Mathematically if u wanna see then impulse of mg is mg ∆t and ∆t is very small for collisions like in the order of ms. So let's take an example of simply dropping a ball of 1kg from a height of 5m taking g as 10 velocity of impact is 10m/s. Say collision is elastic so rebound velocity is also 10m/s. ∆p is 20Ns. Let's take ∆t for collision as 1ms so the average upward force on the ball is ∆p/∆t which is 20000N. Which is 2000 times greater than the weight of the ball. Thats why we can neglect Fg in comparison to the normal force during the duration of collision.
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very cool, you explained them in the best way
Definition of consistency 😊😊😊
sir please bring some electromagnetism questions too
sir some do good mixed problems in electrodynamics also request
Bhaiya I wanted to practice waves portion so if you can bring some questions of waves in the next video it will be grateful ❤ thanks for efforts.
Pls bring nixed problem from all chaoter
Is normal torque bigger and not neglected due to it being equal to centripetal acceln component of rod
irodov ques 1.248 solution please
dc pandey sir have completed whole solutions
@@Professor69z i know but i love the way he explains
Bhaiya it’s almost nov plz bring q on electrodynamics now
Nice
in 2nd problem, how do we ignore impulse of gravity, do we do in all prblms, or theres some different case
Mathematically if u wanna see then impulse of mg is mg ∆t and ∆t is very small for collisions like in the order of ms.
So let's take an example of simply dropping a ball of 1kg from a height of 5m taking g as 10 velocity of impact is 10m/s. Say collision is elastic so rebound velocity is also 10m/s.
∆p is 20Ns. Let's take ∆t for collision as 1ms so the average upward force on the ball is ∆p/∆t which is 20000N. Which is 2000 times greater than the weight of the ball. Thats why we can neglect Fg in comparison to the normal force during the duration of collision.
@@Phyx_IITMthanks.. hands down best explanation 🙏
W
Bhai 12th ke q bhi leaao