Here's a Question! - Finger in a Cup
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- Опубліковано 19 гру 2022
- A cup of water is placed on a digital scale. Steve puts his finger in the water without touching the cup. What happens to the reading displayed on the scale?
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#archimedesprinciple #buoyancy #newtonsthirdlaw #actionreaction #heresaquestion
What? I did not see that coming. I would have thought this was easy.
I thought because of the force from the mass of the finger is at your feet, or rear if sitting, that the scale would not change.
My knowledge when it comes to these kind of buoyant forces is lacking. Thanks for helping to change that.
WOW, didn’t expect that! Very cool experiment!!
I answered currently!
Although, to be honest, a part of my brain was yelling "idiot, it'll stay the same".
After putting the finger in water, you ousted same volume of water. So this volume of water now is placed in cup on more height than before. So it has more weight (in terms of force of gravity cause it depends on height) and is pushing on scalse with more force.
But maybe this effect have less influence on scale
Forgive me if I'm misreading this, but the displaced water doesn't have a greater weight. In fact, it has less weight (very slightly) since it is (very slightly) further from the center of the Earth. Since it isn't floating, the finger is displacing an amount of water equal to its volume (which causes the level to rise). The mass registered by the scale increased by about 13 grams, so we would get the same effect if we poured an additional 13 mL of water in the cup. The level would rise by the same amount, and the scale would show the same amount of increase.
Do you think there is some energy lost like shocks in a car? Or is it even like that for shocks? Lol im not that read up on my physics
Sorry, but I'm not sure how your comment relates to this video.
Never would have guessed that buoyancy was a factor.
What would be the quantitative value equivalent to?
Will it be the weight of water displaced?
Yes.
or the finger would come out wet?
❤️ u sir 🥺
Why not Steve's full body weight added to the water weight?
Because Steve's full body weight isn't being supported by the water. So, sure, if Steve could somehow climb into the cup, then the scale would register his full mass. However, the only thing the cup is 'aware' of is the bit of Steve's finger that's in the water. It doesn't know that there's a whole person attached to it. And, keep in mind that it isn't the mass of the finger that's registering on the scale. It's the mass of the water that's being displaced. As someone else mentioned in the comments, if the finger were hollow or made out of lead, the results would be the same. At least, as long as it remains supported from the outside. Drop it in the cup and the full mass would register (just like if Steve were able to climb into the cup).
i got it.
How to measure volumes with a scale.
:o)
I picked D, but my heart wasn't really in it. 😏
...thanks?
So it increased by exactly 13g, does that mean his finger up to that knuckle he inserted it to weighs that exact amount? That seems quite light, so I guess not. Only one way to find out! *Gets out meat cleaver.*
I think Steve would rather be electrocuted.
That's the weight of the amount of water displaced. If his finger was completely hollow or made of solid lead, the scales would show the same number.
Let's not be too hasty... Loss of a finger probably wins out over loss of everything.
@@JeffersonLab How long does the pain last, though? (NOT suggesting an experiment!)
Of electrocution? Worst case, the rest of his life.