14.1 Introduction to IR Spectroscopy | Organic Chemistry

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  • Опубліковано 3 гру 2024

КОМЕНТАРІ • 10

  • @AnnaDesMarais
    @AnnaDesMarais 9 місяців тому +6

    Chad, I just wanted to let you know, that I love you. You're my saving grace.

    • @ChadsPrep
      @ChadsPrep  9 місяців тому

      I'm happy to hear that I'm helping you!

  • @yashtrivedi2671
    @yashtrivedi2671 3 роки тому +11

    Incredible explanation, thank you

    • @ChadsPrep
      @ChadsPrep  3 роки тому

      You're very welcome Yash! I'm actually working on re-filming the replacement for this lesson today. Any suggestions?

    • @yashtrivedi2671
      @yashtrivedi2671 3 роки тому

      @@ChadsPrep I think this is a great video so I do not believe much more needs to be added. But maybe another video (in addition to the one you already have) on practice problems could be helpful!

    • @ChadsPrep
      @ChadsPrep  3 роки тому

      My premium course on chadsprep.com currently includes 800 practice questions (I'm steadily adding more) including 15 IR questions fyi!

  • @mup1537
    @mup1537 3 роки тому +5

    Man it's just kind of amazing how different your ranges are from my text book. They're obviously quite similar but sometimes different by 100 cm-1

  • @26d8
    @26d8 4 роки тому +4

    thank you so much, why the cis alkene has changed in dipole moment but trans alkene doesn't? arent both symmetric?

    • @ChadsPrep
      @ChadsPrep  4 роки тому +3

      Dipole moment = (partial charge)(distance of separation)
      The trans isomer is nonpolar and has a zero dipole moment (sp2 C-H bonds oriented 180 degrees apart). This means there are no partial charges. So whether we stretch the bond or not there is no dipole moment when you plug in zero for the partial charge in the above expression. To absorb IR radiation there has to be a change in the dipole moment which isn't the case here.
      But the cis isomer while symmetrical in one plane still has a small dipole moment as the sp2 C-H bonds are only oriented 60 degrees apart. With a non-zero dipole moment it will have a partial charge in the equation for the dipole moment and so stretching the bond will change the dipole moment and thus we can expect an IR absorption.
      This would have been far easier to explain in person but hope this helps!

    • @26d8
      @26d8 4 роки тому +1

      @@ChadsPrep thanks alot for your response, that sure helped me alot.