Transformation Matrices Part 3

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  • Опубліковано 16 лис 2024

КОМЕНТАРІ • 15

  • @rbaleksandar
    @rbaleksandar 12 років тому +10

    On the homogeneous transformation slide you forgot to mention the following:
    - the three zeros at the bottom represent the perspective transformation vector, which in this case is (0 0 0)t, since there is no such transformation.
    - the 1 in the lower right corner below the translation vector (last column in the matrix) is actually representing the scaling factor. It equals 1, since there is no scaling in our case

  • @batuhany34
    @batuhany34 12 років тому +1

    You are a great person, sir. Thank you.

  • @rbmnewton
    @rbmnewton 6 років тому

    Hi milford, thanks for the videos . Am currently looking to develop a Quadraped with Creep gait. I have no prior experience on Inverse Kinematics. These videos were helpful in getting started :-)....

    • @CrisMadla
      @CrisMadla 5 років тому

      Mageshwaran R B same here!

  • @terencecarmichaeljr2985
    @terencecarmichaeljr2985 9 років тому +1

    Very helpful. Thank you.

  • @uditsaxena3844
    @uditsaxena3844 3 роки тому

    thanks sir

  • @rbaleksandar
    @rbaleksandar 11 років тому

    Hom.transf.matrices are applied in various fields such as computer graphics and digital image processing. In robotics this doesn't make sense (how would you scale a link or a joint in the real world? :D) but in those two it is often used. For more information see the wikipedia article titled Scaling_(geometry)#Using_homogeneous_coordinates . Note that this scaling factor can only then be used, when you scale in all three dimensions (uniform scaling). Otherwise you use the usual scaling matrix.

  • @SoumilShah
    @SoumilShah 5 років тому

    it helped me. thanks a lot for videos

  • @gleniosp
    @gleniosp 11 років тому

    Excellent! Thank you!

  • @saravanana5419
    @saravanana5419 4 роки тому

    Very helpful. Could u please explain what is the need to alter the position of the displacement values in the translation matrix? Currently i am facing an issue. I am using current frame method and the translation values are given as Z,X,Y instead of XYZ. Thanks

  • @AlanDias17
    @AlanDias17 10 років тому +1

    It helped me, thanks.

  • @yousafkhan7909
    @yousafkhan7909 6 років тому

    very good, thank you sir

  • @Gamer_2047_
    @Gamer_2047_ 7 років тому

    nice content thanks

  • @aXque
    @aXque 11 років тому

    Can someone help me, I have an exam coming up and I can't understand this transformation matrix.
    -2 0 0 a
    0 1 0 b
    0 0 -2 c
    0 0 0 1
    It's not a pure translation, what is this? What does it do?