Significant Figures in Mixed Operations

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  • Опубліковано 22 жов 2024

КОМЕНТАРІ • 39

  • @guitardunce7571
    @guitardunce7571 2 роки тому +4

    Excellently explained and clarified. I'm doing a subject at the moment where this is getting introduced, and the lecturer consistently fails to explain with examples as to how these rules are applied. Really good work.

    • @ChemHelpASAP
      @ChemHelpASAP  2 роки тому +1

      Sig figs seem so simple, but they can be very tough when put into practice. I am glad this helped!

  • @biancabrown7279
    @biancabrown7279 Місяць тому +3

    I love you random lady I found for chemistry... I will be sticking around and watching any ads all the way.

  • @francescadavis3913
    @francescadavis3913 Рік тому +2

    Thank you! Reviewing how to do significant figures in mixed operations and this clarified completely!

    • @ChemHelpASAP
      @ChemHelpASAP  Рік тому

      Fantastic! I am so glad you found it helpful!

  • @dhillondhesi7289
    @dhillondhesi7289 2 роки тому +2

    Amazing lady, thank you for being a competent teacher!!!!

    • @ChemHelpASAP
      @ChemHelpASAP  2 роки тому +1

      I am glad it helped! Sig figs are tough; it takes time and practice to really figure them out.

  • @kelpiedreams
    @kelpiedreams Місяць тому +1

    Thank you for making this video! Would you say it's accurate to just apply the lowest number of SF and/or DOP to your answer from all the steps in the calculation then, for example if in a multi-operation problem I had a lowest SF limit of O in step 2 then it would carry all the way through to the answer?

    • @ChemHelpASAP
      @ChemHelpASAP  Місяць тому

      It depends on the calculation. Some mixed operations end up being limited by the multiplication/division part of the calculation, while others are limited by the addition/subtraction piece. Unfortunately, there isn't one rule you can apply to mixed operations, which is why they are the most difficult for sig figs!

  • @comamiday462
    @comamiday462 Рік тому +2

    good afternoon, I have a question... 4.2500/24.02 is 0.1769358868 but your round off and the same with 51.67/30.90 that is 1.328277635...and the final result will be 1.505213522, is that okay?

    • @ChemHelpASAP
      @ChemHelpASAP  Рік тому

      I am not sure I fully understand your question. Are you asking if it is ok that your calculator gave you more decimal places than my calculator? If that is the case, I would say it doesn't matter because you still need to round to the third decimal place in the final answer. So I can write as many decimal places as I would like before rounding, but once I round to the correct number of sig figs, I am always going to round to the third decimal place which will give the same answer.
      If you want to see more examples of sig figs in mixed operations, you can check them out here: ua-cam.com/video/B6LrWnWFTj8/v-deo.html

  • @rickygelabert6558
    @rickygelabert6558 Рік тому +1

    Superb video, it helps me to remember all the rules perfectly. Thanks a lot

    • @ChemHelpASAP
      @ChemHelpASAP  Рік тому

      I am so glad you found it helpful! It is tough to keep all the rules straight in mixed operations.

  • @ArunGeorge20
    @ArunGeorge20 2 місяці тому

    Excellent video.

  • @benw8416
    @benw8416 2 роки тому

    i love you, first week of chem and this help me alot

    • @ChemHelpASAP
      @ChemHelpASAP  2 роки тому

      I am so glad you found it helpful! Please let me know what other topics you would like to see. If you want more sig fig work, I just did a live stream with more examples. I am here for you!

  • @nimratk2196
    @nimratk2196 3 роки тому

    Thank you so much!!! This made it so much easier!!

    • @ChemHelpASAP
      @ChemHelpASAP  3 роки тому

      Wonderful! I am so glad it helped!

  • @Youngballer739
    @Youngballer739 2 роки тому +1

    Thanks makes sense now

    • @ChemHelpASAP
      @ChemHelpASAP  2 роки тому

      I am so glad it helped clarify! I also have another sig fig in mixed operations video if you want to see more examples.
      ua-cam.com/video/B6LrWnWFTj8/v-deo.html

  • @sbarb65
    @sbarb65 2 роки тому +1

    This is amazing thank you so much!

    • @ChemHelpASAP
      @ChemHelpASAP  2 роки тому

      You are very welcome! Glad it helped!

  • @deliveringIdeas
    @deliveringIdeas 3 роки тому +1

    Thank you ma'm.

    • @ChemHelpASAP
      @ChemHelpASAP  3 роки тому

      You are welcome! Thanks for watching.

  • @Maria-kq4bv
    @Maria-kq4bv 3 роки тому +1

    Thank you

    • @ChemHelpASAP
      @ChemHelpASAP  3 роки тому

      You are very welcome! Thanks for watching!

  • @jojoo_aah8072
    @jojoo_aah8072 3 роки тому +1

    thank you.

  • @bakihanma644
    @bakihanma644 Рік тому +1

    why did it go from 10^23 to 10^22?

    • @ChemHelpASAP
      @ChemHelpASAP  Рік тому

      I divided 6.02214 x 10^23 by 56.10564. I simplified the fraction.

    • @bakihanma644
      @bakihanma644 Рік тому

      @@ChemHelpASAP I still don't understand... Is that a rule that when you divide you lower the exponent?

    • @ChemHelpASAP
      @ChemHelpASAP  Рік тому +1

      It's less about the exponent and more about the mathematical operation. I suggest you think about 6.02214 x 10^23 as one number with many zeros after the six. It may also be helpful to review how scientific notation works. This video may help!
      ua-cam.com/video/yhXYPSDLgWI/v-deo.html
      Edit- zeros after the six, not before.

    • @bakihanma644
      @bakihanma644 Рік тому

      @@ChemHelpASAP I watched the video it's helpful but still doesn't explain my problem. 6.02214 has one number in front of the decimal so there should be no need to move the decimal anywhere if we follow what the rules in the video you linked say about scientific notation.

    • @ChemHelpASAP
      @ChemHelpASAP  Рік тому +1

      You are correct that any time a number is in scientific notation, there should be one nonzero digit in front of the decimal. But think about the problem in a different way. Consider this problem: 6.0 x 10^4 divided by 200. This equals 3.0 x 10^2. Why did the exponent decrease? Because another way to write this problem is 60,000/200. This equals 300. It's not about the exponent, it is about the numbers themselves. You are simply writing them in scientific notation.
      602,214,000,000,000,000,000,000/56.10564 = 10,733,600,000,000,000,000,000

  • @jaredingles6893
    @jaredingles6893 8 місяців тому

    Why is it so hard for people describing sig figs at the end of the calculation to say WHY THEY GOT THE NUMBER OF SIG FIGS!!! geeez!