Thanks for sharing. But I think, for the 2nd question, the least value of x must be 6 since x must contain both 2 and 3. The other possible values of x should be 12 and 32.
In the second question how only the three solutions are all solutions of x, u can multiply x with any other prime numbers, it hasn't any problem on the HCF.
Its impossible x to be 3 right? Since the HCF is 6 When x is 3,this immediately changes the HCF from 6 into 3 Same goes to 33 as well. Point me out if im wrong
Thanks for sharing. But I think, for the 2nd question, the least value of x must be 6 since x must contain both 2 and 3. The other possible values of x should be 12 and 32.
6 being HCF, possible values of x can't be just 3 ; and other multiples of just 3 which are not multiples of 6
It was helpful but 3 can't be the highest common factor of 6 bro.....thanks
thank you very much for this, you are a life saver, and i dont know what i would have done without you.
In the second question how only the three solutions are all solutions of x, u can multiply x with any other prime numbers, it hasn't any problem on the HCF.
Thanks 🙏
Sir you are a legend........ thank you so much ......
Asian boiii is going hard on mathsss boiii
ABSOLUTE LIFE SAVER
hello, this is very helpful, except i dont understand why you put 3 squared
We require the greatest value in power
The greatest power makes up lcm
thank you very much
Ty, this helped a lot
Its impossible x to be 3 right?
Since the HCF is 6
When x is 3,this immediately changes the HCF from 6 into 3
Same goes to 33 as well.
Point me out if im wrong
Can you rationally explain why its wrong?
If x=3,the hcf will not be 6 instead it will be 3
And how will you send it to me?
Please proceed
Sorry?