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Показувати елементи керування програвачем
Автоматичне відтворення
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Yeah, I can do this!
3125 = 5⁵a + 5⁵ᵃ = 05⁵ᵃ = -aa = -u5⁻⁵ᵘ = u-5uln5 = lnu(1/u)lnu = -5ln5(1/u)ln(1/u) = 5ln51/u = 5 => u = 1/5 => *a = -1/5*
Great solution and not complicated.
x=-(W(5ln5))/(5ln5) also, W Lambert function is multivalued so there also other values.
as soon as you see 3125 and calculate that it is 5^5 you know a is going to be linked to 1/5.a little bit of trial and error error leads to a=-1/5. Not tricky at all.
That's the trick 💪💪💪
a=-5
Yeah, I can do this!
3125 = 5⁵
a + 5⁵ᵃ = 0
5⁵ᵃ = -a
a = -u
5⁻⁵ᵘ = u
-5uln5 = lnu
(1/u)lnu = -5ln5
(1/u)ln(1/u) = 5ln5
1/u = 5 => u = 1/5 => *a = -1/5*
Great solution and not complicated.
x=-(W(5ln5))/(5ln5) also, W Lambert function is multivalued so there also other values.
as soon as you see 3125 and calculate that it is 5^5 you know a is going to be linked to 1/5.
a little bit of trial and error error leads to a=-1/5. Not tricky at all.
That's the trick 💪💪💪
a=-5