22.4 Hofmann Elimination and Cope Elimination | Organic Chemistry

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  • Опубліковано 28 січ 2025

КОМЕНТАРІ • 14

  • @jackiele5019
    @jackiele5019 2 роки тому +1

    OMG what you said at 8:56 totally helped. Thank you.

  • @alexandrajohnston4835
    @alexandrajohnston4835 2 роки тому

    This made so much sense, thank you!!

  • @undeadsoul0608
    @undeadsoul0608 2 роки тому

    Thanks for your help

  • @tahsinuddin
    @tahsinuddin 2 роки тому +1

    I'm a little confused - how does the oxidation step for H2O2 carry out for cope elimination? I'm confused on how the O- attaches in the first step. Thank you so much for the video!

    • @ChadsPrep
      @ChadsPrep  2 роки тому +2

      Hey there - the lone pair on the N atom acts as a Lewis base and attacks one of the 'O' atoms in HO-OH to add an OH group to the amine (hydroxyamine). The OH group is then deprotonated by the -OH left behind in the first step to form the amine oxide. I hope that helps!

  • @naimeeyiturk5415
    @naimeeyiturk5415 Рік тому

    Türkiyeden selamlar hocam teşekkürler

    • @ChadsPrep
      @ChadsPrep  Рік тому +1

      You're welcome, from U.S.A.

  • @sciencenerd7639
    @sciencenerd7639 2 роки тому +1

    👍

  • @misbahiqbal6296
    @misbahiqbal6296 2 роки тому

    👏👏👏