You have some things mixed up. THe 2.5 is not watts, it's voltage - it's the voltage drop on that bulb. Take a closer look at the glass bubble you called the shunt. THAT is NOT the shunt. There's a little wire on top of that bubble - THAT is the shunt FYI. Good video though. Oh, take note, there are 50 of those bulbs per light string - those are series strung lights and 50 bulbs using 2.5V = 125V which is the nominal voltage of your home supply and what they design by so you are correct about bulbs lasting longer when you replace ALL the burned out ones. When they burn out, the voltage drop goes down on the bulb using the shunt to conduct the power and that voltage then spreads over the rest of the bulbs in the string causing a slight rise in voltage on each bulb. The weak filament blows from the higher voltage applied and the ripple effect of the voltage rising continues. If 10 bulbs go out, that means you've got 40 left in the string and the voltage across the string increases 25V (2.5 x 10 = 25). Divide that 25 by 40 left and you get how much higher the voltage is across each bulb - 25/40 = .625 increase so now each bulb burning now has 2.5 + .625 = 3.125V on it. That's a lot for a 2.5V rated bulb and they go. Hope this sets the record straight and is useful to know......
good advice,Albert,We still light our tree with 1930s GE-Mazda c-6 bulbs (series)...I add an extra lamp in the string,to drop the voltage abit,makes the 'hard to find' lamps last longer...
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You have some things mixed up. THe 2.5 is not watts, it's voltage - it's the voltage drop on that bulb. Take a closer look at the glass bubble you called the shunt. THAT is NOT the shunt. There's a little wire on top of that bubble - THAT is the shunt FYI. Good video though. Oh, take note, there are 50 of those bulbs per light string - those are series strung lights and 50 bulbs using 2.5V = 125V which is the nominal voltage of your home supply and what they design by so you are correct about bulbs lasting longer when you replace ALL the burned out ones. When they burn out, the voltage drop goes down on the bulb using the shunt to conduct the power and that voltage then spreads over the rest of the bulbs in the string causing a slight rise in voltage on each bulb. The weak filament blows from the higher voltage applied and the ripple effect of the voltage rising continues. If 10 bulbs go out, that means you've got 40 left in the string and the voltage across the string increases 25V (2.5 x 10 = 25). Divide that 25 by 40 left and you get how much higher the voltage is across each bulb - 25/40 = .625 increase so now each bulb burning now has 2.5 + .625 = 3.125V on it. That's a lot for a 2.5V rated bulb and they go. Hope this sets the record straight and is useful to know......
Thanks for the clarification! I appreciate you.
good advice,Albert,We still light our tree with 1930s GE-Mazda c-6 bulbs (series)...I add an extra lamp in the string,to drop the voltage abit,makes the 'hard to find' lamps last longer...