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A1 - Converting Factored Form to Vertex Form
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- Опубліковано 5 кві 2020
- Part 4 of 6
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There's a mistake in the video.
f(8) = -4
So in vertex form it should be minus 4 at the end instead of plus 4.
And the vertex is (8, -4)
Everything else and all the explanations are still right.
Yeah I was going to say that didn’t make sense, thank you for saying that though, I thought I was going crazy
I thought i was dellusional when i saw that :p
You are a literal saint
For those confused about 4 or -4 in f(8) = (8 - 10) (8 - 6)... yes, he corrected it (should be minus 4) down in the comments. This way hopefully, you don't have to scoll down too far! :) Great job... and thank you!
phew thx
Wow! This is so much easier than what my math teacher taught me. Thanks so much for sharing!
give me a kiss
Remember you help people more then you think, keep up the good work👍
Thank you so much!!! I'm a math major that couldn't understand this simple concept and you helped so many things click!
this helperd me a lot in my test LOL thank you so much dude
when you do f(8) and simplify, how is -2•2 positive 4? Shouldn’t it be -4?
Also thank you, this helps me out a lot.
Yes, it's supposed to be -4. I put the factored form into desmos and it was translated down 4. so the Vertex form for that equation is y = (x - 8)^2 -4
yes it should've said -4. I'll put a screen up at that moment
@@rademakermath2748 what happens if your h ends up as 0? Do you write it as x - 0 or x + 0? And also, what happens if your a is 0? Is there a specific way to write it or do you just write 0?
@@exmachina8475 if h is zero and you want to keep it in the vertex form style then you would do (x - 0) or just x.
'a' can't be zero. If it is, it won't be a quadratic anymore
You might mean "what if 'a' doesn't have a value written?". If there is no number where 'a' usually is, that means a = 1.
@@rademakermath2748 Okay, thank you!
thank you sooooo much!!!! you just saved me from a breakdown!!
this helped me more than 4 classes with my math teacher
Thanks for helping me at 9 pm before my math test tomorrow lol
Doing my math hmwk in second period. This video saved me
Real
Thank you so much! I have this bookmarked on my computer now!! :)
So, does that mean that the vertex for y=-2(x+6)^2+288 would be (-6, -288)? Also when writing the vertex for any question, do you change the signs for both the numbers cuz in some of your videos I watched, you only changed one of the numbers signs.
It would be (-6, 288). Only the x value of the vertex gets flipped in the equation.
@@rademakermath2748 thank you!
Uhm Hi! May i ask if its a standard to divide x ints by two to find the aos
what an absolute G
Thank you!!!!!
Thanks alot
The part where u calculate the Aos..will have to be always add then divide it to 2?
Yes. Because the Axis of Symmetry will always be halfway between the x-intercepts.
shouldn’t the four be a negative since it’s negative two times two?
yes, it was written wrong. It should be -4.
Sir where you do live
How did you get 288?
Since the axis of symmetry is -6, that is also the x-coordinate of the vertex, so you need to plug that back into the original equation for x to find the y-coordinate of the vertex.
this cleared up so much for me wow
I'm glad it helped. Good luck with your class!
I thought it would be -4 instead of 4 since its -2(2)
yes. that was pointed out a few months ago. it should be -4.
@@rademakermath2748 ok thank you I was so confused
im so confused what is f(x)???? is it just y? so instead of doing f(x)= its y=????
f(x) is the output when x is inputted. So yes, f(x) is the same as y.
@@rademakermath2748 thank u so much u deserve more recognition
his voice is sexy he could teach me any day😉
-2 x 2 is -4. Not 4 bro
yep, that correction is in the pinned comment bro.
@@rademakermath2748 your replying to comments but your not posting anymore. I like your content man, why are you not posting anymore?😥