I have a question. In the case of the pn junction, when reverse bias was applied, the Fermi level remained in the neutral region. But why is Vsb added to the bottom right diagram energy band?
@@sankarrao1100 I have a question. In the case of the pn junction, when reverse bias was applied, the Fermi level remained in the neutral region. But why is Vsb added to the bottom right diagram energy band?
We need more knowledgeable teachers like you sir!
Finally someone who understood that observing energy levels are crucial fot understanding the body effect :) thumps up
yeah, many people explain it using electron and holes being attracted to body terminal and this that and end up contradicting themselves.
I love your voice and the way you explain things
Wonderful in preparing for the interview
Excellent clarity in concept!
Thank you for this valuable lecture
excellently explaining but could not understood it
THANK YOU BRO............
Sir... why didn't you add Vsb with another 2 fi f (fermi potential)?
thank you, it's helpful!
I have a question.
In the case of the pn junction, when reverse bias was applied, the Fermi level remained in the neutral region. But why is Vsb added to the bottom right diagram energy band?
Why do holes accumulate in the neutral region of the p-type?
Thankyou sir
Thank you very much sir 🙏
Thanks sir ji
Tq sir
At 7:47 of the video, when there is a voltage difference between S and B (the bottom right diagram) , shouldn't the fermi level of S and B differ?
No, because there is no current from source to body via MOSFET, no current implies no shift in Fermi level
@@sankarrao1100 I have a question.
In the case of the pn junction, when reverse bias was applied, the Fermi level remained in the neutral region. But why is Vsb added to the bottom right diagram energy band?
Ei means like
intrinsic energy level