A. Minimum horizontal distance between two parallel main reinforcing bars shall be equal to or more then the value.. 1) The Diameter of bar if the diameter are equal 2) The Dia. Of larger bar if the diameter are unequal 3) 5mm more then the nominal maximum size of coarse aggregates. . . Example:- #.Minimum horizontal distance of bars shall be equal to or more then 1:- Dia of bar are equal = 12 mm 2:- nominal max. size of CA + 5mm then 20+5mm= 25 mm. So take horizontal distance = 25 mm #.Minimum horizontal distance of bars shall be equal to or more then 1) If Dia of bar are unequal take larger dia of bar = 32 mm 2) nominal max. size of CA + 5mm then 20 + 5mm= 25 mm. So take horizontal distance = 32 mm. B. Minimum vertical distance between two rows of bars shall be greater of value 1) 15 mm. 2) Maximum size of bar 3) 2/3 of nominal maximum size of coarse aggregates. Example:- #.Vertical distance of bars shall be greatest of 1) 15 mm 2) Max size of bar = 12 mm 3) 2/3 nominal max. size of CA = 2/3*20=13.33=14mm So take minimum vertical distance 15mm #.Vertical distance of bars shall be greatest of 1) 15 mm. 2) Max size of bar = 16 mm 3) 2/3 nominal max. size of CA = 2/3*20= 13.33=14mm So take min vertical distance = 16 mm
Dhanyavaad! Humare videos pasand karne ke liye shukriya. Hum hamesha yeh koshish karte hain ki hum aapko informative aur helpful content provide kar sakein.
Great teacher❤️
your video is really informative.... kindly enable english subtitles sir... respect from tamilnadu
make video about what is eccentric footing and strap beam
Thank you sir
Maximum distance between bar????
Very good
A. Minimum horizontal distance between two parallel main reinforcing bars shall be equal to or more then the value..
1) The Diameter of bar if the diameter are equal
2) The Dia. Of larger bar if the diameter are unequal
3) 5mm more then the nominal maximum size of coarse aggregates. . . Example:-
#.Minimum horizontal distance of bars shall be equal to or more then
1:- Dia of bar are equal = 12 mm
2:- nominal max. size of CA + 5mm then 20+5mm= 25 mm.
So take horizontal distance = 25 mm
#.Minimum horizontal distance of bars shall be equal to or more then
1) If Dia of bar are unequal take larger dia of bar = 32 mm 2) nominal max. size of CA + 5mm then 20 + 5mm= 25 mm.
So take horizontal distance = 32 mm.
B. Minimum vertical distance between two rows of bars shall be greater of value
1) 15 mm.
2) Maximum size of bar
3) 2/3 of nominal maximum size of coarse aggregates.
Example:-
#.Vertical distance of bars shall be greatest of
1) 15 mm
2) Max size of bar = 12 mm
3) 2/3 nominal max. size of CA = 2/3*20=13.33=14mm So take minimum vertical distance 15mm
#.Vertical distance of bars shall be greatest of
1) 15 mm.
2) Max size of bar = 16 mm
3) 2/3 nominal max. size of CA = 2/3*20= 13.33=14mm
So take min vertical distance = 16 mm
Good, But always remember there is a Cl 26.3.2 of IS 456 b which specific tell about the case when we use needle vibrator.
@@Civil_Guruji yes sir
good morning sir aap training karvate ha to kya chartificate bhi denge kya or online hi shikhna padega kya puri information dijiye
Yes we also provide certifications, call on 9111001234 for full details
Nice video
Dhanyavaad! Humare videos pasand karne ke liye shukriya. Hum hamesha yeh koshish karte hain ki hum aapko informative aur helpful content provide kar sakein.
Best sir
Bahut bahut shukriya! 😊 Aapka support hamesha hamare liye khas hai.
Nai cheez
Iska 2nd vedio kaha par hey ?
Pura add hi de do na
Very Confusing
So easy to understand mam no confusing