Math Olympiad|Solve for x?|4^-x=1|

[@payoo_2674]

4^(-x) = 1 1 = e^(2kπi) k∈Z
2^(-2x) = e^(2kπi)
ln(2^(-2x)) = ln(e^(2kπi))
-2x*ln(2) = 2kπi
x = 2kπi/(-2*ln(2))
x = -kπi/ln(2)
the only one real solution for k=0 is x=0
other solutions are imaginary