F2 has no moment in the clockwise direction but rather in the anticlockwise. So it has no distance in that direction, then, F2 x 0 = 0 considering the clockwise direction.
Welcome, Chisom. There are no figures in the moment 1 video. If it is moment 2, I think we didn't add 20 and 30. Please check again and get back to me. Correction: There was an arithmetic error in the later part of moment 3 and we made the corrections in the comments below. Thank you.
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Best teacher of physics ever
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Thank you sir and I must confess that my 10 years difficulty is over in few minutes. I salute you,sir
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LIFE SAVER 💗💗 , MY TEACHER COULDNT EXPLAIN IT BC HE SUCKS🥲
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Really grateful for this sir..m so happy i didn't skip
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Good work sir
Very informative, thanks for demystifying moment
Thank you ....very informative
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6:31😂
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Good morning, can you say the perpendicular distance from the force to the pivot is zero and so f×0=0
F2 has no moment in the clockwise direction but rather in the anticlockwise. So it has no distance in that direction, then, F2 x 0 = 0 considering the clockwise direction.
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Please why'd you add 20 and 30 I thought you would subtract
Welcome, Chisom.
There are no figures in the moment 1 video.
If it is moment 2, I think we didn't add 20 and 30.
Please check again and get back to me.
Correction: There was an arithmetic error in the later part of moment 3 and we made the corrections in the comments below.
Thank you.
Thank you sir
Welcome
Miriam, where are u watching from?
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Your smile along kills the topic
Really grateful for this sir..m so happy i didn't skip🥰
Really grateful for this sir..m so happy i didn't skip🥰
Great 👍