Sir I have a question to ask from you of statistics..... Find the missing frequencies in the following distribution, if the sum of frequencies is 120 and the mean is 50. Class 0 - 20 frequency 17 class 20 - 40 frequency F1 class 40 - 60 frequency 32 class 60 - 80 frequency F2 class 80 - 100 frequency 19
Just an extra point : In rs Agarwal it is written that when the degree of a polynomial is 4 then the polynomial is called "biquadratic" It was not mentioned in the video so I thought I should tell you guys
Sir #8 question me ham agar dono equations ko or solve kare to Equation 1 =4p+r=-10 Or Equation 2 =p+4r=-10 hoga To dono ke rhs equal he So on equalising the LHS WE get 4p+r=p+4r =4p-p=4r-r So,3p=3r And 3 wil get cancelled out from both So,p=r An easier way to do the same question😊
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We will get x=2 after putting the value in your given equation -- (2)²-3(2)+2 = 4-6+2 =0 We can say that after putting the value of x the answer we get is 0 so (x-2) is a factor of your given information.
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Sir I have a question to ask from you of statistics.....
Find the missing frequencies in the following distribution, if the sum of frequencies is 120 and the mean is 50. Class 0 - 20 frequency 17 class 20 - 40 frequency F1 class 40 - 60 frequency 32 class 60 - 80 frequency F2 class 80 - 100 frequency 19
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Just an extra point :
In rs Agarwal it is written that when the degree of a polynomial is 4 then the polynomial is called "biquadratic"
It was not mentioned in the video so I thought I should tell you guys
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#8 question me ham agar dono equations ko or solve kare to
Equation 1 =4p+r=-10
Or
Equation 2 =p+4r=-10 hoga
To dono ke rhs equal he
So on equalising the LHS
WE get
4p+r=p+4r
=4p-p=4r-r
So,3p=3r
And 3 wil get cancelled out from both
So,p=r
An easier way to do the same question😊
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Please solve this question sir
x²-3x+2 by x-2
We will get x=2 after putting the value in your given equation --
(2)²-3(2)+2 = 4-6+2 =0
We can say that after putting the value of x the answer we get is 0 so (x-2) is a factor of your given information.
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