Relation R in the set N defined as R={(x, y):y=x+5 and x less 4} Reflexive, Symmetric, Transitive|12

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  • Опубліковано 14 гру 2024

КОМЕНТАРІ • 13

  • @AmitKumar-wl8ok
    @AmitKumar-wl8ok 10 місяців тому +3

    How it is transitive??
    When (1,6) is there and (6,sth) is not there; then (1,sth) cannot be determined .
    Then how can you say the relation is transitive???

    • @FountainofMathematics
      @FountainofMathematics  10 місяців тому +7

      A relation is transitive only when if aRb and bRc exists then we need to check for aRc. here in this question, there is no point of discussing about aRc with out bRc. Which implies that there is no counter example to disprove, hence transitive.

    • @AmitKumar-wl8ok
      @AmitKumar-wl8ok 10 місяців тому +1

      @@FountainofMathematics Thank you sir for clearing my doubt.

  • @sohilkhaparel2431
    @sohilkhaparel2431 11 місяців тому +1

    👍 Thanks sir

  • @DelaDemdoe
    @DelaDemdoe 7 місяців тому +1

    you are wrong about the transitive,

  • @naniakshaykumar8894
    @naniakshaykumar8894 Рік тому +2

    Thanks boss😊

  • @ss-iw4pl
    @ss-iw4pl 9 місяців тому +1

    How it is transitive it is not transitive

    • @AnbuElangovan
      @AnbuElangovan 9 місяців тому

      It is transitive don't fail ur exam

    • @ss-iw4pl
      @ss-iw4pl 9 місяців тому

      @@AnbuElangovan 😂ok

  • @Yogesh-xw5zm
    @Yogesh-xw5zm 9 місяців тому

    It is not transitive prove it

    • @AM-wv5qy
      @AM-wv5qy 5 місяців тому

      Instead of proving it is transitive they trying to disprove it since there was no theory saying it doesn't belong to r they said its transitive o dont understand either all maths problems should have one universally accepted answer but hamara education system chutiya hena