The best ever videos on circuit theory. Sir tomorrow I have my semester exam of circuit theory and I was just 0. After watching your videos on network theorems I have confidence to pass. If I will pass tomorrow.. you will be the reason sir. Thank you so much.
Sorry to be so offtopic but does anybody know a method to get back into an instagram account? I was dumb forgot my password. I appreciate any help you can give me!
@Kaden Ira thanks so much for your reply. I got to the site on google and im waiting for the hacking stuff now. Seems to take a while so I will get back to you later with my results.
Sir while finding the relation between Vx and the currents you haven't included V2 in the KVL equation as the 4 ohm resistor end is connected to the positive terminal of V2
Ans of H.W. will be A=11/34 & B=40/34
On substituting I1 in V1 we can find A,B values as
A=0.32,B=1.176
Thank you sir
I have also same ans
Will you explain your answer???
B=(4-0.4705)=3.5295
Thank you 👍
@@dhanasekars8147 B=4-5.1764=1.176
thank sir
The best ever videos on circuit theory. Sir tomorrow I have my semester exam of circuit theory and I was just 0. After watching your videos on network theorems I have confidence to pass. If I will pass tomorrow.. you will be the reason sir. Thank you so much.
Did you pass?
@@w1ndro1d 😂😂 she would have replied 🤦♀🤣
@@komalikagaikwad8457 q😂😂😂😂😂😂😂
@@w1ndro1d 😀😀😀😀😀😀
Aapka knowledge to bda Kamal h sir( Your knowledge is excellent 👌)👏👏
Please do more videos sir I am preparing for gate 2021 from your lectures only
Please do videos of ECE sir
Sorry to be so offtopic but does anybody know a method to get back into an instagram account?
I was dumb forgot my password. I appreciate any help you can give me!
@Cairo Marcellus instablaster :)
@Kaden Ira thanks so much for your reply. I got to the site on google and im waiting for the hacking stuff now.
Seems to take a while so I will get back to you later with my results.
@Kaden Ira it did the trick and I finally got access to my account again. I'm so happy:D
Thanks so much, you saved my account :D
@Cairo Marcellus happy to help :)
You are very good teacher
Ans
A =0.323(11/34)
B=1.176(40/34)
C=0.029(1/34)
D=0.470(16/34)
Right
How???
How you got 40??
Thanks a lot Professor
Wonderful lectures.... ❤❤❤
A:11/34
B:20/17
A : 0.3235 or 11/34
B : 1.1764 or 40/34
A= 11/34 ,B=40/34 ...is my ans...😁😁😁🤗🤗🤗...
Which clg
A=0.3235 and B=1.1764
Sir next please start #Transient. This is Hamble request to you
Thanks so much 🙏
A=11/34
B=40/34
right
How please send me the picture
A=0.323 ,B=1.17
can you explain
Thanks Sir 😃😃
A=0.323
B=1.176
thank you sir
Sub the value of I1 in eq 3 ......
v1=11i1+4i2
We can get
V1=11/34v2-40/34 i2
very nice
Sir while finding the relation between Vx and the currents you haven't included V2 in the KVL equation as the 4 ohm resistor end is connected to the positive terminal of V2
A=11/34=0.3235
B=40/34=1.1764
What is the z value
10:51 / 11:14
H. W ans
A=11/34, B=40/34
Thanks
i1 value put eq. v1 then after solve this A=11/34 ,B=1.1764
Sir is we find z parameters instead of finding abcd parameters and convert them into abcd parameters in exams
A = 44/136 ; B = 160/136
Tq sir!
A=11÷34,B=60÷17
Why Is sign for parameters not taken into consideration???
nice lictur
Sir what law did you follow in calculating vx please reply sir
He used kvl...
a =0.3235
b= 1.176
A will be 0.0323 and B will be 1.176 sirr
I2 current direction opposite aa
A=11/34,B=40/34
A : 0.3235
B : 1.1764
how?
plz some one tell me how to get A and B by solving equation like we got C and D??
Simply replace i1 in v2
Put the value of i1 in the value of v1.
Looks like im not going to be an engineer :(
How can we find |Z| ?
Ad- bc
Transient 🙏plz
Transients
11/34,40/34
A=0.3235, B=1.1765
A=3/17
B=14/17
🙏❣
B=11.764, A=0.3235
A=11/34
B=20/17
How send me pic plz
match the ABCD equation to the Y parameter equation, you will get the answer
a=0.32352
b=1.17647
A=0.323 and B=1.1764
A=0.323
B=1.176
A= 11/35,b=40/34
A = 0.32, B = 1.176
A=11/34,B=40/34
A=1.176
B=0.3225
A=11/34 B=40/34
A=0.3235,B=1.176
A=11/34,B=40/34
A=0.3235
B=-1.176
How???
How you got 40??
A=11/34
B=40/34
A=11/34, B=20/17
A = 11/34, B = 20/17