150+ Marks Guaranteed: MOTION IN A STRAIGHT LINE | Quick Revision 1 Shot | Physics for NEET
Вставка
- Опубліковано 5 лис 2024
- ✨ Playlist ✨
• Complete Chemistry In...
• Complete Physics In On...
• Complete Zoology In On...
• Complete Botany In One...
• Zoology : NCERT Line b...
• Botany : NCERT Line by...
• Uthaan NEET 2024 | Com...
• Uthaan NEET 2024 | Com...
• Uthaan NEET 2024 | Com...
• Uthaan NEET 2024 | Com...
✨ Links ✨
📕Uthaan NEET 2024 Batch : physicswallah....
📕 Prachand NEET 2024 Batch: physicswallah....
📲 PW App/ Website: bit.ly/PWAPP_YT
📚 PW Store: bit.ly/Store_PW
🌐 Yakeen NEET Telegram: t.me/pw_yakeen...
☎️ For any Queries or Complaints visit: bit.ly/PW_Queries OR give a Missed Call on 07019-243-492
#NEET #UthaanNEET2024 #NEETDropper #motioninastraightline #neetphysicsoneshot
#motioninastraightlineoneshot
Good luck with your studies! 🎓✨
📕Get All DPPs & Pdf: Uthaan NEET 2024 Batch : physicswallah.onelink.me/ZAZB/senpv6z6
🌐 Yakeen NEET Telegram: t.me/pw_yakeendropper
Sir plzz jyada question krvaya kro
Theory to hm revise krke Ata h
Ap bss question krvaya kro
Nice video
@@GugleNaru
@frettymedic
Muja zero
1:03:07 - solution → 1:4:9:16 → ye ratio lagana hai
so, t=2s se t=4s → h1 = 16x - 4x
h1 = 12x
similarly, t=6s to t=8s → h2 = 64x - 36x
h2 = 28x
so, h2/h1 = 28/12 = 7/3 = 2.33
therefore h2 = 2.33 h1 ☺
2to4s 3h 6to8s 7h
H2/h1 7/3
thank you so much
😂sahi h@@Swadesh1
Thanks bro ❤
♥
29:04- Avg speed =6m/s
1:03:09- If we take distance in first 2 sec be h
Then h1=3h and h2=7h
So , h2=2.33h1 (B)
Slide -46-C (aa gaya)
1:11:35-khel Gaye sir
1:23:08-C , velocity after 3 second=120m/s. , velocity after 5 second= 100m/s
Taking ratio V3/V5= x+1/x= 6/5=5+1/5,. So, x=5
1:30:52-B(aa gaya)
1:41:11 - 1-B
Slide72 2-D
3-C
4-accelerated motion (non uniform)
Slide - 73- 60m/s
Slide-75-D
1:47:44-(slide -79) -A
1:56:25-D,relative velocity=40m/s,
t=8sec , length of train=40×8=320m
1:56:56 (slide-87)-C
Slide 73 ka 50 ayega Bhai , final minus initial karke
60m/s sahi hai
Vai slide 87 Thora explain Karo GE pls
@@Lunchu0602 dekho 3rd equation of motion lagao bs velocity ki jagah relative velocity le lo which is (V1- V2) ...PHIR AGAR stopping distance jyda hoga to collision nhi hoga ... condition satisfied by option c only hence vhi answer hai
Mr sawal phod diya😂🥲
1:07:12
Solution
let's the time is t-t'
So pahle u= 0 se Vmax tak 1st eq of motion apply koro
Vmax= 0 + alpha(t-t'). { eq no. 1}
And equate it with Vmax formula
Vmax= alpha.ß/alpha+ß ×t =alpha(t-t') { from eq 1}
alpha cancel hoga and t-t' is our required time = ßt/alpha+ß
Bhai fir t kha gya
Thanks bro
@@pubgkillers2712are usne ye mana h ki (t-t') wo time h jo max vel attain karne me laga toh isiliye is pure term ki value nikal na h
Wah bhai great
great brother
Slide 89:
For train A total distance= 61l
Hence tA= 61l/30...........1
Similarly for train B
Tb= 64l/ 20............2
Dividing 1 and 2
122tb=192 ta
Now tB=TA+35
We will have Ta =61
Putting again in eq 1
l=30
And L=60*30=1800
Thank you
thnx🎉🎉
at 1:01:01 ans. should be 240
as next 7 sec is written
Yes
Yes
Hn yarr
Ha
Yes , flow flow main glt ho gya sir ji se 😊
1:55:02 Slide -86 Ans.(D) 320m
X= Velocity x time
Velocity in m/s of train -A --> 25m/s
and of train B --> 15m/s
both moving in opposite direction so velocity add 25 + 15 = 40m/s
time = 8sec (given)
X = 40 x 8
X (Length) =320m
Explain 😅
sem sem kiya
@@Gariyasee1611 okay
Fir length of train A ky hogi .
Ye toh total length aa gyi na
ABKI BAR 700 PAR ...JAI MAA SARASWATI...TYSM SIR....ITS COMPETITION WITH MYSELF ❤️❤️🥰🙆🏻♀️🤗
Jai na Saraswati
Jai ma saraswati
Next yr babe😉
Jay ma swarasati
@@Bittumandal-fz8ro babe apni maa ko bolna
1:07:49
Vmax = a t1 = B t 2
Also;
V max = aBt/ a+B
We have to find the time after which the car decelerates i.e. find t1
So, equating the two eqn for vmax,
at1 = aBt/a+B
Hence t1 = Bt/a+B (C correct option)
Slide 46
@@MbbsMD-r1m sahi hai👍
Thanks🌹
Best of luck to all the Neet aspirants, I wish you all will Achieve something great in life 🔥🍀❤
Best wish ever bro 🙏✨
I😅
1:34:53 slide 66. Ans :-125m
Time taken by mass to strikes the ground=u/g+√u²/g²+2H/g
=1+√1+15
=1+4
=5sec
So height=75+10×5
=75+50
=125m👍🏻👍🏻
yes bro i got it
Ni ek baat btana jbb ye pbject drop kiya tha tbb ye ground se 75m pe tha
Question me pucha h ki height from ground when the object hits the ground
So
Distance from ground is 75+125 =200
@@debasispanda2006aree nhi yrr 5 sec jb object move krega tab balloon 🎈 S=ut=10×5 move krega so 75+50=125👍
Shi h
@@debasispanda2006bhai actually yai uniform velocity sai upar jaa raha ha … g neglect hogi aur iski khud ki acceleration zero hogi bcz uniform velocity… isss liya S = ut hoga … 5 sec mai yai 50 he upar Jaya ga so, 50 +75 = 125 answer ✅
1:07:38
a=acc.
b=retardation
t=total time of journey
t'=time in which it attains max. velocity
Vmax=(ab/a+b)*t
Using eq. of motion
v=u+at
(ab/a+b)*t=0+at'
t'=(b/a+b)t
thanks bro
@suman Thanku
Thanksssss
Thanks
Thank you so much
LET'S RUN FOR AITS 🌟
Yeh PW wale selection karwake hi manenge ❤
Nhi hone dena chahte kya
Inshallah ❤❤😊
TERKO LENA NII KYA
Bhai aap ko kya problem hai aapko selection nhi Lena to mat padho jabardasti thodi kar rhe pw wale😊😊❤
Kisi ke pass mr sir ki made easy pdf hai kya 🥲 muje chahiye time nahi hai likhne ka abhi bahot chap baki hai
1:56:25 ...lb= 320 metre
As train A is moving with 90km/hr which means 25m/s this velocity will be shared to the passenger ...Va=25m/s
Now velocity ( Vb)=15m/s
Their relative velocity of passenger and train B will be added so we get VBa= 40m/s
Now as the passenger is like k person on the ground
So T= lb/v relative
8= lb/40
Lb= 320 m answer
❤❤❤
Time toh {L(B)+ L(A)}/ V1 + V2 tha na?
1:07:50 silde 46 answer
at'= b(t-t')
at'= bt-bt'
(a+b)t'=bt
so t'= bt/(a+b)
explanation: jis time alpha khatam hoga usi time beta retardation shuru hoga. and usi time velocity maximum hoga.
so let that time is t'
and we know at1=bt2
and jo retard hoke rest tak pahucha use hum ulta v soch sakte hai that woh v zero se accelerate hoke us point tak aya jaha pe velocity max hai
so putting the value of t' in above equation
at'= b(t-t')
at'= bt-bt'
(a+b)t'=bt
so t'= bt/(a+b)
@AnuraagPw
Bhai 1:01:00 wala question dekh vo glt lg rha wahan 240m hona chahiye na
@@Adarsh_chahar yes 80×3 hona chahiye.
agar total puchhta toh 320 ata
240 hona chahiye answer
V max ka formula laga ke at1=(ab/a+b) ×t then, t1=(b/a+b) t🙂🌿💚
@AnuraagPw ako ebar bujai dibo pariba neki?
❤
1:07:39. Slide 46 case of rest to rest motion
Total time T=t1+t2
t1= time in which distance covered with alpha acceleration
t2 = time in which distance covered with beta acceleration
t2/t1=alpha /beta -------(1)
Vmax= alpha t1
From equation (1)
t2=t1[alpha/beta]------(2)
Putting value from (2) in t1+t2=T
t1=Tbeta/alpha +beta
Thnx❤
Wow nice
T =t1+t2
SO , t1/t2 =BETA /ALPHA
BUT IF WE TAKE t1 = beta t2/alpha...and put in value [from 2]
So t2 equal to alpha t/alpha +beta
1:22:51 u=150 after three seconds v=120(mr*) after 5 second v=100 Thus V3s/V5s =x+1/x =5
-gt liya kya & kyu i mean 15 s ko stop hoga na?
1:41:13
1) B-uniform motion
2) D-constant acceleration
3) C-retardation
4) Non-uniform acceleration
Yes i am satisfied with your answer
By chance 4th match the column answer not given in table but you correct
😊😊😊
1:41:00 ✓1-b 2-d
3-c 4-accelerated motion
slide 86
Va = 90km/hr = 25m/s
Vb = 54km/hr = 15m/s
relative velocity = Va - Vb = 25- (-15) = 40m/s
length of train = vt
= 40*8 = 320m
is this Right ?
Niche phoolo ki dukan upr Gori ka makan 8:56
Copied😂
Sams
Same
Same
Yes
1:44:01 MR* (Distance>displacement)
Hence Distance/displacement>1
Only fourth
1:21:55 pen uthaoge to paap padega😂
Aayudh sir ❤😂
1:02:36 MR* let 0 to 2sec x distance travelled
2 to 4sec h1--------(1)
4 to 6sec y distance
6 to 8sec h2-----(2)
h1/h2=3/7
h2=2.33h1
MR fod diya😊😊❤❤
3/7 kaise
@@Sana-mb7pv1st second:2nd second:3rd second:4th second=1:3:5:7
@@Sana-mb7pv
MR* Galileo ratio❤️
Bhaiya arjuna batch mai likhaya tha ki ratio 1 second fhir 2 second fhir 3 second k liye 1:4:9... hoga per 1st second 2nd second 3rdsecond k liye 1:3:5 ... toh konsa sahi hai aap logo ne jaise kiya hai uss hisab se humhe ulta parhaya gaya hai@ayanmemon__271oo
@@utkarsh6969aree I had same confusion in 11th dekho......1:3:5 ratio displacement in 1st second displacement in 2nd second .....3rd 4th and so on k liye hora h mtlb 1 1 second ka displacement ka ratio h. ....or 1:4:9 displacement in 1 second displacement in 2 seconds displacement in 3 seconds mtlb 1 sec se lekar 2sec tk je displacement ka 1 se lekar 3 second ke displacement and so on.
Ka ratio h
1:29:54 option d correct t¹=t²
~uniformilililili~
1:32:18 distance=20m then mango will come to ground in 2second..
As ncc cadet's have uniform speed then there acceleration must be zero therefore distance=speed*time =2.5*2=5m🙏✍
Bro kese bata chn ka t ko can u plse explain it will be a great helpp
Bina pen chalaya kra hu mai 😂
@@_Exusiai_ s=ut+1/2at^2
u=o
so s=1/2 at^2
19.6= 1/2 *9.8* t^2
on solving t^2=4 which means t=2s
now, distance= speed*time
= 2.5 * 2
= 5 m
Salute bruhh mughe i thought sabse gadhi mai hu nta vale nikal ke fek na de exam se phele
@@manormadevi8571nahi di aap akele nahi ho..
Slide 56
V=u-gt :- v = 150-10×3 = 120m/s
As it is time 5sec :- v= 100m/s
120/100= x+1/x = 5 ans c
Omg❤
Energy ✅
Quality content✅
Questions ✅
Confidence ✅✅
Aisa content kahi aur milna aur vo bhi in such a less time is next to impossible..🔥
I strongly believe in all the PW faculties.. literally hats off to all these legends..like no one can provide such an amazing content that too for free and be with us till our exam gets over❤
Agar koi pehli baar kar raha hoga? Unhe aa jayega samajh? Concept samajh aa raha hai isme?
Kbhi offline aakr dekho to pta chle😢
1:41:12 - rest ko koi graph nhi diya hai 1-b 2-d 3-c 4-accelerating
Who is here after neet 2024
Kon kon neet 2024 ke baad Aya h
2025 ke liye aya hu
Re neet ke liye aya hu
@@AnujYadav-gt2bctujhe grace marks mile hai😮
Sabka hoga August m@@Sakshi_72
Re neet k liye aai hu but grace marks wali nhi hu😂😂
1:03:02 taking time interval as 2s..
S1 : S2 : S3 : S4 = 1:3:5:7
from this we get 2 relations
S2/S3 =3/5 and S3/S4 = 5/7
equating the values from this we get
S2/ S4 = 3/7
and value is given in question that S2 = H1 and S4 = H2
therefore..H2 = 2.33 H1
S2/S3 kyu ye ratio toh t=4 to t=6 ka h aur question me t=2 to 4sec and t=6 to 8sec me pucha 4 to 6 sec ka nhi 🤔 ek dfaa aur dekh lo Maine v 1:3:5 yhi ratio ka use Kiya h lekin answer a aa rha h
@@DrTaniya_13 S3 ka wala cancel out kar diya ..dono main S3 aa rha tha...dono ka S3 ka value equate kar diya
@@DrTaniya_13nahi aya yar Mera
1:1 me next 7a bol rha g toh 3×80 hoga na?
Can you help me to solve this question with a proper solution
SLIDE 62 1:30:03 ANS D , bcoz in ques lift is uniform, it means uniform motion yaani uniform velocity so speed or direction uniform hogi then time same hoga
Bhai agar uniform na hoker variable hoti toh option C correct Hota na?
@@Khushijat4343nhi I think option a correct hota tab kyuki upar jane me time kam lagta aour niche ane me jyada lagta
@@Mehek0988 Agreed
😢😢
Slide 1:23:13 56 c option
Kaise ayaa
Slide 86 1:56:34
Opposite me velocity add karenge 90+54= 144km\h to m\s conversion= 144×5\18=40
S=u×t = 40×8= 320 m
Hit like if I'm correct
1:01:00 Sir isma Ans
Displacement in next 7sec=3x
=3×80=240m hoga (By Physics Med easy) ............ 🙂🙂
yes👍
Yes
Ha wahi me dekh Raha tha sir glti krr rahe hai ,toh ham toh bhool hi jayege
Main bhi confused thi thank you
@@renu_7890 🙏
Slide 56
V at 3 sec=120m/s
V at 5 sec=100m/s
x+1/x=6/5
5x+5=6
x=5
1/5 aayega nah solve krke
@@devang2 5 aiga
5x+5=6x ayeega edit kr lo. 👍
@@Suman-bo3vh tmne krliya na ...
Yes bro 5 right answer
1:03:07 JAY SHREE RAM
FROM GALELIO ODD NUMBER
1S ME 5M TRAVEL
2S ME 15M TRAVEL
3S ME 25M TRAVEL
4S ME 35M TRAVEL SO ON..
RATIO HOGA 1:3:5:7:9:11:13:15 (8SECOND KE 8 RATIO AAGYE )
T=2S TO 4S = 5+7=12 (H1)
T=6S TO 8S = 13+15=28 (H2)
H1÷H2 = 12÷28
H2 = 2.333 H1
Hey how much are you scoring in mock tests
What's your neet score?
@@krishpatel-s4d 480 😔 bro
@@krishpatel-s4d apna bhi bta de ?
@@siriencia What is your neet score cutie?
1:03:07
h(0to2):h(2 to 4):h(4 to 6);h(6 to 8) = 1:3:5:7
h1/h2=3/7
h2=2.33h1
Thanks 22 ❤
1:23:21 slide 56 ans-c
How?
@@rayyantechbros7058 Velocity nikalo 3 and 5 sec pe or dono ko divide krke equal x+1/x kardo and aajainga
Slide 46:-
V max = ab/a+b × t where a = alpha b = beta and t is total time
Now, we use eq. Of motion for the first part of the journey (v = u + at)
V max = 0 + at'
t' = V max /a
t' = {ab/a+b × t}/a
•°• t' = bt/a+b
Bhai aapka ye konsa attempt hai?
Direct ho jayega isse Acha toh 'at1=bt2' is formula ss ....
@@AditiJain-wi4mrbhai kaise thoda explain kardo
Ubhai a kaise kat gya ??? Aur upar t kaise aya
Thanks
Sir apne utthan se sabhi neet Dene walo ka utthan kardiya ❤❤❤
Attendance Neet Aspirants ❤😢2025
Mai 😢
Me
Lol😂😂
Thank u so much sir..
Aapki health theek nhi phir bhi kitna . Achche se padha rhe..
Aap se hi to hum motivate hote hai.. ❤ again thank u🙏 sir
1:55::03 Slide 86(d) train A v=25ms-1 and train B =15ms-1 train A ko rest me assume kro then net velocity =40ms-1
distance=speed*time =40*8=320m
Ye kaise kiya tumne
Mera to 3rd aya phir 2nd but ye wala nahi aya
Speed ko km/h se m/s m chnge kro
Slide 56 Ans =5(c)
Slide 62Ans= (d)
Slide 79 Ans=(a)
Slide 56 ka tumhara c kaise aya plz explain😢
v= u+at equation apply Karo (a=-g ,u=150m/s)
@@yogeshkumar202 Answer will be a, -5+1/-5 = 4/5 = 120/150. Ek bar check karma shared apka galat hai
Yes 56 ka c hoga
34:42 is question me sir ne distance pure path ka kyo liya he yha par to half ka pucha heto distance πr hona chahiye na
Neeche foolon ki dukaan upar gori ka makaan concept OP🔥🔥
1:01:01 next 7 sec.
Solve from gleleo odd No.
1x:3x
Ans 3×80=240m
Yup!!
Yes right sir ne thk se Pdh nhi❤❤❤😊😊😊
can u explain me plss .i m very conf.
@@Archana945-j1r displacement in t sec is given in qn find displacement in next t sec ( mtbl t sec ke baad ka)
Then solve from 1x: 3x: 5x ....
If qn in given displacement in t s is x find displacement in 2t sec (according to qn displacement in 14 sec means 1 se lekr 14 sec ka beech ka)
1x :4x: 9x...
I hope you understand
@@mdsanaullah3296nyy nyy first 7sec ko consider nhi krna hoga
Slide72 1-B
2-D
3-C
4-accelerated motion (non uniform)
1:22:58 Slide 56 Answer: C (5)
Kya din aagya h comment section m answer dhundhna prr rha🥲😭😂
🙃🙃🙃
💀💀
Match krne ke kaam ata h vai 🐻❄️😁
🎯Thank you sir 🥀
It is the Last drop for NEET😢
Kon sa drop hai
Slide 46 - Question 😀
t = t1+t2
t1 =t-t2 putting the value of t2 = Vmax/b (where Vmax ko hum likh skte hai abt/a+b ..answer C
Thanks bro
For clear explanation 🎉
SLIDE 75 1:44:01
D 5/3
1:07:58
Ans--- C
After T1 sec car starts de-accelerating and the velocity decrease therefore at the end of T1 velocity should be max.
Vmax = A T1 (A is alpha and B is beta)
(A×B/A+B)T = AT1
=>T1 = BT/A+B
Slide 79 -*A* v-x graph slope is a/v as velocity is uniformly increase till x=200 then change in a + then v const a become zero
1:23:28 answer is 5 (slide 56)
Correct option is c
Thank you
How ? Can you pls tell?. I'm not getting the solution
First equation of motion ka use karo
At time 3sec or 5sec par
Thanks @@kumarjadhav652
bhai answer varify kiya aap nai
@@zaheerahmed2719 Sahi answer hai ye
Slove karke dekh lo
Slide 64 done
Slide 56 - c
Slide 62 - d done
Slide 66 - b done
Slide 72 1- uniform motion
2- constant acceleration
3- retardation 4- non uniform accelerated motion
Slide 73 - 60
Slide 75- d
Slide 86 - d done
Slide 87 - c
Slide 89 -c done
Thankyou so much sir!!!🙏🙏🙏🥹🥹
slide 86 ka sol bata sakte h aap
@@HarshBangha change km/h to m/s you will get 25m/s & 15m/s ....they r in opposite direction so relative velocity will be 40m/s
Length= v×t = 40 ×8 =320m
slide 89 ka solution?????
89 wala kaise kiya
@@shaheerafatima937 likha h upar hi aanko se dekhiye ...
1:32:36 U=0 when monkey drop the mango from tree
So t nikl do by using s=ut+1/2 at2 ,,T=2 s ayega s=vt me v= 2.5m/s and t=2 s ka value bita do u will get the ans👍
S=vt kyu liya?
@megharoy7324 basic formula speed is equal to distance by time....
@@kalki6451 haan ho gaya neet bhi de dia😂😭😂
1:56:15 ,Slide 86
Opp hai to add karege
, 90km/h + 54km/h = 144km/h
Therefore 144 ×5/18 m/s = 40m/s
, S=VT hence
S =40×8 = 320 m
34:42 is question me sir ne distance pure path ka kyo liya he yha par to half ka pucha heto distance πr hona chahiye na
@@Bixchuu94 Mera comment check Karo
@@Bixchuu94 speed to constant hai na, half ka dekho ya full, answer same hi ayega
@@sahilsrivastava3016 ok thank you
👍
1:23:34 120/100=x+1/x
X=5m answer
Apka tarika thoda cusal hi questions krna but ans yehi hi😂
1:07:36 for 1 case u=0(from rest) accn=alpha second case v=0 accn= -beta so we can determine for kinematics first equation that t1=v/alpha and t2=u/beta t=t1+t2 so t=v(beta+alpha)/alpha•beta therefore
Vmax=alpha•beta•t/alpha+beta
Thank you 🙏🏻🙏🏻
Kis kis ko 150+ lana hai physics me😊
Kisiko nhi .. ham to time waste k liye aaye hai 🥲🥲
oh...mai to 10+ k liye target kr raha tha...
1+ is enough
Bhai all
Mai 180
Hai koi jisne mr ka swaal phood diya😅
🙆🏻Hmmm MR Sir ko phood diyA Ooo sryyyy i mean MR sir ke swaAl ko phood diyA...🙃
Khud phut gye bhaiiii
Mr Sawal ko prood diya
H2=2.33H1 aya mera
sir ji pura 1D ka feel aa gya loved the lecture questions were new but concepts were old...thank u so so much sir for this efforts mene lecture 2:30 hr me complete kr liya...😊🙏
Back here after neet 2024 results........
Why bro exam to ho gaya ab kyu padh rahe
It's ok try again.
Nahi hua to bhi koi nahi...Read more.
.
.
,
.
.
.
.
.
.
.
.
.
Comment chor ke padh le.
😅@@micky1576
Slide 56
..MR*..Speed decrease by 10m/s
In 3sec seed =120
In5sec speed=100
Bamkee krlo yrr😂
Ans c
Thanku
Nahi aya kaise kare usko
Slide 56 c answer very easy done by mr star
1:23:36
sir aise bol rhe tge tricky ques h , ye toh bhut easy tha
@@namratasingh3238kaise hua😢
done sir all the best dos logo
29:04- Avg speed =6m/s
1:03:09- If we take distance in first 2 sec be h
Then h1=3h and h2=7h
So , h2=2.33h1 (B)
Slide -46-C (aa gaya)
1:11:35-khel Gaye sir
1:23:08-C , velocity after 3 second=120m/s. , velocity after 5 second= 100m/s
Taking ratio V3/V5= x+1/x= 6/5=5+1/5,. So, x=5
1:30:52-B(aa gaya)
1:41:11 - 1-B
Slide72 2-D
3-C
4-accelerated motion (non uniform)
Slide - 73- 60m/s
Slide-75-D
1:47:44-(slide -79) -A
1:56:25-D,relative velocity=40m/s,
t=8sec , length of train=40×8=320m
1:56:56 (slide-87)-C
Hey...what about last question what is the solution
@@komalrawal001 Apr mains 23
@@komalrawal001 ha re pyq h mains 23 April ka
@@DestroyGamers talk with dignity what is this"or ha re" I'm not your friend... maintain a line btw thanks for the information
@@komalrawal001 chill issa kya hi bola tha
Slide number 46 the answer will be filed with the help of Alpha t1 is equals to beta t2 and we know that t is equals to t1 + t2 and we have to find t1 so will put the value of t2 in the equation first that is and then will find the answer 1:07:59
Slide 62 option d because in uniform motion acceleration constant, in this case g. So when coin falls in both case, acceleration is g which means time taken is same
Niche Fulon ki dukan 💐
Upar Gori ka Makan ❌️
Niche Baigan ki dukan 🍆
Upar MR ka Makan ✅️
Respect for M R sir from bottom of the heart🤩
1:07:53 ...let us consider t1 as time to reach V max
So t1+ t2= t (total time)
And at1=Bt2 here
We can substitute t2= t-t1
at1= B(t-t1)
at1=Bt-Bt1 =
t1(a+B)= Bt
So t1= Bt/a+B
Thankyousir🙂🙂
Thank you ❤❤
Thank you
Fun fact the notes used in this lecture are the med easy book notes so if I want to understand any topic or anything I can literally watch it from here 😊😊😊😊😊😊
Is it okay to watch this if you are doing the chapter for first time?
1:30:00 (t1=t2)
EXPLANATION:- the relative velocity of ball w.r.t floor of lift is zero in both cases... and relative acceleration is same(i.e =g) in both cases... therefore time same lagega..
Bro jb lift acc a se lift upar ja rhi h too voo g-a nhi hoga ??
Uniform motion hae lift ka therefore acceleration of lift =g
Note: object caries the velocity not acceleration of vehicle / lift etc from which dropped . Therefore acceleration same velocity same hence t1= t2
1:30:01 slide 62 :- person ne lift ke andar hii coin ko drop kiya hai toh in t1 coin with respect to lift's floor stationary hii hoga as both will move in same velocity..and t2 already stationary hai so t1=t2
1 hoga I think
@@pratishthayadav1656Are bhai tum lift ke sath v velocity se upar ja rahe ho aur tumne coin drop kiya. Tumhe nahi lagta coin tumhara velocity share kar lega. Lekin accelerated hota to 1 ata kyunki acceleration share nahi hota aur woh motion me farak dalta h
Aree bhai ye batao lift upr accelerated hota non uniform motion se to time jada lgta ki kam@@dipayanbiswas5543
Hn to bhai velovity share karega to agr lift upar ja rha hoga to ball ko bhi upar ki taraf velocity mil jayega us case me time jyada lagega drop wale se aur agr lift neeche aa rha hoga to neeche ki trf velocity share karega is case me kam time lagega@@dipayanbiswas5543
1
1:22:58 slide56 ANS = C
How
Kaise Aya bhai
yes
❤ thanku
V = u + at apply karo t 3s and t 5s per
34:50
The distance is given half the circular lap. Hence , the distance must be (2πr/2) and not (2πr) which is for full circle. Same with the time. Which must be half for a Half circle.
Either ways , the answer comes (A.)
Yes... Exactly I was saying.. no one commented... Thank you 👍🏻
I was thinking the same. Thank you 👍🏻
araaaa lekin question mai speed constant hai.....isisliye half circle ka nikalo ya full circle ka dono same hoga,,,,,,,,,,,,,,,aur upar se time v toh full circle ka diya hua hai
@@khushimandhan3201 constant speed hai re
@@rajkamal6161 par question me Diya h half ka nikalo toh half ka hi formula lagayenge na
Slide 66
Ans b(125)
28:59 ANS IS 6 m/s
1:03:04 option B divide in equal time interval.....H1/H2 =1:√2-1
MR star ⭐⭐⭐⭐⭐
Wo toh time ka ratio hai equal distance k liye . Aur Tumnhe value rakha toh v 2nd kha se match kr rha
This is wrong bro ...isse answer nhi match ho rha
Shi kaha b hi hoga
He himself is a talent damnitttttt
Wishing u all,
All the very best for ur NEET exam❤
Let's hope for the best🤞& be prepared fr the worst👀
Yes sir slide 46 me total time ko two part me devide kar lenge then use rest to rest case
At'= B(t-t')
At'=Bt-Bt'
t'(A+B)=Bt
t'=Bt/(A+B)
Slide 56. x=5
Slide 86
Relative velocity me direction same ho ya opposite ho hmesa add krenge to, Soo 90km/h+54km/hr=144km/hr
Isko m/s me change kr lenge=144×5/18=40m/s
V=ST
V=40m/s×8s=320m/s answer
Slide 46 :- aT=b{t-T}
aT=bt -bT
T{a+b} = bt
T= bt/a+b
1:01:00
Ans - 80×3=240 hoga
haa
Ye correct hai 240 hi but sir ne 320 galti se kiya hai
Thanku so much sir... This series is very very helpful for us... Question krke bahut confidence mil rha hai... Thanku so much 🙏💙
Aits preparation ❤
1:23:21 Sir, option C is correct❤ Slide 56
1:41:13 rest ka koi graph nai hai... 1-B 2-D 3-C 4-non uniform acceleration
1no. Bro
Niche phoolo ki dukan upar Gori ka makaan ❤ 9:29
02:00:02 the question is so beautiful so elegant just looking like a wow 🤍✨
❤
solution kya hh
So bitti full so mja aajailo guru ji😂😂😂😂😂😂
Iska solution kya hai?
Genuinely yaar maza aa gaya
1:07:55
V(max)= (Alpha× beta)t / (alpha + beta)
So if we take this journey from rest to V(max) then,
By using 1st equation of motion
V=u+at
(Alpha× beta)t / (alpha + beta)= 0 + Alpha×T
By solving this equation we will get
T= (Beta × t) / alpha + beta
slide 46- (c) v=u+at se karna h sir
slide 47 - (c)
slide 62 - (d) 😁
slide 64 - (A)
slide 66 - (B)
slide 72- 1-B,2-D,3-c,4-no option is correct😁
slide 73- 40m/s
slide 75- (D)
slide 86 - (D)
slide 87 -(C)
slide 88- (D)
slide 89- (C) tagda sawal🔥🔥 5 min ki calculation ke baad
How slide 89 proceed
89 ka answer kese aaya?
Bhai slide 79 bhi bta deta yrr
✍slide no. 86
relative velocity of A wrt B = 40 m/s t=8s d=vt =320m
Mr sir op or unka conceptual padha op se v op😊😊😊😊😊
NICHE PHOOLON KI DUKAN, UPAR GORI KA MAKAN ........ MR ⭐⭐🌟🌟 GARDA VISUALISATION
Slide 56 1:23:32 ans is x=5
HAN MERA BHI YHI AA RHA
Mera bhi ❤
Kaise ayaa
@@vedantgawande1634dono time pe v=u+at se vel nikali and dono values ko divide karke x+1/x ke equal put kiya
Ha mara bhi aya