Sorry to be so offtopic but does anyone know of a method to get back into an instagram account? I stupidly forgot the login password. I would love any help you can offer me
"Now, solving the equation with those values we get... Oh... LOOK!" Seriously, though, sweet illustration of pitot tube. Wish I had this for my Engineering Measurements class.
Really awesome concept thanks for uploading this video I wish this type of animation video if teachers teach like this in schools than it will be helpful for students and students imagination power will aslo be increased and this type of teachings can aslo helps students for further resarch in specific subject in future
thank you so so so much! I really love it! Awesome intuitive presentation which will clear the concepts of thousands of students❤❤. We want more videos like these.
fluid mechanics by itachi. my dream has come true. i had quick question, if say we have 6 pitot tubes in a large tube, can we use the velocity distribution on the pitot tubes, to calculate volumetric flow rate of the large tube? if so, how does one do this or how does one find a relationship between velocity going in the pitot tube to the pitot position distance. thanks once again itachi
If the Flow is in-compressible, steady, streamline (idle) then of course you can use Pitot tube to calculate velocity, using the derived equation. To get velocity, Just identify the pressure (use pressure gauge) at different point and use in the equn of pitot tube (to get velocity). Then you can use use Poiseuille's law to predict the volume flow rate of water through this large pipe. But in real life that's impossible, Turbulence is almost always a factor in larger pipes, as is friction caused by the interaction of the fluid with the pipe walls. So to calculate Volume flow rate and and average velocity, you need other parameter like Pipe Diameter, length, friction factor,pipe roughness etc.. Pipe are always designed, in accordance with the flow rate and pressure that it can handle.
@@NiLTime Thank you very much for your detailed answer. i have a follow up question. In the beginning of the video, you had connected 2 piezometer tubes. I am unsure on how the pressure in both the tubes are the same. Is it because of constant fluid velocity along the larger pipe? What if the velocity is different, would this differ the static pressures obtains in the two peizometer tubes? Also is there a video on your channel explaining the fundamentals of the peizometer tube? Thank you once again and i appreciate you taking the time to make such amazing videos^.^ PS- this is an edit. i found the piezometer head loss video on your channel. That explained my question above^. Thx. i am still a bit confused as to how would one find the total pressure at a peizometer tube, given the initial velocity at the inlet of the large pipe and the distance from the inlet the the pipe. Is there an equation that could do this or do we have to manually put a pitot tube directly below the peizometer in order to measure velocity and thus find the total pressure at that tap? I am considering a large pipe where there are 10 static taps with different heads and the flow is not steady that is two streams of unequal velocity are mixing together and since there is a pressure drop, will we have to keep a peizometer at each static tap in order to measure the velocity at that point or can we find velocity from the distance and initial velocities of the two streams.
@@emilymaze6616 In this video, Static pressure in both piezometer are same because the fluid is ideal and also have constant velocity. Increasing Velocity decreases static pressure and vice versa. If you consider friction then of course static pressure and dynamic pressure would decrease along the length of pipe. For the next part, with piezometer you can only get static pressure, not total pressure. For total pressure use pitot tube. You can calculate local velocity at different point using combination of piezometer and a pitot tube. Pitot gives total pressure. Piezometer gives static pressure. subtract them to get velocity. You can also use "Pitot-Static" tube. It is more precise and donot require piezometer. Hope that helps and enjoy reading ^^ .
V2=0 because at that point speed of water particles decreases due to high pressure as a result it creates what we call stagnant pressure which is the sum of dynamic and static pressure
Mam if static pressure are same at both point then how water flow from 1to2 because i study water flow from high pressure to low pressure it my dout please solve
I have a question, in case tube measuring static pressure, the fluid level increase by its motion, using kinetic energy and come to stop, so why it not measure as total pressure?
@@NiLTime thank you but i dont quite understand… i understand what happen when the fluid is dynamic but i was trying to imagine what would happen if the fluid were static (i was asked that question in an exercice..) my thought were that if the dynamic pressure is experiencing in tube 2, in static condition tube 2 will experience drop pressure and the fluid level in the tube will drop too, but will it be the same level as tube 1 or there will be a différent level in both tube ? (I’m really sorry for my english, i hope what i’m saying is still understandable..)
@@emmadenisi1606 yeah. If fluid were static, both tube would have same pressure. In this case same static pressure. Watch this video. ua-cam.com/video/2-jl2jObj4E/v-deo.html
when water enter it's head .. it gets trapped and couldn't get out so they remains static... which means zero velocity. Please watch this video ua-cam.com/video/CxqM_kkwgU4/v-deo.html
Because the pitot tube is fixed at a point (which means it is not moving) So, when moving fluid collides with the pitots head the velocity is completely reduced to zero. Just imagine pitot tube as big rock fixed at a point which can stops fluid completely when they strike its surface and hence can experience stagnation pressure of moving fluid. Still confused watch this ua-cam.com/video/CxqM_kkwgU4/v-deo.html ...
When she said "Oh Look", I felt that
Felt what?
@@kwenheejo9008 Lmaooooooooooooooooooooooooooooo
@@kwenheejo9008 A little wired, is it?
@@李冀维 yeah, still don't get it
Sorry to be so offtopic but does anyone know of a method to get back into an instagram account?
I stupidly forgot the login password. I would love any help you can offer me
"Now, solving the equation with those values we get... Oh... LOOK!"
Seriously, though, sweet illustration of pitot tube. Wish I had this for my Engineering Measurements class.
Thank you Falprofessional ^^ ..
@@NiLTime Lowe you
I wish anyone loved me as much as she loved solving for the stagnation pressure XD
Yeh she do haha
"Look!!" 😲
You are a lifesaver! Thank you so much for this video. Extremely helpful haha! Also when she said "Oh, look!" Ahahaha that was so cute xD
I was so confused about this topic, You've cleared everything up thank so much
Oh this is just perfect. Thanks for posting.
Wlc bro :)
Really awesome concept thanks for uploading this video I wish this type of animation video if teachers teach like this in schools than it will be helpful for students and students imagination power will aslo be increased and this type of teachings can aslo helps students for further resarch in specific subject in future
ofcourse, I agree with you ^^
I didn't understand exact concept while studying in book but now I got it .Thank you 🥺
Aww .. good to hear ^^
Thanks. The explanation was just perfect.
OMG ! You explain more clear than my teacher .
Amazing it's clear my concept please more animation add for fluid mechanics it helps us
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Finally understood it. Thank you so much
u made it soo simple to undetstand ,thanks on brhalf of the whole engineering community
ua-cam.com/video/KZNMYV23sj4/v-deo.html
.
..
thank you so so so much! I really love it! Awesome intuitive presentation which will clear the concepts of thousands of students❤❤. We want more videos like these.
Great..love from Bangladesh ❤️
this is just what i was looking for, thank youu!
Wavoo.. What a great video.. Nice explanation.. Thank u
Wow your animation is osm
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Keep up the excellent work. Look what you have done. Thanks
fluid mechanics by itachi. my dream has come true. i had quick question, if say we have 6 pitot tubes in a large tube, can we use the velocity distribution on the pitot tubes, to calculate volumetric flow rate of the large tube? if so, how does one do this or how does one find a relationship between velocity going in the pitot tube to the pitot position distance. thanks once again itachi
If the Flow is in-compressible, steady, streamline (idle) then of course you can use Pitot tube to calculate velocity, using the derived equation. To get velocity, Just identify the pressure (use pressure gauge) at different point and use in the equn of pitot tube (to get velocity). Then you can use use Poiseuille's law to predict the volume flow rate of water through this large pipe. But in real life that's impossible, Turbulence is almost always a factor in larger pipes, as is friction caused by the interaction of the fluid with the pipe walls. So to calculate Volume flow rate and and average velocity, you need other parameter like Pipe Diameter, length, friction factor,pipe roughness etc.. Pipe are always designed, in accordance with the flow rate and pressure that it can handle.
@@NiLTime Thank you very much for your detailed answer. i have a follow up question. In the beginning of the video, you had connected 2 piezometer tubes. I am unsure on how the pressure in both the tubes are the same. Is it because of constant fluid velocity along the larger pipe? What if the velocity is different, would this differ the static pressures obtains in the two peizometer tubes? Also is there a video on your channel explaining the fundamentals of the peizometer tube? Thank you once again and i appreciate you taking the time to make such amazing videos^.^
PS- this is an edit. i found the piezometer head loss video on your channel. That explained my question above^. Thx. i am still a bit confused as to how would one find the total pressure at a peizometer tube, given the initial velocity at the inlet of the large pipe and the distance from the inlet the the pipe. Is there an equation that could do this or do we have to manually put a pitot tube directly below the peizometer in order to measure velocity and thus find the total pressure at that tap? I am considering a large pipe where there are 10 static taps with different heads and the flow is not steady that is two streams of unequal velocity are mixing together and since there is a pressure drop, will we have to keep a peizometer at each static tap in order to measure the velocity at that point or can we find velocity from the distance and initial velocities of the two streams.
@@emilymaze6616 In this video, Static pressure in both piezometer are same because the fluid is ideal and also have constant velocity. Increasing Velocity decreases static pressure and vice versa. If you consider friction then of course static pressure and dynamic pressure would decrease along the length of pipe.
For the next part, with piezometer you can only get static pressure, not total pressure. For total pressure use pitot tube. You can calculate local velocity at different point using combination of piezometer and a pitot tube. Pitot gives total pressure. Piezometer gives static pressure. subtract them to get velocity. You can also use "Pitot-Static" tube. It is more precise and donot require piezometer. Hope that helps and enjoy reading ^^ .
Thank you lady or mr whoever has created this video❤️
ua-cam.com/video/KZNMYV23sj4/v-deo.html
This is amazing!!
Thank you so much. Great explanation!
Finally understand what dynamic pressure is
I can not understand your language fully but your animation is sufficient for me to understand this function
ua-cam.com/video/KZNMYV23sj4/v-deo.html
this explanation is a masterpiece
Thank you, this is VERY helpful
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Thank you itachi
انت بتجيب الأدوار دي منين روعة❤❤
Good and Helpful Tutorial. Thank you.
Damn good explanation ever! expecting more videos from you❤️
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Ooh look is great 😂😊😊😊
Awesome 👍 animation, explanation and whole presentation.
the great way of explaining...thank you
Welcome friend ^^
Keep doing such work it is very helpful...
ua-cam.com/video/KZNMYV23sj4/v-deo.html
It's good, but could have been much better if the concept of zero velocity at the entrance of pitot tube have been explained in detailed.
watch this then you will understand ua-cam.com/video/CxqM_kkwgU4/v-deo.html :)
@@NiLTime thanx, I'll definitely see it
Nice
You are nailing it
Very helpful and creepy video!
Nice
Very good Explaination
Keep watching ^^
2:04 ♥️ I felt that.. Oh look
ua-cam.com/video/KZNMYV23sj4/v-deo.html
What is 'datum' height at 1:54? And z1 and z2
amazing explanation. thanks
Anyone knows why v2 is zero at the head of pitot tube is zero 1:50 ???
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Stagnation point
Nicely explained
ua-cam.com/video/KZNMYV23sj4/v-deo.html
How do you calculate for the static pressure? ro*g*h?
excellent explanation
very nice explanation
Can we use the top of fluid level in pitot tube as a reference point instead of point 2
Good question
Excellent content and clear explanation for a video voiced by a bot!
Haha Thankyou ^^
Intelligence girl... Thanks... 🇧🇩♥️
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Thank you for this channel!
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Nice video❤
Wow what a wonderful explanation 🔥🔥🔥🔥
Thank you so much ^^
Great way to explain an important principle.
ua-cam.com/video/KZNMYV23sj4/v-deo.html
.
Ek number
can someone explain why V2=0, fluid at point 2 is moving right? still cant understand the logic
V2=0 because at that point speed of water particles decreases due to high pressure as a result it creates what we call stagnant pressure which is the sum of dynamic and static pressure
Wonderful ❤️💜💙💚💛🧡
It's really more than my expectation
aww ... Thankyou ^^
Great 😍👍
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Great
Mam if static pressure are same at both point then how water flow from 1to2 because i study water flow from high pressure to low pressure it my dout please solve
exactly. Thanks.
Oh... Look... I subscribed
nice channel
very helpful video, thank you
Glad to hear ^^...
Static pressure from piezometer is calculated the( height of the piezometer till filled water)+ (hydrostatic pressure head)
Am I right?
I have a question, in case tube measuring static pressure, the fluid level increase by its motion, using kinetic energy and come to stop, so why it not measure as total pressure?
Amazing, thank you
Thanks, very nice explanation
Glad it was helpful! ^^
Madam..Thank you. I will use this video for my lecture.
ofcourse go ahead ^^
Good explanation
One question, how about turn the pitot tube 180 deg? Tube pressure will become low, then P2=P(stag) - P(dyanmic)?
Excellent video
I applied your teaching to do my assignment and I want some sort reference at the end of the work I did.?
Please help me out
Like a textbook or something I can look from
it's very helpful. Thank you!
Wlc
knsa mga taga cit diri? shawtout kang EC!
Why velocity at stagnation point is 0 !?
This is great video but i dont understand somewhere which is V2 why is zero?
Hey consider watching this : ua-cam.com/video/CxqM_kkwgU4/v-deo.html ^^
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Please tell me what program did you use to do this animation video
Blender app .. XD
Awsome animation
Thanks ^^
When she said “V” when doing the calculations it was like when you say a nickname for someone with a name beginning with V
Plz upload video on working of siphon tube!
ua-cam.com/video/KZNMYV23sj4/v-deo.html
If the fluid stops, does it mean tube 2 will become similar as tube 1 ? Thank you
No. Tube 2 (pitot) will experience greater pressure than tube one. This greater pressure is dynamic pressure. Static pressure is similar on both tube.
@@NiLTime thank you but i dont quite understand… i understand what happen when the fluid is dynamic but i was trying to imagine what would happen if the fluid were static (i was asked that question in an exercice..) my thought were that if the dynamic pressure is experiencing in tube 2, in static condition tube 2 will experience drop pressure and the fluid level in the tube will drop too, but will it be the same level as tube 1 or there will be a différent level in both tube ? (I’m really sorry for my english, i hope what i’m saying is still understandable..)
@@emmadenisi1606 yeah. If fluid were static, both tube would have same pressure. In this case same static pressure. Watch this video. ua-cam.com/video/2-jl2jObj4E/v-deo.html
Need more topics from you
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Why V2 = 0 ??
What happens to the formula if the medium IS compressible? Is there a negative multiplier?
ua-cam.com/video/KZNMYV23sj4/v-deo.html
.
Good , thanks
uhm. sorry for the noob question, but what was the name of the first tube that measures static pressure? cant find it anywhere. im new to this btw
It's called "Piezometer". ^^
@@NiLTime thanks. ♥️
Is the piezometric tube similar to pressure gauge? Do both measure static pressure?
really good
Thank you ^^
why velocity at the entry of the tube V2 is equal to 0 ???
when water enter it's head .. it gets trapped and couldn't get out so they remains static... which means zero velocity. Please watch this video ua-cam.com/video/CxqM_kkwgU4/v-deo.html
Perfect
ua-cam.com/video/KZNMYV23sj4/v-deo.html
Hi , why is the velocity at pt 1 = 0 ?
hey it's not point 1 ,its point 2. It's because the water velocity completely stops at point 2.
2:04 I lost it lmao
why the velocity in point 2 is zero
watch this video ua-cam.com/video/CxqM_kkwgU4/v-deo.html :)
Thank you
wlc dear ^^
when i see tough concepts: _AMATERASU_
That would burn everything haha ...
Hey peeps
Wasn’t the “hey look” similar to Barbie life in the dream house !
Pilots-- Dynamic Pressure= Impact Pressure-Static Pressure
thank you!
mantop from dtp2b
can anybody tell me why velocity of point 2 is zero? bb
Because the pitot tube is fixed at a point (which means it is not moving) So, when moving fluid collides with the pitots head the velocity is completely reduced to zero.
Just imagine pitot tube as big rock fixed at a point which can stops fluid completely when they strike its surface and hence can experience stagnation pressure of moving fluid. Still confused watch this ua-cam.com/video/CxqM_kkwgU4/v-deo.html ...