my prof said with chain rule to always say "the derivative of the outside times the derivative of the inside" it may make sense. so (stuff)^2 derivative is 2*(stuff) then take derivative of stuff. so 2(stuff) * stuff ' here sin would be cos. 2sin * cos
I praise thy holy salaman kotal khan for his great work in the field of mathamatics. Without his holy butttery voice, I would be but a mere padwan of what I am today
Everyone in the comments talking about math stuff while I'm over here trying to count how many times he said respectively. I'm just over here thinking how much respect is in this video.
I only watched this to review, I already know how the chain rule works, but the way he explained it makes it look more complicated than “derivative of outside when x= inside function, times derivative of the inside”
What is the problem with some college/university teachers. is it laziness? I guess it is pride - it seems they dont want subjects to appear simple, too simple for students to suddenly catch what they spent many years to train for. It is not only right, but an honest thing to "call a spade a spade." Thanks KA!
It's just that you want to find the derivative (i.e. slope of the curve y = f(x)) AT the point x So whatever the point x on the line x squared, it's derivative will be 2 times this point ( i. e. 2x) When I want the derivative of x squared with respect to sinx. I mean this: whatever that point x is, I'm gonna find its sine. the specific value of this sine, I will input it into x squared and see what will be tge slope of line on THAT value. So, I take x, I input it into sin function, I get an output, I input this new output into the x squared function, I get a brand new output, and I want the slope of the line on that specific brand new output. I encourage you to watch composite functions videos from precalculus playlist + revise the intro videos on derivative as a concept
It means that how does one value change with respect to another meaning , how much y will change if x is changed, for example if you derive postion x with respect to time t, then you get velocity meaning that derivative of x with respect to t is v, so when t has changed a little how much did x change or rather by factor did x change, that factor in this case is velocity v
sorry, i feel like you shouldn't have used sin x, and instead just a simpler function. ive learned and understood the chain rule before and came here for a refresher and this didnt help :(
in the case of a linear function (where the function is just multiplying x by a constant) the derivative is just the product of the two derivatives. if f(x) = 5x and g(x) = 10x. then. g(f(x)) = 50x. and (50x)' =. f'(x) * g'(x) = 50 if the outer function is not linear like g(x) = x^2 then the slope changes depending on the input it gets from the inner function f this is why the slope of the g(x) should be evaluated at the same value as it gets from f(x) in other words. (g(f(x)))' = f'(x) *. g'(f(x))
wow super thanks mr.Khan kumar, now i really understand with this thing called chain rule how it work, but still cant visualized it but thanks i clearly know how it works now
The U substitution of inner x terms is simpler 2nd step is finding dU by differentiating U = dU/dx to express everything in x terms So 2 successive differentiations. "Outer and "inner"" Final result expressed as a differential coeff (DC) as a rule
I love you so much ,So wish you could be my math lecturer. you are better tan him. thank you so much I was thinking o changing my course but now never all your video you make math easy and simply
I didn't quite understand what does it mean "With respect to something", And quora and google didn't really help, Can someone help me on this? Edit: I figured it out and it turns out it just means it's the x axis but now it can be substitued as other variables like t, So when it's "with respect to something" it means that the y equation is using that variable as the x
I just uploaded a video where I go through such exercises step-by-step, explaining everything along the way. It might help you. Regarding your question, take this example. 1. The derivative with respect to x of the function x^2 is 2x. 2. The derivative with respect to x of (x+3)^2 needs the chain rule to be solve. 3. The derivative with respect to (x+3) of (x+3)^2 is 2(x+3)
No, it’s not a fraction. However, the way he write the notation can help you to think about the derivatives. They’re not fractions, however it may help you to think about them ‘cancelling’ in this way
When we take the derivative of the function f(x), we write the derivative as dy/dx but Sal wrote the derivative of h(x) as dh/dx . So ain't we supposed to write the derivative of f(x) as df/dx? Please clear my doubt.
@@kshjnbvsmd d(f(h))/dx = 2nd line of 4:10 it’s kind of law. If you differentiate it. You want to differentiate of d(f(h)). Firstly if f(h)= (sinx)^2. That means it’s differentiation will be(d/dx (x^n) *d/dx (x). put here x=sinx.
2:25 isn't it the derivative of the whole function with respect to the inner function sin(x) or are you saying that d/d(sin x) (x^2) = 2 sin x I think it should be d/d(sin x) (sin x)^2 = 2 sin x
It's multiplying the outer function times the inner function. If we see sin x as u, then the original function is u^2. So Sal took the derivative of u^2 and got 2u, which is 2sin x. Then he took the derivative of the inner function, sin x, and got cos x. Therefore, the derivative is 2 sin x cos x.
@@flying_asparagus1279 what i find confusing is why we multiply the differential of the outer function with respect to the inner function, by the differential of the inner function with respect to x. i must have learned chain rule years ago now, but coming back to it i realise ive only memorised how to apply it sort of mechanically and dont have an intuitive understanding in my head of why it works that way. Sal doesnt really explain that in the video but just gives us the easy way out of thinking about it in terms of the leibniz notation with the fractions, but even points out that this isnt mathematically rigorous.
I think he is correct. if you see the upper example. you can replace the Sin x with the a, which is the same x but different x value. the first x is a, and the second x is Sin X.
This left me far more confused than when I started
my prof said with chain rule to always say "the derivative of the outside times the derivative of the inside" it may make sense. so (stuff)^2 derivative is 2*(stuff) then take derivative of stuff. so 2(stuff) * stuff ' here sin would be cos. 2sin * cos
Exactly.. 😥
Well it cleared my doubt even though he wasn't really teaching
MonTV MonTV this cleared it up so much for me, thank you!!!
@@montvmontv117 I understood nothing but “stuff” 😶
I praise thy holy salaman kotal khan for his great work in the field of mathamatics. Without his holy butttery voice, I would be but a mere padwan of what I am today
U play mortal kombat
@@naziasiddiqui8807 U play DN
I sometimes come here to listen to his voice ._. it's soothing makes math Beautiful
Coming here for the first time and I can already see this man having a wave of fangirls
Everyone in the comments talking about math stuff while I'm over here trying to count how many times he said respectively. I'm just over here thinking how much respect is in this video.
I only watched this to review, I already know how the chain rule works, but the way he explained it makes it look more complicated than “derivative of outside when x= inside function, times derivative of the inside”
Any good videos that you thought were a better review?
He just doesn't want us to memorize it thats why he took harder approach
Yeah because he's trying to make you understand why it works. Otherwise you're just memorizing formulas without knowing what they do.
oh my god! my teacher taught me this but never mentioned it's called chain rule. I blindly use this method without knowing what it is for!
What is wrong with your teacher
this video just saved me from failing in Physics. Thanks a lot Sal sir
What is the problem with some college/university teachers. is it laziness? I guess it is pride - it seems they dont want subjects to appear simple, too simple for students to suddenly catch what they spent many years to train for. It is not only right, but an honest thing to "call a spade a spade." Thanks KA!
Still trying to figure out EXACTLY what 'with respect to' means. People always seem to gloss over it or talk around it.
If you differentiate x^2 + y^2 with respect to x you will get 2x while differentiating with respect to y gives 2y
It's just that you want to find the derivative (i.e. slope of the curve y = f(x)) AT the point x
So whatever the point x on the line x squared, it's derivative will be 2 times this point ( i. e. 2x)
When I want the derivative of x squared with respect to sinx. I mean this: whatever that point x is, I'm gonna find its sine. the specific value of this sine, I will input it into x squared and see what will be tge slope of line on THAT value.
So, I take x, I input it into sin function, I get an output, I input this new output into the x squared function, I get a brand new output, and I want the slope of the line on that specific brand new output.
I encourage you to watch composite functions videos from precalculus playlist + revise the intro videos on derivative as a concept
It means that how does one value change with respect to another meaning , how much y will change if x is changed, for example if you derive postion x with respect to time t, then you get velocity meaning that derivative of x with respect to t is v, so when t has changed a little how much did x change or rather by factor did x change, that factor in this case is velocity v
These are some very respectful variables
This planet needs you! Thank you for the learning videos!
Found this channel in grade 12, and I'm coming back to it now in my final year (hopefully) of uni.
sorry, i feel like you shouldn't have used sin x, and instead just a simpler function. ive learned and understood the chain rule before and came here for a refresher and this didnt help :(
(x+y)^2
Or ln(x^2), like I solve step-by-step in my newest video. It might help you understand :)
in the case of a linear function (where the function is just multiplying x by a constant)
the derivative is just the product of the two derivatives.
if f(x) = 5x and g(x) = 10x. then. g(f(x)) = 50x. and (50x)' =. f'(x) * g'(x) = 50
if the outer function is not linear like g(x) = x^2 then the slope changes depending on the
input it gets from the inner function f this is why the slope of the g(x) should be evaluated at the
same value as it gets from f(x)
in other words. (g(f(x)))' = f'(x) *. g'(f(x))
OMG I FINALLY UNDERSTOOD THIS THING THANK U SO MUCH
all those hours in school vs a 5 min yt video... it keeps happening but I keep being amazed
wow super thanks mr.Khan kumar, now i really understand with this thing called chain rule how it work, but still cant visualized it but thanks i clearly know how it works now
The power/chain rule is the saviour of math
Im gonna do great on my test tomorrow
The U substitution of inner x terms is simpler
2nd step is finding dU by differentiating U = dU/dx to express everything in x terms
So 2 successive differentiations. "Outer and "inner""
Final result expressed as a differential coeff (DC) as a rule
dang that actually made sense thx sal
I love you so much ,So wish you could be my math lecturer. you are better tan him. thank you so much I was thinking o changing my course but now never all your video you make math easy and simply
I think the chain rule is easy to explain as a 2 stage amplifier. so (g{f(x))' = f' * g'
dang, he did such a great job.
Perfect explanation.
thank you so much
this is so clear
Love this
thank you. your video is very clearly to understand, I'm sure it will help me pass my mid-term exam tomorrow. lmao
How'd it go?
Ya dude how’d it go
Bruh
2 years later. So how was your graduation?
@@Jorge-125 3 yrs*
😂
That's amazing.
Nice
definitely more confused now 😭
I didn't quite understand what does it mean "With respect to something", And quora and google didn't really help, Can someone help me on this?
Edit: I figured it out and it turns out it just means it's the x axis but now it can be substitued as other variables like t, So when it's "with respect to something" it means that the y equation is using that variable as the x
i don’t either
He's paying his respects to the math gods.... Jk, people always use that term and I still don't know why.
I just uploaded a video where I go through such exercises step-by-step, explaining everything along the way. It might help you. Regarding your question, take this example.
1. The derivative with respect to x of the function x^2 is 2x.
2. The derivative with respect to x of (x+3)^2 needs the chain rule to be solve.
3. The derivative with respect to (x+3) of (x+3)^2 is 2(x+3)
very understandable! thank you!
thank you!
Hi Sal, love your videos. Just need to update it to 1080p, will look sharper on bigger screens.
Watching this on a 27-inch 4k monitor, Never once noticed the quality. The only thing that matters is the content of the video.
Master explanation !
Would you mind not taking too long to get to the point please
If x =at^2 and y=2at, then find d^2y/dx^2. help me with this concept
great work
I don't know that about this
Voice and presentation is good .
It both makes sense and it doesn't make sense...
But to be fair I'm still in trig... I don't know too much about the derivatives...
What is happening here, the math is flowing into me 😁😁😁
this is witchcraft man 👏👏👏👏
respect
Wouldn’t cos x actually be -cos x because the derivative of sin is -cosx
how does one tell composition of functions from single function?
Hello, thank you so much for the video, but I have a question please: did the last notation was really treated as a fraction? Regards.
No, it’s not a fraction. However, the way he write the notation can help you to think about the derivatives. They’re not fractions, however it may help you to think about them ‘cancelling’ in this way
Thank you Andy F
I wish he had used a simpler function instead of sin x
I think this one needs a re-do by the same person
I was stuck in the same question and he that that question only.
2:24 the differentiation of sin X will be cos X
It will be 2sin x as we are finding derivative w.r.t sin x
Great
You do tend to present calculus in a mechanical way and so all the meaning and understanding is missing...
David , hmm
stfu
"Mechanical way"? What?
I actually agree with this. I get very lost in the “derivative x” “du dx” “x x x” He doesn’t give any of it meaning
well that's also likely because this is an intro to the chain rule. he is using terms that he likely already explained in a different video.
When we take the derivative of the function f(x), we write the derivative as dy/dx but Sal wrote the derivative of h(x) as dh/dx . So ain't we supposed to write the derivative of f(x) as df/dx? Please clear my doubt.
It doesn't matter because f(x) and y are the same thing.
Can write it as either
h(x) can have the derivative h’(x) or dh/dx
y=f(x) ->>> y is a function of x
dy/dx ->>> derivative of y with respect to x, same as derivative of f(x) with respect to x or df/dx
What did u say?
Shouldn’t we just use the power rule to get 2 sin(x) and that’s it?!!!
Rola Ahmed yeah I’m confused where the cosx comes in and why
Cos x is the derivative of sin x. It’s weird, but yeah
@@jamessamuel1255 have you got any idea now, im stuck in the same confusion..
@@kshjnbvsmd d(f(h))/dx = 2nd line of 4:10 it’s kind of law. If you differentiate it. You want to differentiate of d(f(h)). Firstly if f(h)= (sinx)^2. That means it’s differentiation will be(d/dx (x^n) *d/dx (x). put here x=sinx.
Yeah, this is confusing me as well. I get that the derivative of sin x is cos x, but where did the second sin x come from in the first place?
I recommend a new intro to this intro.
So I'm still confused as to what the answer is 🤔
You should have used different colour pen
use the chen lu
I feel like I have already seen this video before tho.
Dejavu!!
Aumsum time
why he multiplied with cos x with 2sin x ................ i am stuck up can anyone please help me!
I just uploaded a video where I solve such exercises step-by-step, explaining everything I do along the way. It might help shed some light :)
@@PenandPaperScience 👍
2:25 isn't it the derivative of the whole function with respect to the inner function sin(x)
or are you saying that
d/d(sin x) (x^2) = 2 sin x
I think it should be
d/d(sin x) (sin x)^2 = 2 sin x
differential geometry a first course by d somasundran PDF mein knsi website sy mily GI???
Where does the second "derivative of sin x" come from at 3:06? I thought we had already established that the derivative of (sinx)^2 is 2sinx.
It's multiplying the outer function times the inner function. If we see sin x as u, then the original function is u^2. So Sal took the derivative of u^2 and got 2u, which is 2sin x. Then he took the derivative of the inner function, sin x, and got cos x. Therefore, the derivative is 2 sin x cos x.
Nah mate, 2sinx is just dh/dsinx. We are interested to know dh/dx which is equal to dh/dsinx * dsinx/dx. Hence, the chain rule is applied.
@@flying_asparagus1279 what i find confusing is why we multiply the differential of the outer function with respect to the inner function, by the differential of the inner function with respect to x. i must have learned chain rule years ago now, but coming back to it i realise ive only memorised how to apply it sort of mechanically and dont have an intuitive understanding in my head of why it works that way. Sal doesnt really explain that in the video but just gives us the easy way out of thinking about it in terms of the leibniz notation with the fractions, but even points out that this isnt mathematically rigorous.
2:16 did you make a mistake? the answer should be sin2x, isn't it?
I think he is correct. if you see the upper example. you can replace the Sin x with the a, which is the same x but different x value. the first x is a, and the second x is Sin X.
You are both correct. By the double angle identity, sin(2x) is the same as his answer of 2(sinx)(cosx)
First comment
Yeah lowkey that explanation kinda sucked first L khan academy vid ive seen
Btw this video doesn’t not help me because its very different with my school work as i know chain rule is UV-UV % V square
That may be a quotient rule you are confusing it with - Sal was explaining the chain rule.
That's the quotient rule...
first comments