Line integral of a function
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- Опубліковано 30 лип 2024
- This is the first video of a month-long series on vector calculus! In this video, I calculate the line integral of a function f with respect to s over a curve C, which can be interpreted as the area of the fence under f and over C. It’ll serve as the basis of a lot of other line integrals. Enjoy!
Typo: (6,3) should be (9,3). The rest is still correct!
Dr. Peyam's Show yup sir...i really appreciate the way you explain...tq so much
I think that direction should be clockwise not counterclockwise.
ah... I was going crazy at the beginning... 🙂
Dr. Peyam: the most wholesome mathematician
how would the point (6,3) lie on x = y^2 ?
shouldn't it be (9,3)?
Gotta love the energy you bring to mathematics, professors like you are why I'm a math major.
Moises Ramos Same here
Thank you!!!! 😄
Wow! Vector calculus is just so epic with so many practical applications. Crazy helpful is physics aswell. Hats off to yourself Dr. peyam, great video🥂
It turns out that you have to tilt your head not only 90° but 180° in order to fix the point (6,3) an turn it into (9,3). xD
I'm looking forward to this series as well.
Hahahahaha 😂
an turn?
As always, another clear and concise explanation ...
This video is very clear and helpful. Thank you Prof. Peyam.
very "fency" calculus, that made me laugh out loud! Thank you for a great video!
Amazing video as always! I really like Analysis and all of its topics and prefer it over geometry and stochastic :)
eeeee im excited for all these multivariable videos
I'm*
I love the chain lu!
Gran video
9:28 roflmao 😂
Great video 👌
Finding parameterizations when the function isn't given is the hardest part for me. would love to see videos on that!
Many more to come!
Man, this tripod is beautiful.
Thanks so much!!!! 😄
This is pretty close to the arclength of a curve which is equal to int from a to b sqrt(1+(f'(x))^2)dx. The only difference is that it doesn't always have a base of 1 and that you also have to multiply by the height at the point (x(t),y(t))
Yep, absolutely! In fact if x(t) = t and y(t) = f(t), then you get exactly the arc length formula!
My fucking god 😂 I love how you say your jokes
How can this be used to find area of a fence? And, is parametrization always required, can't we solve the question without it?
The area of the fence is by definition the line integral of f ds. For f ds you *need* parametrizations, but for P dx + Q dy, on Wednesday there’s a related way without parametrization
@@drpeyam Thanks Sir, its great hearing from you.
Please can you explain fractional derivatives and fractional integral step by step
Look at my fractional derivatives playlist
Isn't that clockwise?
Good catch! It is clockwise, but since we’re just talking about the integral of f with respect to ds the orientation doesn’t matter. In the next video the orientation will matter!
(6,3)? ummm...
That's what maths lessons are like when I'm teaching!
When drawing the graph couldn’t you just put x in vertical direction and y in horizontal?
Depends on the convention
I don't understand how that's counterclockwise. A clock will go from 6 to 9 to 12 o clock, and that's what seems to be happening here, so why isn't the direction of movement clockwise?
It’s clockwise
@@drpeyam thanks, I was very worried
Sir please mean no offense but shouldn't the derivatives be partial derivatives
In higher level math they’re the same thing!
@@drpeyam thank you sir
Yeah, you know your stuff. But I would have started with easier examples. Thanks anyway.
Dude you funny AF.you should go for stand-up comedy 😂.but work on your jokes because they kinda lame lol
I’m trying 😅