Mathematical induction with inequality

Поділитися
Вставка
  • Опубліковано 4 лис 2024

КОМЕНТАРІ • 73

  • @bombergame8636
    @bombergame8636 11 місяців тому +57

    The passion this man has is unrivalled, amazing to watch!

    • @ycong4689
      @ycong4689 11 місяців тому +1

      This man is👍👍👍👍

  • @adw1z
    @adw1z 11 місяців тому +16

    I love the diversity of the questions u cover, from simple high school to undergraduate to Olympiad material. Keep going, and never stop learning!

  • @markslowhand4214
    @markslowhand4214 7 місяців тому +2

    A world full of teachers like you would solve a lot of problems, not only mathematical problems!

  • @SmilingDiamondRing-jt5ps
    @SmilingDiamondRing-jt5ps 3 місяці тому +2

    I really love this man he is the best maths tutor I have ever seen

  • @mdasifeqbal2323
    @mdasifeqbal2323 11 місяців тому +4

    This man is better than any class teacher and private tutor.

  • @alpmuslu3954
    @alpmuslu3954 11 місяців тому +11

    Guys remember to like the video, that’s the least we can do to thank him

  • @ophioneldertitan
    @ophioneldertitan День тому

    I always wondered why they add "+ 1" to k and now I completely understand. *Subscribed*

  • @incognito_tab43
    @incognito_tab43 9 місяців тому +1

    Your voice ❗️it literary compels me not only to learn but to understand idk how describe it but tysm for choosing to do this

  • @davidbaker5725
    @davidbaker5725 4 місяці тому +3

    Thanks for this video, it really helped me learn how to better phrase some things when teaching mathematical induction, Your videos are super well done, and really stress the important points of each topic, I appreciate your awesome positive energy!

    • @PrimeNewtons
      @PrimeNewtons  4 місяці тому

      Glad it helped!
      Thank you for you message. I appreciate it too

  • @mady-son
    @mady-son 8 місяців тому

    One of the best videos explaining this topic

  • @glorrin
    @glorrin 11 місяців тому +8

    Great video :)
    Here is a funny trivia: in my country |N include 0, and if we want to exclude 0 from any group of number we add a*, so all natural numbers would be |N*, that means it is also easy to define the domain of 1/x which is |R*
    The example is great to explain induction but we can go further, it is easy to prove that n = 1, it is done in the video
    for n

    • @PrimeNewtons
      @PrimeNewtons  11 місяців тому

      Nice observation. I'll take note

  • @NigusMamo-d8f
    @NigusMamo-d8f 5 місяців тому +1

    Thank you for your guidance and support. Your dedication inspires me to learn and grow.
    Sincerely, [Thomas]"

  • @sultangaddafi9934
    @sultangaddafi9934 Місяць тому

    Damn...I was sooo confused but my doubts are now cleared!!...Mathematical proofs can be a unforgiving but thanks to you all's well!!!

  • @NahomMerga
    @NahomMerga 8 місяців тому

    The Best explanation there exist❤

  • @abdulkhadarainur4348
    @abdulkhadarainur4348 11 місяців тому +4

    Never disappoints.

  • @biswambarpanda4468
    @biswambarpanda4468 11 місяців тому +2

    Wonderful sir

  • @flight7218
    @flight7218 11 місяців тому +1

    what we have to prove is the same as "2n

  • @carlosangulo2888
    @carlosangulo2888 11 місяців тому

    I love your videos bro. Thanks.

  • @AZALI00013
    @AZALI00013 11 місяців тому

    very nice video !!!

  • @dirklutz2818
    @dirklutz2818 7 місяців тому +1

    You're the best!

  • @holyshit922
    @holyshit922 11 місяців тому +1

    About your algebra video series
    You can mention about similar matrices,Cayley Hamilton theorem, and maybe Jordan form
    after you finish with eigenvalues you can record something about rotations , reflections , orthogonalization

  • @nicolascamargo8339
    @nicolascamargo8339 11 місяців тому +1

    Wow genial esa pasión que le pone a los videos

  • @ViniciusTeixeira1
    @ViniciusTeixeira1 7 місяців тому +1

    I solved the induction step like this:
    Considering that there exists a natural number K such that K ≤ 2^(K - 1), then K + 1 ≤ 2^(K - 1) + 1. Naturally, 2^(K - 1) + 1 ≤ 2^(K - 1) + K. But by the initial hypothesis we know that 2^(K - 1) + K ≤ 2^(K - 1) + 2^(K - 1) = 2^K; therefore, K + 1 ≤ 2^K

  • @jamesharmon4994
    @jamesharmon4994 11 місяців тому

    My faith in math is shaken by proofs such as: The sum of all positive integers is negative one twelfth.

  • @Nutshell_Mathematica
    @Nutshell_Mathematica 11 місяців тому +1

    Amazing can u set of questions these type in a another video

  • @uwuowo7775
    @uwuowo7775 11 місяців тому

    I love your content bro

  • @digbycrankshaft7572
    @digbycrankshaft7572 11 місяців тому +6

    If k+1

    • @danielschneider9358
      @danielschneider9358 11 місяців тому

      It wouldn't follow from that, correct.
      But:
      The fact that k+1

    • @coolblue5929
      @coolblue5929 11 місяців тому +2

      I have the same problem. Surely you can only make the right hand side bigger, not smaller.

    • @danielschneider9358
      @danielschneider9358 11 місяців тому +2

      The idea here is that you are making an even STRONGER condition, and saying that if that condition is true, the other one also has to be true
      You want to show: k+1

    • @martynpage1794
      @martynpage1794 11 місяців тому +2

      Is it that k+1

    • @coolblue5929
      @coolblue5929 11 місяців тому

      @@danielschneider9358 you are making the condition WEAKER, not stronger. If you are trying to show that a

  • @holyshit922
    @holyshit922 11 місяців тому +3

    1:29 This is one of the reasons I like math
    For examle when I used to go to school Pluto was consider a planet now it isnt

  • @ramizhossain9082
    @ramizhossain9082 10 місяців тому

    Great proof.

  • @davidemmanuel9418
    @davidemmanuel9418 9 місяців тому

    Beautiful ❤️

  • @OscarKanyimbo
    @OscarKanyimbo 11 місяців тому

    Thanks 🙏 I'm just having my exam in the next 24 hrs

  • @Vengeance-yb8lm
    @Vengeance-yb8lm 11 місяців тому

    Do you have any advice for math youtubers who are just starting out ?

  • @reamartin6458
    @reamartin6458 11 місяців тому

    This was cool 😎 thanks

  • @holyshit922
    @holyshit922 11 місяців тому +2

    Why induction works ?
    In my opinion it is based on structure of natural number
    each subset of natural numbers has minimal value
    each natural number has successor

    • @adw1z
      @adw1z 11 місяців тому

      It’s like a domino effect.
      You’ve shown that if it works for some natural number k, it will work for k+1. This in turn means that it will work for k+2 etc… (and so it will work for all natural numbers >= k )
      but you’ve shown it works for 1. Thus it must work for 2, then 3, then every natural number after

    • @yasir6347
      @yasir6347 9 місяців тому

      Yeah I think that’s the well ordering principle

  • @tuhinrezareza6966
    @tuhinrezareza6966 9 місяців тому

    For 6

  • @Thachoanhdi
    @Thachoanhdi 11 місяців тому

    We can use Bernoulli’s inequality

  • @ZANBA_MYON
    @ZANBA_MYON 11 місяців тому

    At 11:30 I didn't see the reason for the conclusion that k + 1 = k + 1 and hence make the connection k + 1

    • @PrimeNewtons
      @PrimeNewtons  11 місяців тому

      How did you know 2k

    • @ZANBA_MYON
      @ZANBA_MYON 11 місяців тому

      @@PrimeNewtons you got a point there. What I could have said was that our induction step assumes that the statement k

  • @coolblue5929
    @coolblue5929 11 місяців тому +3

    Sorry, I think your last step is wrong. You can only make the RHS bigger, not smaller.

  • @rookiepilot15
    @rookiepilot15 Місяць тому

    Please come to meridian world school in Texas and teach us pls I beg u my brotha

  • @youssefnidhsain4082
    @youssefnidhsain4082 11 місяців тому

    i have a question isn't 0 a natural number ? in addition to that p(n=0) is a true statement since 0

    • @dakehami
      @dakehami 8 місяців тому

      0 is not a natural number

    • @dakehami
      @dakehami 8 місяців тому

      0 is not a natural number

  • @cyruschang1904
    @cyruschang1904 10 місяців тому

    if n ≤ 2^(n - 1)
    2^((n + 1) - 1) = 2^((n - 1) + 1) = 2 x 2^(n - 1) ≥ 2 x n
    but 2 x n = 2n > n + 1 (because 2n - (n + 1) = n + 1 > 0)
    So we have established
    if n ≤ 2^(n - 1)
    2^((n + 1) - 1) ≥ n + 1

  • @Aiellosfetano
    @Aiellosfetano 8 місяців тому

    Sorry, i don’t understand why k+1 is < or = a 2k?

  • @New-zl7np
    @New-zl7np 9 місяців тому

    Bro,solve this mathematical induction question 3^n≥n^2,for all natural number,I need this question answers.please!

  • @waxis9153
    @waxis9153 11 місяців тому

    Is math the most trustworthy science? Wel since it's based on certain axioms, as long as we can't prove that those axioms are true we can't really know if math is 100% trustworthy. But then again most of our systems that we have are at a certain level based on axiom(s).

  • @jafarmasuha268
    @jafarmasuha268 6 місяців тому +1

    The explanation is not logically accurate, so it is difficult for students to understand.

    • @PrimeNewtons
      @PrimeNewtons  6 місяців тому

      You need to state what is accurate or inaccurate. Your comment s not helping me learn anything from you. I'd appreciate if you post something helpful 🙂

  • @muhammadnawab3959
    @muhammadnawab3959 10 місяців тому

    At 5.15 u proved that 1 and 2 are natural but u did not say anything about 3

  • @jafarmasuha268
    @jafarmasuha268 6 місяців тому

    There are arguments that are not logically accurate.

  • @sparshsharma5270
    @sparshsharma5270 11 місяців тому

    To be honest I never liked proof by induction.
    Among all different types of proofs, the proof by induction is said to be the weakest one actually.

    • @DBstudios98
      @DBstudios98 7 місяців тому

      By who? Induction is not "weaker" than other forms of proof. It's just as mathematically valid as other methods, if it gave less of a correct result it wouldn't ever be used

    • @sparshsharma5270
      @sparshsharma5270 7 місяців тому

      @@DBstudios98
      All proofs give correct result hence the name.
      But there are types of proofs with their methods.
      As per experts, induction is weakest yet most interesting. And as per them, proof by brute force would require all exhaustive cases checked hence large complexity. Like if chess would ever be solved, it would require brute force algorithm. Even for quantum computers, solving chess would take lot of time.

  • @jacktut2590
    @jacktut2590 6 місяців тому

    please help me solve this Show that
    5^n +6^n < 9N for n greater or equals 2.