instead of in school
hahaha basically... UA-cam University FTW
I think your website is great too, its real nice looking and really easy to use and follow, great job
Thanks! :)
well said
48 people DIDN’T find this helpful??? This is what will help me pass the test tomorrow.
Same here 😂
Hope it went well!!!
this is the best physics lesson i never had b4
You are literally a lifesaver, thank you so much!
Happy to help!! You can also see a few more videos on the topic here: engineer4free.com/statics see videos 58-65 =)
in 9th grade doing this it’s so stressful but you came in clutch
9th grade, wow! Thats a record I think.🤜🤛
9th grade? Bro where you going to school at? MIT high school?
your explanation is spot on
Thanks!! =)
Thankyou idol its Helpful clear explanation than my teacher
Happy to help =) the full playlist is here: engineer4fee.com/statics
@@Engineer4Free waoh thanks a lot idol👍🤞❤
So if (5.08, y) is the centroid, how can the y-coordinate be found? Love your videos by the way, they're saving my life this semester!
You can find the y coordinate by doing the exact same process, just switching every instance of "x" with "y"
the centroid of semi circle is 0.63 so the x3 will be 2+6+0.63=8.63
This was a ton of help! Thank you!
Cheers dude, glad to hear it!
Now I am your scriber dude...
Love from india thank-you
Glad to have you Raja! Tell some friends 🙂🙂
Another great video thank you!
Thanks Luis!! 🙂
what I want to know is when do I use 2/3 or 1/3 for triangles
the centroid is 1/3 of the way from the tall side, and 2/3 of the way from the short side, for right angle triangles in this orientation
@@Engineer4Free Alright thank you
Hi! Thanks for making these informative videos !! They really help. But I am getting stuck on one concept. How do we know when to use which centroid formula for a triangle ? Why didn't we use the 1/3 b for the centroid as opposed to the 2/3b? What is the main difference?
Thanks for all your help.
the smaller side I believe you use the 1/3 and the bigger one you use 2/3 when you divide the triangle from the middle
Jahh ✌️
i Came .. i Saw .. i Subscribed ! 😇
Awesome, thanks Sharad!!! =)
thanks man you've helped clarify things
great explanation, but it would have been better if you do the y bar as well.
Thanks, but yeah that was my bad. I didn't bother because at the time when I made this it was a just precursor to simple distributed loading problems wihh vertical loads in which the y bar is never needed, but it could be for sloped members or wind/pressure loading etc... So whoops sorry!
The dislikes are from all the teachers and professors who are obsolete because of you
😂 maybeee
Could you please upload y-axis video as well. Thanks
Hello. I have a question. about to find the x bar for triangle. Im confused wether to use 1/3 or 2/3 . TQ
The centroid is 1/3 of the way away from the tall side, and 2/3 of the way away from the short side 😊
hye if the triangle is upside down. for y bar i need to use 2(b)/3 again? because it will start from the shortest one?
If the triangle was flipped vertically, the short side would still be on the left, so the calculation would be the same.
@@Engineer4Free thank u so much
Small advice on u is dat the colour that u are using is not well visible how about to use black or red colour?
Hey yeah, I made this video quite a long time ago, and have since tried to make the pen stokes more visible. Thanks for the feedback!!
i have a question bro if i want to get the y-bar is it just y-bar=sum(YiAi)/sum(A
)
yeah
Sir, when will xbar or ybar for the centroid of a shape be equal to zero?
X bar will be zero if the centroid lays on the y axis. Y bar will be zero if the centroid lays on the x axis.
Thank you Sir :)
sir can you do a video on getting y bar?
Who's bad professor is the reason they are here in 2021!? XD
Me 😂
Is the y(bar) the sam method except using y values?
Yeah, sorry in hindsight I should have also calculated it in this example. See videos 58 and 59 here: engineer4free.com/statics for more info ✌️
Probably late but is the Ybar equal to 0.1630?
Which software is it that you use to make this video? It looks really nice
Hey thanks, I have a full list of software and hardware that I use at engineer4free.com/tools check it out!
My teacher “taught” me this in 90 minutes when she could have done it in 9!
😏
Why isn't the x of the semi circle 0 here?
The center of area of a full circle is in "the middle." Just draw a semicircle by itself and try to locate the "middle." You wouldn't draw the middle touching an edge, it would be about where I have drawn it in this video. Make sense? circles and semicircles are different shapes.
8 units away form the origin??? so thats start from zero Right??
Yea
that was useful .. thank you Mr.
Thanks for watching and letting me know :)
Great video but so disappointed u didn't do y bar😢
Why is it the x component of the triangle is 2(b)/3?
because hes taking all the measurements from the origin of the graph. the component is 2/3rds from the origin or 1/3 from the nearest side.
Yeah thanks for being a bro Kody.
Woahh thanks this helped me a lot in my statics exam. 😁
Glad to hear it!!!
absolutely lit fam
Very very Tqq Sir...❤🎉🎉❤❤
I don't get where you found ??1.5??
The shape on the right is a semi circle. It is 3 units tall (see y axis). That means the diameter of the (would be full circle) semicircle is 3. Radius is 1/2 diameter, = 3/2 =1.5
What will be the y coordinate of the Center of mass of semicircle
The the centroid of a semicircle is 4r/3π away from the flat edge, and halfway between the top and bottom when it's oriented like this. y coordinate is therefore r away from both the top and the bottom
greatttttt thanx MR this is helpful
Awesomeee thanks for the comment!
So for y I have to use 1/3 ??
Yeah, for the triangular section, it ybar is 1/3 of the way up the triangle vs height, from y=0
What about for y?
Yes whoops, I should have also demonstrated ybar. I didn't, because in most statics problems like this, you only need xbar, but ybar is the same, just swap all the x's for y's. so ybar=ΣyiAi/ΣAi
What about the y for the triangle?
for a triangle in this orientation, centroid is 1/3 base away from the bottom right corner, and 1/3 height away from the bottom right corner.
10/10
does any one did, the (y) i have 1.44
Yup that is correct!
salim nour Haa sxp
Sir pls ask in hindi
You're not that audible though
Is the sector of a circle is 2/3 r sinƁ/Ɓ