When the matrix operator is differentiation (d/dx), the eigenvalue equation becomes: d(e^ax)/dx = λe^ax Simplifying, we get: ae^ax = λe^ax This implies λ = a. Since there's only one distinct eigenvalue (λ = a), there will be only one corresponding eigenvector.
JazakAllah ! Allah ap ka iqbal hamesha boland rakhe.
Allah pak always bless u with his uncountable blessings
thanks a lot sir
you explaining method is very excellent, amazing, respected.
Thanks and welcome
Bhhhtttt acha explain krte hain ap
Jzakallah sir ap ki video bht nice thi bht sary concept clear ho gy an
Allah pak ap ko lmbi umar dy sir g
kia ap ka paper ho gaya hai agar ho gaya hai to please share kar dain
jazak allah sir very interesting video. I'm not getting bored while watching your video. Thanks again
36:22
Option (c) infinite many
Jazak Allah Khairan Kaseeran Kaseera sir ❤️
MashaAllah Respacted Sir,apka teaching method BHT acha hai❤
Jazak Allah
جزاک اللہ۔۔
JazakAllah sir g ❤🎉
Nice sharing ❤️
thaks alot sir khush rhay hamasha.
u welcome
Good efforts sir Thanku so much
All the best
Excellent work
jazak Allah
Proffessor Chill originally Chill master hy
Great bro
🙂
sir you are great .thank u so much
All the best
Jazak Allah
Excellent method of teaching
Thanks for liking
Sir you are my fvrt❤. Thank you so much ❤️. Excellent work
Thank you so much 😀
Very good ☺️👍👍🥰
ggoood sir
Thanks and welcome
I just enjoying while watching this video
Thank you for enjoying
Ek ka answer unique /one solution hy..
2nd ka answer (x-1)^3 hy
12:04 ka answer d hai
21:20
Ap ny kaha direct method zayada fast hty hn
Or 29:50
par ap kh rhy hn k Iterative methods fast hy
g i check it now, 29:50 waly question py ma ny stay nai kia bina daikhy hi nikal gya ..
direct methods are fast
Sir video bout achi hai.
Tin tin itni length 48 mint ki
48 mins me ap daikhen k kitny lectures k concepts clear ho gaye hen
😂
x^3-1 answer
yes , thanks
yes yehi hai
(x-1)^3 Is correct
When the matrix operator is differentiation (d/dx), the eigenvalue equation becomes:
d(e^ax)/dx = λe^ax
Simplifying, we get:
ae^ax = λe^ax
This implies λ = a.
Since there's only one distinct eigenvalue (λ = a), there will be only one corresponding eigenvector.
Sir jii in quizzes me se paper araha hai? Please guide
jin 2 mcqs k answers nhi lgy hoay kisi std ko elm h to kindly bta dain.
jin k answer nai lagy wo repeated hen
@@professorchill78 sir me first time ap k lectures liay
Ma sha allah Excellent teaching method 😍😇👑
💕━━━━⊱✿⊰━━━━💕
Tʜʌŋĸs ❤️
Tin tin tin 😂🙌
Sir yh quiz file mil skti ha
download the file from description of video
hahahah ameen ho gya bhai
plees prepare meterial for finl term
Already uploaded dear
Asslam o alaikum sir mid k liy koi file h to bra dain
quiz 1 and 2 and handouts only are best for mid
what is eigenvalues
ye sawaal google se puch len 😁