Thank you so much. :) I actually dismissed the explanation about the loop to shorten the length of the video. Apparently it was a bad idea. So after calculating the impovement indices for all of the unused squares, we need to select the square with the most negative improvement index. And then we need to draw a loop for that square. Basically, we need to start at the square with the most negative improvement index, go out from that square and wisely make a loop that comes back to the exact same square. To draw the loop, there are several rules that we must stick to. The rules are as follows: 1. We can only move horizontally (right or left) or vertically (up or down). 2. We can only make a stop at a used square. 3. When we make a stop, in order to move again, we need to change the direction of our movement. (Meaning that if previously we move horizontally, and we stop, to move again, we need to move vertically). 4. We need to put plus and minus sign alternately at the square that we make a stop. (Beginning with plus sign at the initial square, that is the square with the most negative improvement index). I really hope this helps. :)
@@raihanazainordin3533 And what if there are several valid figures to draw form the same starting point? For instance, if you are given the possibility to draw a square, a rectangle or even a bus like shape, how do you decide which shape of loop to draw?
I’m your ex student during Diploma (class with Hatem, Fatin Natasha.etc..) now I’m watching this for my linear programming paper (tomorrow) doing my degree. Thank you Miss Raihana or Dr Raihana now!! 😍
I am so grateful to you for this video!! You explained everything in an amazing way (your comment about the loop was really helpful) and help me truly understand how to solve these!
I want to asked someone question of VAM In this method when we take summesion 1 and summesion 2 ....in cell How to solve this type of questions by VAM method.... please explain me I can't understand in class lecture When I see your video lecture I easily understood this question
@@raihanazainordin3533 well I read the comment you are referring to and I understood what you explained about the way you draw the loop. Just to make sure I got this well, in your example, did you draw the loop from the square 100-8 to 100-5 because if you drew it to 200-3,you wouldn't be able to draw another line right or left? Thanks in advance.
@@bgrfield you are welcome. but for maximization problem, the method is the same, cuma terbalik sikit saja dengan minimization, that is, for maximization, we reach optimal when all improvement indices are less than or equal to zero.
Greetings mam🙏🙏 if we get negative improvement indices on dummy shells, is it necessary to do looping to find out more minimum transportation cost?? Plz help mam🙏🙏 Plz reply mam🙏🙏
@@raihanazainordin3533 Thakyou so much for ur valuable reply mam😍😍 but there's one more confusion in my mind...is it relevant to minimize transportation cost by supplying the goods in dummy shells(markets ) through looping?? .....as dummy markets don't have real existence too.... Plz rescue me from this one more confusion🙏🙏 Plz reply mam🙏🙏
@@avayaniroula7596 yes it is relevant. It's part of the steps. Dummy column/row is for unbalanced problem. For unbalanced problem, we do need to assign items to dummy column/row because there will be excess/shortage items. You can watch my video on solving an unbalanced transportation problem. :)
For minimization transportation problem, in order to be optimal, all improvement indices, I must be >= 0. For maximization transportation problem, in order to be optimal, all improvement indices must be
Transportation problem is a special type of linear programming problem where the objective consists in minimizing transportation costs of a given commodity from a number of sources of origins to a number of destinations.
while did u change ur R3 to 2 in the new table where as we got 2 before U used r3+5=8= r3=8-5 r3=3....this what you did but it was change to 2improvement index table
The values of all Rs and Ks are different at a new table because the location of used squares has changed. All Rs and Ks must be calculated again at each new table.
OMG THANK YOU SO SO SO MUCH ! SEMOGA ALLAH MEMBALAS JASA BAIK MADAM 😭 I FINALLY UNDERSTANF HOW THIS CHAPTER WORKS 🤩 tomorrow is my final exam ! wish me luck mdm 💜💜💜💜💜
I'm sorry, you did not explain the reasoning behind the stops of the loop. What if there's a case where the negative improvement index is in the very right most column? What if there's a case with multiple negative improvement indices?
Yes you are totally right. I purposely dismissed the explanation about the loop because of time constraint of the video. Maybe I'll improve it next time. Thanks for the feedback! :)
Everything is ok but you didn’t tell us where did you defer the second 0 from ? When you calculating the unused cell 9-0-0 ??????your explanation is marvellous but incomplete ?!!!!!
you mean, where did K3=0 come from? it came from the last used square R3+K3=3. R3=3, K3 is unknown, so we have 3+K3=3, thus, K3=0. this was explained at minute 2:50.
@@fakhrulhafiz4786 "by using solution" sounds wrong. Did you mean "by using initial solution"? But "solve the transportation problem" means you need to solve the whole thing, from initial to optimal solution.
![Transportation problem [ MODI method - U V method with Optimal Solution ] kauserwise](http://i.ytimg.com/vi/-w2z3MVTcQA/mqdefault.jpg)
![Transportation problem [ MODI method - U V method with Optimal Solution ] kauserwise](/img/tr.png)
![Least cost method[transportation problem] in operation research.](http://i.ytimg.com/vi/5xCUzCTjAXQ/mqdefault.jpg)
This is awesome... however I didn’t fully get on how that loop was made ..but u did a good job still🙌🏽
Thank you so much. :) I actually dismissed the explanation about the loop to shorten the length of the video. Apparently it was a bad idea.
So after calculating the impovement indices for all of the unused squares, we need to select the square with the most negative improvement index. And then we need to draw a loop for that square. Basically, we need to start at the square with the most negative improvement index, go out from that square and wisely make a loop that comes back to the exact same square.
To draw the loop, there are several rules that we must stick to. The rules are as follows:
1. We can only move horizontally (right or left) or vertically (up or down).
2. We can only make a stop at a used square.
3. When we make a stop, in order to move again, we need to change the direction of our movement. (Meaning that if previously we move horizontally, and we stop, to move again, we need to move vertically).
4. We need to put plus and minus sign alternately at the square that we make a stop. (Beginning with plus sign at the initial square, that is the square with the most negative improvement index).
I really hope this helps. :)
@@raihanazainordin3533 What if there are several possibilities to make squares, how do you decide which square to draw?
@@SirRenjie If there exist two squares with the same negative improvement index, you can choose either one to draw the loop.
@@raihanazainordin3533 And what if there are several valid figures to draw form the same starting point? For instance, if you are given the possibility to draw a square, a rectangle or even a bus like shape, how do you decide which shape of loop to draw?
@@SirRenjie the shape of a loop is unique.
I’m your ex student during Diploma (class with Hatem, Fatin Natasha.etc..) now I’m watching this for my linear programming paper (tomorrow) doing my degree. Thank you Miss Raihana or Dr Raihana now!! 😍
You are welcome. All the best for your study, dear. :)
Precious explanation, couldn't find elsewhere on UA-cam
I am from tanzania
Magufuli empire
Is best lecture in this time good voice very good en thank u
You are good. Just don't think about the duration. Take your time. This small explanation is great. Thank you Madam !!!!
Thank you for the comment. I'll keep that in mind. :)
I am so grateful to you for this video!! You explained everything in an amazing way (your comment about the loop was really helpful) and help me truly understand how to solve these!
thank you so much. :)
short, simple and direct explanation, may Allah ease your problem, thank you.
Thank you.
Thanks for the video, I feel like an idiot for buying a textbook when an even better explanation is provided for free!
viewer all the way from the Philippines haha. thank u
Hello there! 😊 You are welcome.
Miss Thanks for the great explanation but I think if the problem is asking for minimization all the index have to be in negative is that true?
I want to asked someone question of VAM
In this method when we take summesion 1 and summesion 2 ....in cell
How to solve this type of questions by VAM method.... please explain me
I can't understand in class lecture
When I see your video lecture I easily understood this question
very helpful video,thanks a lot! can you please explain to me how do we know in which cell to stop while drawing the loop?
Thank you. Please scroll down below and find a comment I replied to explaining about the loop.
@@raihanazainordin3533 well I read the comment you are referring to and I understood what you explained about the way you draw the loop. Just to make sure I got this well, in your example, did you draw the loop from the square 100-8 to 100-5 because if you drew it to 200-3,you wouldn't be able to draw another line right or left?
Thanks in advance.
@@TheMusicMyLife13 correct! :)
Thank you very much! This video absolutely saved my life.
You are welcome. Glad that it did. All the best to you!
very helpful Dr.....but is there any videos on how to find the optimal solution for maximization transportation problem?
Unfortunately no, dear. I haven't made that video yet. Sorry.
@@raihanazainordin3533 oooh, okay Dr. and thank you so much for this video. mudah faham and sangat membantu 🥰😊
@@bgrfield you are welcome. but for maximization problem, the method is the same, cuma terbalik sikit saja dengan minimization, that is, for maximization, we reach optimal when all improvement indices are less than or equal to zero.
@@raihanazainordin3533 i seeee, faham Dr. thank you for the explanation hehe.
Miss thanks for the explanation but if the problem is asking for minimization I think all the index have to be in negative is that true?
For minimization problem, all the indices must be greater than or equal to zero (positive) in order for the problem to be optimal.
it is so helpful, this video helps me understand this method finally!!!! thank you!!!
do we include the dummy cells in evaluating cells with negative values?
yes we do.
thanks@@raihanazainordin3533
What if when we check optimalty, can not create loops with straight lines (Square), should we leave this cell and jump to the next one?
A loop does not necessarily have to be a square. Please read my explanation on how to make a loop in the pinned message.
@@raihanazainordin3533 i see
@@raihanazainordin3533 how about, if the loops not ve right angle, like inclined connection btw cells?
Hi dr, what if there is no loop can be made? Is the optimal cost is the initial solution cost?
Yes, true.
@@raihanazainordin3533 thank youu so much dr. May He bless you. Really understand with all of your explanation ❤️
Greetings mam🙏🙏 if we get negative improvement indices on dummy shells, is it necessary to do looping to find out more minimum transportation cost?? Plz help mam🙏🙏 Plz reply mam🙏🙏
Yes dummy cells must be considered too in drawing loops.
@@raihanazainordin3533 Thakyou so much for ur valuable reply mam😍😍 but there's one more confusion in my mind...is it relevant to minimize transportation cost by supplying the goods in dummy shells(markets ) through looping?? .....as dummy markets don't have real existence too.... Plz rescue me from this one more confusion🙏🙏 Plz reply mam🙏🙏
@@avayaniroula7596 yes it is relevant. It's part of the steps. Dummy column/row is for unbalanced problem. For unbalanced problem, we do need to assign items to dummy column/row because there will be excess/shortage items. You can watch my video on solving an unbalanced transportation problem. :)
@@raihanazainordin3533 thankyou so much mam for ur valuable time and reply😍😍...I'll obviously watch ur next video😊😊 plz provide video link😊
@@avayaniroula7596 you are welcome. :)
Hi what does negative shadow costs mean?
can I asked that this example is least the cost method, so why all denta ij >=0? it must be denta ij
For minimization transportation problem, in order to be optimal, all improvement indices, I must be >= 0. For maximization transportation problem, in order to be optimal, all improvement indices must be
Transportation problem is a special type of linear programming problem where the objective consists in minimizing transportation costs of a given commodity from a number of sources of origins to a number of destinations.
while did u change ur R3 to 2 in the new table where as we got 2 before
U used r3+5=8=
r3=8-5
r3=3....this what you did but it was change to 2improvement index table
The values of all Rs and Ks are different at a new table because the location of used squares has changed. All Rs and Ks must be calculated again at each new table.
@@raihanazainordin3533 so are u saying the changes was as a result of that -1 so it was added to k3 and deducted from R3
On the R2+5=3 how did you get the 5?
Thank you
5 is obtained from the previous used square 0+K2=5, hence K2=5.
u teach better then my professor
thanks very much for the exerted efforts ,well done make it easy to understand .
Happy Ramadan thanks again
What if we had the same negative index, how would we know witch one to choose ?
you can choose either one.
OMG THANK YOU SO SO SO MUCH !
SEMOGA ALLAH MEMBALAS JASA BAIK MADAM 😭 I FINALLY UNDERSTANF HOW THIS CHAPTER WORKS 🤩
tomorrow is my final exam ! wish me luck mdm 💜💜💜💜💜
You are welcome. Glad that you understand. All the best for your final exam.
The video sound is pretty good, beyond my imagination
Thank you.
What to do when the unused squre have more than 1 -ve sign? Do we need to do multiple loop?
Draw loop at the square with the most negative improvement index. For example, if there are -2 and -8, choose -8.
@@raihanazainordin3533 thanks you so much for the fast reply! May Allah bless you Dr, Amiin
at first, I thought I was playing squid game.. LOL
Wow...I really enjoy this...it is well understood
Thank you.
I'm sorry, you did not explain the reasoning behind the stops of the loop. What if there's a case where the negative improvement index is in the very right most column? What if there's a case with multiple negative improvement indices?
Yes you are totally right. I purposely dismissed the explanation about the loop because of time constraint of the video. Maybe I'll improve it next time. Thanks for the feedback! :)
Thanks a lot, finally I've understood!!😇
You are welcome. :)
Very clear. A big help indeed. Thank you so much!
You are welcome.
Brief and smart, thank you!
Good presentation
Maashaa Allah ❤
Maashaa Allah ❤
Maashaa Allah ❤
Character In the video It's great, I like it a lot $$
Everything is ok but you didn’t tell us where did you defer the second 0 from ? When you calculating the unused cell 9-0-0 ??????your explanation is marvellous but incomplete ?!!!!!
you mean, where did K3=0 come from? it came from the last used square R3+K3=3. R3=3, K3 is unknown, so we have 3+K3=3, thus, K3=0. this was explained at minute 2:50.
Highly simplified
Thank you
بارك الله فيك.
Thank you very very much jazak Allah khayr
Omg now i understand this!:) thank you!!
this is super helpful, thank you.
Assalamualaikum madam. Jika dia nk suruh kita selesaikan initial solution just buat northwest corner Methods jer kan?
Waalaikumussalam. Yes correct. The first table (the one that we obtained using northwest corner method) is the initial solution.
@@raihanazainordin3533 jadi kita tk perlu buat MODI kan madam?
@@raihanazainordin3533 contoh soalan tu, dia kate. “By using solution, solve The transportation problem.” So just northwest corner method jer kan?
@@fakhrulhafiz4786 "by using solution" sounds wrong. Did you mean "by using initial solution"? But "solve the transportation problem" means you need to solve the whole thing, from initial to optimal solution.
@@raihanazainordin3533 ouhhh. Okey madam. Tq so much madam. Hahaha. Sye harap madam berjaya dunia akhir Amin. Tq again madam.
Thank youuu so much! May Allah bless u🥰
You are welcome. Thank you for the prayer. :)
very helpful thanks!
200 is allocated cell why u not choose 200
the video image is too poor, you need to fix it more
good job mam thank you so much
thank u for the help
my pleasure.
Thank you so much!!!
Ok why my lect cannot explain like this??
you need to adjust the content
thank you for this video
You are welcome.
Very nice .Thank you
Thank you so much
Please I need lecture note by power point send me
From Somalia thnks
very helpful, thanks
Thank you for sharing 👍
Thank you so much❤❤❤
You are welcome.
Thanks from indonesian
the sound is not good I am quite disappointed
I apologize. I was still new at this recording thing back then. I did not even have the right recording gear and equipment.
Thank you a lot
Thank youuu !!
Kandungan anda sangat menyentuh
Thanks
thank you!
I have atest jezakilah sweet
Thank you so much for this, you've helped me a lot!! 🤍
you are welcome.
thank you very much ❤❤
thanks