Calculus AB/BC - 4.2 Straight-Line Motion: Connecting Position, Velocity, and Acceleration

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  • Опубліковано 26 січ 2025

КОМЕНТАРІ • 16

  • @angelinat.394
    @angelinat.394 4 роки тому +24

    I couldn’t understand this in class but I found your video and now everything makes sense. Thank you!

  • @prestwig1
    @prestwig1 Рік тому +9

    “Spatium” is Latin for space which is why it is used for position

    • @mpm1862
      @mpm1862 11 місяців тому

      Makes sense thanks

    • @thewhat2
      @thewhat2 4 місяці тому +3

      Thanks zaddy

  • @bryanherrera28
    @bryanherrera28 3 роки тому +14

    I LOVE YOU MR BEAAAANNNN 😩

  • @Notnessi
    @Notnessi Рік тому +2

    Thank you for the great content you have on calculus

  • @hanahaki4025
    @hanahaki4025 2 роки тому +1

    Thank you for the explanation! I just learned this in class, but your video helped me a lot. :))

  • @bobtivnan
    @bobtivnan 4 роки тому +7

    I love the explanations. I take issue only with the intervals of increasing and decreasing. I believe they should be closed .

    • @TheAlgebros
      @TheAlgebros  4 роки тому +7

      This is a very interesting question...should the intervals be open or closed for an increasing or decreasing function? The same question will come up for intervals of concavity. Even doing a simple Google search results in a myriad of explanations and justifications. In unit 5, we touch on this lightly but try not to have the kids get stuck on that as there are various explanations as to why we would use open, and why we would use closed. Fortunately, the questions that CollegeBoard presents to them will explicitly define if it is on an open or closed interval.

  • @dennisli4437
    @dennisli4437 4 місяці тому

    Wouldn't the interval be [1+, ~4.8-] because technically at 0, the particle is at rest. Someone please help... (Question 6 and 7)

  • @randomstuff8828
    @randomstuff8828 2 роки тому

    05:28

  • @MihirRaiNotSubTwo
    @MihirRaiNotSubTwo 2 роки тому

    In the problem on the first slide, wouldn't the graph for velocity start at 0, since the ball that Mr. Brust will throw has not moved at time = 0?

    • @TheAlgebros
      @TheAlgebros  2 роки тому +1

      We should clarify this problem for t>0. That way at t=0 we would have open circles for velocity and acceleration.

  • @JoseRamirez-mz5fb
    @JoseRamirez-mz5fb 2 роки тому +15

    Ruined my high school calc experience

    • @ultrapotato64
      @ultrapotato64 11 місяців тому +4

      this video did?

    • @nxxda
      @nxxda 2 місяці тому

      @@ultrapotato64i think he meant the topic