Further into Inductors | They're the magnetic analog of capacitors! | Doc Physics

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  • Опубліковано 19 лис 2024

КОМЕНТАРІ • 56

  • @Stannaboy
    @Stannaboy 8 років тому +30

    U dont deserve to be a high school teacher Doc..... U deserve to teach at a university... Your explanation is better than my lecturer's explanation 10 times

  • @carterboelke6201
    @carterboelke6201 6 років тому +3

    Your teaching style is engaging, inspiring, passionate, and well thought out. Thank you.

  • @arcillaguiab
    @arcillaguiab 10 років тому +4

    oh gosh so helpful! you have so much character when you talk it keeps me focused :) thank you doc!

  • @JbalanceT
    @JbalanceT 6 років тому

    The first person that i see what know to teach. I m glad to watch yours videos.

  • @DocSchuster
    @DocSchuster  11 років тому +1

    Oooh, nice. No problem with that at all. However, you must acknowledge the two simultaneous effects of more resistance: not only is the final current smaller, you'll get to 63% of it faster, which defines tau. From a physics perspective, it feels great, since resistance decreases the inductor's ability to prevent its flux changing. A superconducting coil NEVER gets to 63% of its final current (infinity)!
    I appreciate your perspective greatly! I hope my in-class students consider it too.

  • @powertube5671
    @powertube5671 5 років тому +1

    Nice lesson. BTW, since current doesn't like to just stop, when you open the switch abruptly, it will arc and you will get a nice EM pulse that can be heard on an AM radio.

  • @ajay192837465
    @ajay192837465 9 років тому +6

    WELL U ACTUALLY WROTE THE CORRECT FORMULA OF THE INDUCTANCE IN A SOLENOID(AT 9:30). I GUESS ariaghafari73 WOULD BE CORRECT IF THERE WAS "N" INSTEAD OF "n". U HAVE DEFINED IN THE PREVIOUS VIDEO U HAVE DEFINED """"""n= N/l. DO U REMEMBER THAT DOC. BETTER CHECK IT AGAIN. But as the other videos ur explanation was rocking. THANK DOC FOR THE HELP.........

  • @edvargas3105
    @edvargas3105 3 роки тому

    Doc Shuster you are Brilliant!!!

  • @nadiaasimohamed6663
    @nadiaasimohamed6663 8 років тому +4

    can you please please replace my lecturer ? omg youre so good ! thanks for sharing the knowledge on this !

  • @haajarnihal1579
    @haajarnihal1579 10 років тому +2

    your explanation is easy to understand .. i want to know the relation of inductor and EMF .. 'BACK EMF' ..

  • @marcos3865
    @marcos3865 3 роки тому

    I really love your videos,
    From Italy 👍🏻

  • @sanjayd411
    @sanjayd411 5 років тому

    Perfectly explained. 👍👍

  • @rubyf1993
    @rubyf1993 9 років тому +5

    Hey, great videos. Do you have something about mutual induction?

    • @MahinMundra
      @MahinMundra 9 років тому +3

      yes please. mutual inductance.

  • @savvyfavy5805
    @savvyfavy5805 9 років тому +2

    I agree with Mv Dk - I think you were initially correct at 9:30 when you used n instead of N, and defined n as N/l. Please remove that pop up note if you're already correct!

  • @CE113378
    @CE113378 9 років тому

    As long as you are pointing out symmetry, when you derive the energy densities, why not use H instead of B? u = 1/2 mu0 H^2. u = 1/2 eps0 E^2. After all, B is magnetic flux density, and H is magnetic field intensity. E is electric field intensity. Also, you got the inductance of the solenoid right (9:28). Great video.

  • @jamesleem.d.7442
    @jamesleem.d.7442 6 років тому

    Good stuff.

  • @dillonberger4036
    @dillonberger4036 10 років тому +3

    Hand wavy at 6:49 derivation of potential energy derivation. SOLVE THE DIFFERENTIAL EQUATION LIKE A MAN DOC!!!!!!!!!!!!!!!!

    • @DocSchuster
      @DocSchuster  10 років тому +6

      Dillon Berger That's the best advice I've had all week!

  • @ariaghafari73
    @ariaghafari73 9 років тому +2

    At 9:30, you asid the inductance of a solenoid is u*n^2*A*L, when it's actually u*n^2*A/L

    • @9797cleo
      @9797cleo 8 років тому +1

      +ariaghafari73 If L=(𝜇𝑜N^(2)A)/l and n=N/l , then it should be L=𝜇𝑜n^(2)Al? Please point it out if I am wrong :)

    • @anirudhtammireddy464
      @anirudhtammireddy464 7 років тому

      i'm confused too..
      i support 9797cleo

  • @Sumpinsfishie1
    @Sumpinsfishie1 11 років тому +1

    I have a question that is not directly related to this video. Ok, so an inductor induces voltage to another inductor/coil. Current in the secondary would produce a magnetic field, right? Wouldn't that induce a smaller amount of EMF into the primary side?

    • @DocSchuster
      @DocSchuster  11 років тому +1

      Yep! That, in turn, would induce a current in the second coil. Are you following the directions of all these induced currents? Very often, we find something very complicated happening in physics and we decide carefully how many times we want to pay attention to the accumulated, but weakening effect. In fact, the advanced technique of perturbation theory uses this exact principle to zero in on the most important parts of a problem. Good work.

  • @felitchiia
    @felitchiia 10 років тому

    Hello, enjoying greatly your videos. Your enthusiasm keeps it fun!
    Tough, (at 14:50) shouldn't it be that the current has fallen by 37% at time=tau?

  • @HaniYahya9
    @HaniYahya9 10 років тому

    When you say the current takes a long time to pass through the inductors if we close or open a circuit, how fast is it in our normal seconds? is it few seconds or years or days or what?
    Thanks

    • @DocSchuster
      @DocSchuster  10 років тому +2

      It depends on the resistance of the coil. Do some more research into "time constants." I have a video on exponential decay that might help...

  • @alfredcentauri
    @alfredcentauri 9 років тому

    Please reconsider the solution given for opening the switch after a long time (13:00). When the switch is opened, there is no path for inductor current. Put another way, with the switch open, the time constant is zero since the open switch is in series with the resistor. If you don't find this convincing, then consider simulating in SPICE or equivalent.

  • @schwabbie123
    @schwabbie123 9 років тому +15

    WHY YOU SAY SQUUUURED INSTEAD OF SQUARED?!?!

    • @mikeck1
      @mikeck1 7 років тому +4

      ffs i know. He saw it on a calculator i guess and loved it.. SQR

  • @SparkFastt
    @SparkFastt 11 років тому

    Tau being inversely proportional to the resistance is counter-intuitive. Would it make more sense to say that with a larger resistor, you will have a smaller I_final? Mathematically this would be shown as R=Vbatt/I_final ---> Tau= L*I_final/Vbatt

  • @HM-dm3qg
    @HM-dm3qg 6 років тому

    Is that table made of muskmelon?

  • @samshen6755
    @samshen6755 8 років тому +1

    too good!!! best video ever. Which University are you attending as a professor? I need to apply that

    • @DocSchuster
      @DocSchuster  8 років тому +2

      +Sam Shen Thanks for your kind words. I'm a high school teacher.

    • @devilkanan
      @devilkanan 8 років тому +1

      +Doc Schuster I'm willing to join high school again for all this awesomeness. :D

    • @amondevecasones1929
      @amondevecasones1929 8 років тому

      +Doc Schuster WAW

  • @mihirbpi
    @mihirbpi 5 років тому

    mu not times epsilon not is c so the energy density of an electric field has an extra c compared to the energy density of a magnetic field. Where c is the speed of light so another hint to how electricity and magnetism are related by the speed of light as Maxwell showed.

  • @jeanpierredaviau7478
    @jeanpierredaviau7478 6 років тому

    An action of current creates a reaction from the inductor. (similar to
    Newton 3 law)

  • @anuragyadav_8572
    @anuragyadav_8572 5 років тому

    please explain how t(tau) = L/R.

  • @evanlitho9003
    @evanlitho9003 8 років тому

    what does mew not stand for?

    • @wedmunds
      @wedmunds 7 років тому

      Vacuum permeability constant (mu-naught).
      Epsilon-naught is vacuum permittivity constant.
      One is for magnetic field, the other for electric.

  • @MastaChief10
    @MastaChief10 8 років тому

    if you could not use the lagrange L that'd be great, other than that helpful vid :)

    • @wedmunds
      @wedmunds 7 років тому

      It was supposed to be a fancy i :)

  • @HM-dm3qg
    @HM-dm3qg 6 років тому

    You definately need an outro with a song. The way you are so energetic, a plain ending doesn't seems good. Add probably rap at the end. Jk....I am binge watching all of your videos. Better than Netflix!!!

  • @bjl1000
    @bjl1000 7 років тому

    except capacitors hold a charge a lot longer.

  • @patryk_49
    @patryk_49 6 років тому

    So it was actually L that looks like a Z, what a plot twist.

  • @lamborghinilambo7064
    @lamborghinilambo7064 8 років тому

    Be my physics teacher I will pay u billions

  • @lucasmorrison701
    @lucasmorrison701 10 років тому +6

    Great series, just stop saying "squr"!

    • @kpgngr
      @kpgngr 9 років тому +8

      Lucas Morrison squr is the best part!

    • @savvyfavy5805
      @savvyfavy5805 9 років тому +2

      Lucas Morrison That's my favorite part!

  • @CE113378
    @CE113378 9 років тому

    Around 14:xx-ish, you have a real problem once you open up that switch. Your switch is in series with your inductor! You opened a switch that was in series with an inductor that already had current flowing through it! ARGH! So, your analysis is fine, except that your R is not merely the R of the resistor, but the R of that open circuit of the switch (a really big freaking R when the switch is open - ideally around infinity). Thus, your tau is zero seconds, and that current goes away "instantly" (in a exponential decay of course with a tau of zero seconds). Otherwise, you end up with a KCL crisis. If you did this in the lab and were observing the current on an oscilloscope, and if you didn't know better, you might be thinking, "Where is my time constant!?!?!"

    • @CE113378
      @CE113378 9 років тому

      Dan Hillman To clarify, the initial current when you open the switch is V/R. But the R used in the time constant is tau = L / (R+Rbig) = 0, since Rbig --> infinity.

  • @audreyandremington5265
    @audreyandremington5265 4 роки тому

    scwere

  • @siminedelcu2874
    @siminedelcu2874 6 років тому

    Teoretic very,very weeeel!Practic....desastre!!!

  • @tboneproductions2453
    @tboneproductions2453 5 років тому

    So you’re saying an inductor is like a woman, it doesn’t know what it wants. Lol