Work energy and power 07: Vertical circular motion complete concept class 11
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- Опубліковано 19 вер 2024
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------------‐----------------------------------------------------------- Vertical circular motion complete concept and examples in work energy and power chapter in class 11
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These videos are in Telugu/English on intermediate physics, NEET, MAINS, EAMCET
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tq tq tq tq sir god sended
Sir please complete remaining chapters😔...I have completed this chapter and i solved H.C vermas concepts of physics-1 64 questions in 3hours ..thanks sir I have learnt concepts....No couching is required 😘
Sir tangential acceleration is gsin theta
tnq sir its really helpful....
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Root over v1 square minus gl
Very nice explanation
√v1^2-gl
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43:39underroot v square_-gl
At 5.52 g is negative
NICE SUPER EXCELLENT MOTIVATED
Nevv annitiki ide comment pedutunnav.......
🙄🙄
@@ganeshjaggineni4097 kvsk sir meeku telusa bro
Ledhu.....
"You tube" lo aa channel chusa...
Under root v square -gl
Nice
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Tq nice explanation
Sir please make video on power as early as possible...
Sure
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Super class sir
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For more information go through description of the video tq
Sir at angle 60 degree thaggara velocity is √v2--gl
sir plz keep video on concept power
Sure 👍
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Sir the answer for 60 degrees is root v1 square -gl
Excellent
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Sir plz upload lens conceps plz refration of light
Sir velocity at 60 degrees is root over v square minus gl
Excellent
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sir , at 8 :27 timing question I got answer as sq .root of V 1 square - gl as answer for velocity of mass at 60degree angle
At d point cos60 ans is under root of v1squer minus gl sir
Sir complete this chapter 😢
Root over
Sir work, energy and power lo power topic cheypaledu ga SIR
Haa cheyyali
@@kvskphysics Koncham tvaraga cheyandhi sir please 🙏🙏🙏
Power gurinchi cheppaledu
sir I have a doubt why l-cos should take sir plz explain
Sir at time:41:16 tangential acceleration is g sin theta kada sir
Yes, it should be g sin theta
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V1 square -gl
Excellent
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Sri could you please upload video on power also
60 degree answer is
√v^2-gl
Power vedio sir
A very good evening sir ur teaching is excellent sir .
SIR WILL YOU TAKE ONLINE CLASSES
PLZ SIR THIS IS MY REQUEST TO TAKE ONLINE CLASSES WE ARE SUFFERING FROM PHYSICS YOUR TEACHING IS EXCELLENT WE NEED TO JION IN YOUR CLS😊
Sir ee vedio first lo tangential acceleration g sintheta annaru last lo g costhetha annaru...ede correct sir
Power concept video sir🙏🙏
Root v1 square-gl is the answer
at 60 degrees the answer is root of v1square -gl
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√v1^2-gl is the answer at 60°
Excellent
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Hie sir one video is hiden sir
Sir neet lo vache each chapter lo dheni midha i mean which topic midha questions adugutharu cheppagalara...all topic cheppagalara
sir in last problem, tangential acceleration should be gsintheta. can you clarify my doubt
Yes u r right
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Sir you said deceleration is gsin●
v60=root over v1.sq-gl
Sir power concept kuda upload cheyandi sir plsss it's my sincere request
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Sir power kuda cheppandi, mains
Sir meeru chala bhaga explain chestunnavra meeru a collagelo teaching chestaru
Tq.. I'm not working now
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To sir
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Plz sir
Sir exllent teaching helping a lot
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Sir I've got √v1^2-gl
Excellent
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Tb=m/l(v1^2-2gl)sir ekkada l 2 unai
Tb=mv1^2/l-2mgbut ekkada l ledhu adhi ala sir
Sir....pls reply my doubt
Sir at 19:56 L why do you not wrote
4g^2 is 16 sir meru malli 16g^2 vesaru
At 8:32, the velocity at 60° will be √v1^2 -gl
Excellent
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@@kvskphysics tq sir
At 60 degrees √v1^2-gl
And I have a doubt that when it is in vertical circular motion then the tension of the string changes or will it stay constant
Tension changes
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Thanku so much sir
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Ur teaching was excellent sir if u had no problem join our college and teach us my college is sri chaitanya in vijayawada sir
Sir in the last example the tangential acceleration should be gsin theta know sir ...... And that will be √3/2 ×g
Super class sir
√v1^2-gl
Excellent
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Sir ee vedio first lo tangential acceleration g sintheta annaru last lo g costhetha annaru...ede correct sir
√v² -gl
Excellent
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@@kvskphysics ok sir tq so much