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The logic I used is in numerator we have 16 digits And in denominator we have 15 digits so possible ans are √1,√4,√9 And from analysing the unit digit we can tell ans is √9 that is 3
Sir I have 1doubt 'If any number has a fractional power and their power will has inverse (ie. reciprocal)then the answer. 2^6/7 then 2^7/6 =?. Make one in this solution and this answer finding fast please sir.
A nice idea no doubt. But it will be pretty difficult in the first place to conceive the numerator as a multiple of .. such as 11 x 99, ... 111 x 999 etc. We can perhaps use an easier trick to quickly arrive at the answer. For example, the sum of the digits of the numerator is 72 which can be divided by 9 (Any number whose sum of the digits is divisible by 9, the number is divisible by 9). Interestingly while doing so, we get the other factor as 123456787654321. As we have in the denominator is same as 123456787654321, it just gets cancelled and we get just 9. And the result is 3.
Sir aapke liye ek question hai from 11th grade starting student, solve kar diye to maan jaunga/ lim x tends to 0 {180*(2-2cosx)^1/2}/x. ( iski value 0 nahi hai)
the limit doesn't exist, like |sin^2(x)| hai na, so +- 180*sqrt(2) aayega limit(like nahi aayega since LHL and RHL are not same, but LHL and RHL ka value ye hai respectively)
I know mathematically the limit does not exist but jab hum practically isme x ki value put karna start karte hai , jo ki 0 ko approach kar rahi hai ,with the help of FULL PRECISION CALCULATER ,you won't believe iski value ek most famous constant ko approach kar rahi hogi.
sir I identified that 1111111088888889=987654301234568+123456787654321. so its1st sum part and 2nd sum part is divisible by denominator which comes out to be (8+1)^1/=3
Numerator has 16 digits, denominator has 15. For part in sqrt, if integer solution exists, it should definitely be less than 10. denominator ends with 1, numerator with 9, only possible integer solution is 9
thumbnail me hi bana leta, par denominator me end me 1 dekha toh video me aaya aur pta chala end me 2 chor views leta ha galat thumbnail daalke gadha , karma hoga tu barbaad hoga
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Sir Why sin 180 degree or >90 degree aer posible?🤔 ak videos banaye ispe
The logic I used is in numerator we have 16 digits
And in denominator we have 15 digits so possible ans are √1,√4,√9
And from analysing the unit digit we can tell ans is √9 that is 3
Genius 😱😱😱😱😱
how exactly did you analysed the unit digit??
did it by seeing that 33^2=1089, 333^2=110889 and so on
Sir pls increase freuqncey of videos❤. Addiction ho gya hai bhannat maths channel ka➗️➕️➖️nasha karna hai toh maths ka karna chahiye.🍷🥂🍷😊😊
dil ki baat bol di bhai
Best teacher ever
❤❤❤
Gjbbbbbbbbbbbbbbbbb sirji... Mjaa aagya aaj kuch nyaa seekh kr❤
Sir ap please jee ADV ke liye chapter wise playlist banao..
Maine dekha ki numerator main 9 hai aur denominator main 1. To maine denominator ko 9 se multiply karne ka try kiya aur solve ho gaya.
Same me
Same here
Can anyone explain me
same
copied
ua-cam.com/video/9YMes-j3ZQc/v-deo.html
Sir what books did you use when you were in 10+2?
Best question ❤❤
Sir please make a video on jensun inequality
It was easy one by doing some manipulation we get answer
Sir ap bohot acca ho ❤
Can a function have two different derivatives
Sir power batch ka planer provide kar dijiye plzzz.
Sir Sigma per ek video please 🥺 sir
Bhot easy tha bina pen uthai hi ho gaya, allen ke notes meh hame aise bhot se ques karaye hue hai
🎉
Sir I have 1doubt 'If any number has a fractional power and their power will has inverse (ie. reciprocal)then the answer. 2^6/7 then 2^7/6 =?. Make one in this solution and this answer finding fast please sir.
Sir jee advance ke problem layiye sir please
Given X+1/X=√3 find the value of x^100+1/x^100=? Please 🙏🙏🙏 sir questions par video banaye
Super🎉🎉🎉🎉🎉concept
A nice idea no doubt. But it will be pretty difficult in the first place to conceive the numerator as a multiple of .. such as 11 x 99, ... 111 x 999 etc. We can perhaps use an easier trick to quickly arrive at the answer. For example, the sum of the digits of the numerator is 72 which can be divided by 9 (Any number whose sum of the digits is divisible by 9, the number is divisible by 9). Interestingly while doing so, we get the other factor as 123456787654321. As we have in the denominator is same as 123456787654321, it just gets cancelled and we get just 9. And the result is 3.
These questions are getting too dank for me.
Sir aapke liye ek question hai from 11th grade starting student, solve kar diye to maan jaunga/ lim x tends to 0 {180*(2-2cosx)^1/2}/x. ( iski value 0 nahi hai)
the limit doesn't exist, like |sin^2(x)| hai na, so +- 180*sqrt(2) aayega limit(like nahi aayega since LHL and RHL are not same, but LHL and RHL ka value ye hai respectively)
I know mathematically the limit does not exist but jab hum practically isme x ki value put karna start karte hai , jo ki 0 ko approach kar rahi hai ,with the help of FULL PRECISION CALCULATER ,you won't believe iski value ek most famous constant ko approach kar rahi hogi.
Sir Maine to is questions ko class 8 ke concepts se solve kar diya
Sir ke glasses: 🗿🫡
Sir jee k liye question practice ki maths ki best book konsi h please bataye❤❤❤❤❤
Arihant's Prilepko, AD Gupta MCQs
Maine ese hi dekhliya ki niche wali term ko 9 se multiply karne se upar wali term arah hai 😅
Sir please riemann hypothesis ke upr video banayie🙏
@@arandomfish9630 Bhai mein college mein hue
Sir nda 2024 question paper solution karwaiye please
nice
I did it...❤
Sir, are you leave pw
Sir I knew that 33²=1089,333²=110889,3333²=11108889 that's how I solved this
BTW thank you sir ❤❤
Bhai itne sare numbers ke square yad rkte ho 333 tak tumhe malum hai kaise mind mein click krta hai bhai
@@Dx_Era_31bhai koi yaad nahi karna hai bas pattern dimag mein apne aap baith jata hai
🤯😎
Sir red 🕶️ op 💀👍🏻
Right ans 9.5 hi
I solved it myself😊😊
sir mene toh claculator use kar ke 20 sec me nikal diya
No pattern needed
I tried to solve the question writen on the thumbnail and failed, because of the error
This is from Japanese Olympiad exam
bas 2 number pattern jaankar hi 99% logo se alag ho sakte hai hum
Main screen pe to 2 ki 1 dikha Raha hai
Bhot easy tha
2nd pattern 7th class me aata hai
😢f f(x)=cosxcos2xcos4xcos(8x).cos16x then find f'(π4) please ye question kra lo
Sir itna ruk ruk ke kyu bol rhe hai
Ek dm bannat
sir I identified that 1111111088888889=987654301234568+123456787654321. so its1st sum part and 2nd sum part is divisible by denominator which comes out to be (8+1)^1/=3
Easy
Hello sir
Please aap karwaiye aap feel karwaiye
3
Numerator has 16 digits, denominator has 15. For part in sqrt, if integer solution exists, it should definitely be less than 10. denominator ends with 1, numerator with 9, only possible integer solution is 9
I Solve this question in less than 1 minute because I know both patterns 😊
brh doesnt even now grammar
@@voiceoverwithbhaGYA9287 my English is weak 😅
You too 😂😂😂😂 @@voiceoverwithbhaGYA9287
@@voiceoverwithbhaGYA9287Same can be said for you.😂
@@Amit_368Bbhai ye pattern kaise yaad rkte ho tumhe kaise click kara yeshe hoga
Ye to Mayne dimak me kar diya
mene khud se solve kiya sir
Kaise kiya bhai batao
Sir do you teach class 9 maths also ?
Who see last digit of denominator and numeritor is 1 & 9 so ans is 3 ,
POV : we all are JEE Aspirant 💀💀
I also do this...
@@SwagatikaPriyadarshini606 hey are you jee aspirant
@@listenme98 yes
@@SwagatikaPriyadarshini606 class?
12th
First view sir❤
1+1+1+1+1+1+1 = 7
Thala for a reason
Thumbnail thik karlo plz
Wahi to bat hai bhai actual me 10 percent log v nahi kar par honge par comment sare mathematician karne aaye hai
πlakh subscribers
copied from AyaansMath
ua-cam.com/video/9YMes-j3ZQc/v-deo.html
Bro ur solution is so much different. U used variables and sir used number patterns. Dont put false allegations pls
first comment
Not flexing but maine 30 seconds mein orally ho gaya
Don't even need 30 seconds if you know the pattern already
thumbnail me hi bana leta, par denominator me end me 1 dekha toh video me aaya aur pta chala end me 2
chor views leta ha galat thumbnail daalke gadha ,
karma hoga
tu barbaad hoga
Bili jaisi aankho ne muje like kar dia
👍🏻👐🏻👍🏻
Sir red 🕶️ op 💀👍🏻
Sir red 🕶️ op 💀👍🏻