Slide 22: As rho , and l same Then R is inverely to area Then R1/R2=r2²/r1² From here new resistance will be 126 ohm Then q,about system resistance so Req'=126/7=18ohm 46:37 Mobility will be proportional to q/m On solving we get 1/2:1:1/2 Multilpy by 4 Getc2:4:2 X=4 😊 Slide 48 Ans -25v Slude 52 3/5A Niche kai 2 resistor ka current jayega nahi sirf upar kai 3 tesistor ka current jayega so Total current -2R ka current 1-2/5=3/5A Slide 71/B As i used A ka,1.5I²R B KA 0.75I²R C KA 0.33I²R D KA 3I²R Slide 76 c 100w kai acroos voltage less hoga.
@@SoumaShubhraSarkar Req=R/n =1100/5=220 ohm Then current nikal lo vo ayega 1A total current ayega ye But humse pucha h current in ammeter Ammeter ke right side R/3 and left side R/2 then loop rule se I1 nikalo then I=I1+I2 se solve kr lo
Hey ,hi Can we just go through this lecture nd make a formula list nd practise is it enough, will I be good at solving questions...or should I need to see one shot!!? Would ge fearful for ur reply..😊
HW question SLIDE 22 41:53 new resistance of each wire will be 9R as the radius decrases by 3 times(R proportional to 1/ r^2 )and then 7 of these are added in parallel so 9R/7 comes 18 ohm
46:44 ...as mobility proportional to e/m....then deutron : proton : alpha partical......e/2m : e/m : 2e/4m.... 1/2 : 1 : 1/2 sabko 4 se mutiply krdo...to jo x h bo nikl ayega...jo ki 4 h...so ans [x=4]***
@@dharitripatel0613 see as per question ans to 1/2 : 1 : 1/2 h pr options me aisa option given nhi h to hme dekhna hoga options ke according kon s shi h isiliye 4 se multiply kr diya
slide 22 ..here resistance is inversly proportional to r² as l is constant therefore resistance of new wire is 14 *9 =126 ...... connected in parallel hence 126/7 =18 ohm 😊
41:52 slide 22- if 7 parts of the wire are joined in parallel series,the net resistance becomes 7 times divided,hence 2 ohm(14/7) The radius decreases 3 times,the length remains const in 7 identical insulated wires.hence,resistance proportional to 1/r square..resistance increases 9 times(3×3) Now, effective resistance is 2ohm×9=18 ohm(B)
Slide no. 22 done answer is 18 ohm Because as length is same and area is changing R=rho L/A R inversely related to r^2 Then after solving resistance of single wire is 126 ohm Now connected these 7 resistors in parallel Resultant resistance if 18 ohm
@@SushmithaPeruvajefirst calculate the total current in circuit it will be 5 ampere then divide it by number of resistance it will be 1/5 ampere from first resister 1 / 5 ampere will be passed and the from second also 1/ 5 ampere current pass show remaining current through ammeter 5 - 2 / 5 is equal to 3 / 5 ampere
Pahle parallel mein resistance R/2 tha bad mein resistance R ho jaega jiski vajah se potential drop across the B2 bulb is increase then incandescence of B2 will increase
@@sanatan-dharma4.o are bhai sun , power ma comparison hai. Power = I²R , ab sab me I same hai , to jisme Resistance jyada hoga usme power jyada , to tu sabke R nikal de .....
slide 22 radius decreased by 3mm and length remains constant so resistance increases by 9 times new resistance = 9*14 = 126 but 7 wires are in parallel so final resistance = 126/7 R= 18 ohm ....OPTION B IS THE CORRECT ANSWER 😇 slide 48 Vp= -25 volt
@@stutiraj1507 radius nhi resistance hota hai r^4 ke inversely proportional lekin tb jab volume constant ho ..is ques me length constant hai toh inversely proportional to r2 hoga
8:13 Iavg=□Q/□t ❤11:13 quick recap question 17:33🎉 revise formulas of conductivity resistivity and all 22:48 mobility order 23:29 electric field outside conductor applied by external battery is zero kyuki 25:06 mobility does not depend on vd or E uska bas formula mai hai m=vd/E 25:33 explained why mobility does not depend on vd kyuki agar vd double toh E bhi double kyuki vd=eEtau/m and vd is directly proportional to electric field
42:03 Slide 22 => R proportional to (R1/R2)^2 So R2= R1x(r1/r2)^2 = 1/9×14 7 same wires are in parallel combi Therefore ... R(final)= 9*14/7 = 18 Have a nice day
@@Zuki454 I=V/R se ek resistance ka current calculate Kroge to 1/5 ayega… is hisab se total 5 me 5 Ampere aayega… but ammeter Jaha laga hai uske pehle bas 2 resistance hai.. means 2/5 A will be used remaining 3/5 will go further hence in ammeter reading it will be 3/5
Sir bohut hi acha lecture tha...sab questions naye ...Sara concept clear hogaya..yeh chapter mera hota hi nhi tha...but apse padhke questions karke laga ki yeh bhi hojayega...todha practice aur mehnat lagega but it's not impossible...thank you so much sir itne crucial time par hamare sath rehne ke liye...guide aur motivation ke sath itna acha padhane ke liye...app teachers itna mehnat karte h toh lagta h...agar app hamare liye kar sakte h...toh hum khud ke liye toh kar hi sakte h...Dil se shukriya sir❤
Maja aaya sir sab sahi hua. Thanks u sir ek vo semiconductor wala galat hua tha aapne bola selection nhi hoga. Thoda bura laga but mai bhi aapka ramlal hu last tak haar nhi manunga. Overall is dedication ka liye thanks u sir next time i will improve my self
SLIDE 77 option B decreases as in both Resistance of B2 is same but the current in the circuit is different. current in the second case will be less because the overall resistance of the circuit increases in the second case so power dissipated in B2 will decrease .
@@sunflower291 pehle resistance 3 R/ 2 tha (overall resistance )after that resistance 2R ho jayega to current decrease hoga to power is directly proportional to I^2 na so b2 ka brightness will decrease
Thank you so much sir fabulous lecture may Allah reward you your efforts making this type of lecture also one of the my favourite chapter again Th ank you
Mr sir ab n padhayenge kisi bhi batch me kuki 😢😢.......👇🏻👇🏻👇🏻👇🏻👇🏻👇🏻..... NTA wale lekr ja rhe h unhe paper bnane ke liye 😂😂😂😂😂😂😂 mjak se ht kr amazing lecture sir ❤❤❤
Slide 22: First for one wire pl have to find (14×4π×81) Then for seven identical wire , Have to find resistance of one wire pl replace karke (14×4π×81/4π×9)=(14×9) Then equivalent resistance for identical seven wire =(14×9/7)=18ohm❤
Slide no.. 22 7 wire ke liye nikalna hai Resistance to pahle ek wire ke liye nikalenge isme length ko constant rakhenge jis se R invortionaly proportional r^2 ho jayega iska answer 126 ohm aayega phir isko 7 se divide kr denge to 18 ohm aa jayega..
Sir, if possible uthaan series ki questions aap solve karne ki pehle eek version bhi upload karwa dunga? Like non-annotated version, question eek baar bhi revise karna aasan hoga aise, aur us questions ke eek copy print bhi kar sakta hu, thank you sir ❤
Slide 22- we will compare the first wire and take one wire from the 7 insulated copper wire combination so here l is constant and rho is constant and we know that R=rho*l/A we can write this as rho*l=R*A now since Rho*l is constant so R1*A1=R2*A2 now putting the values we will get R2= R1*(r1)^2/(r2)^2 now we get R2=126ohm now the r equivalent of combination of 7 such wires will be 126/7= 18 ohm answer hence b is the right option!!
Slide 76 - ( C ) hoga as current is same in series and resistance is inversely proportional to power to jismein resistance jaada to potential drop bhi jaada 🫡
@@Rohanrautsjpahle2 resistance across current nikal do to agar. 2 identical resistance parallel me h R/2 = 1100÷2 = 550 aur phir i =v/r = 220÷550 =2/5
In that question we just have to check the net resistance of circuits....aur firr jb har circuit ko ek equivalent resistance se represent krke dekhenge to jis circuit ka resistance jada hoga ussme power dissipation jada hoga kyuki I to sb me same hai so P=I²R se P directly proportional to R
@agrwal866nhi switch off krne se resistance increase ho jaayega (kyuki remaining do bulb series me ) Aur resistance increase hone ki vajah se current decrease hoga ab kyuki series me hai bulbs to power I pe depend krega so I decrease hence power dissipation also decrease i.e. brightness decreased
Slide 22) R=pL/A pL=constant Resistance inversely propational to area R/R'=A'/A=πR'²/πR²=3²/9² R'=9×R=9×14 =126 Now if we use 7 resistance in parallel then Req=R'/7=126/7=18ohm. Ans.
@@poojapooja6845 R/L diya hua hai =120 toh ...phele length of wire nikaal lo 2πR= L ...toh yaha se L ayega 0.2π ...ab is value ko R/L=120 wale me daalo toh Resistance of wire aa jayega 24π ohm Ab esko bent kr diya hai toh R/2 and R/2 parallel combination me h ...R/2=12 π ohm ayega Toh...req 12π/2= 6π Ohm answer
Sir main ek genuine cheez btata hun... Meri neet mein 646 ayi hai but as we all know due to paper leak bht koi k nhi hua itne number pr bhi.... Sir jo student pyq bola plz uske ye bol digiyega ki 146 physics mein neet mein lane pr bhi apke current ke aaj ke question poore nhi bne... Sir your content is just like pretty awesome for 180 on 180 in neet❤️❤️
42:00 slide 22 R is inversely proprtional to A ..so R1/R2= 7 r2^2/r1^2 ..solving this ans will be 18 ohm 46:45 u=et/m ..ud:up:ua=2:4:2 ..x=4(ans) 1:17:34 Vp= -25 V 1:24:36 slide 52 ans 3/5 A
📕Get All DPPs & Pdf: Uthaan NEET 2024 Batch : physicswallah.onelink.me/ZAZB/senpv6z6
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Faadu concept provide krte ho sir love you sir ❤️❤️❤️❤️
Duadarrr 💥💥 questions practice ho gyi sir mja aa gya with mr ⭐ questions and mr sir❤❤
Notes kaha milega ??@@vivekaryan2.090
Notes kaha milega 🥲
Pls homework ka ans batado
Namak SWAAD anusar... Aur MR ka LECTURE - *AUKAAT* ANUSAAR 🔥
Sabzi me 😅
Aukaat*
Aur content 😅😎 .....
SAHI H ❤
Aukaat❌
Aukaad✔️
#1:17:33
Potential at point Vp = - 25 volt
Mera bhi😊
Kaise???
@@Ummayy_ solve kro Aachen se
Mera v
Ye - 25
Slide 22:
As rho , and l same
Then R is inverely to area
Then R1/R2=r2²/r1²
From here new resistance will be 126 ohm
Then q,about system resistance so Req'=126/7=18ohm
46:37
Mobility will be proportional to q/m
On solving we get 1/2:1:1/2
Multilpy by 4
Getc2:4:2
X=4 😊
Slide 48
Ans -25v
Slude 52
3/5A
Niche kai 2 resistor ka current jayega nahi sirf upar kai 3 tesistor ka current jayega so
Total current -2R ka current
1-2/5=3/5A
Slide 71/B
As i used A ka,1.5I²R
B KA 0.75I²R
C KA 0.33I²R
D KA 3I²R
Slide 76 c 100w kai acroos voltage less hoga.
Thank you ❤
😍
slide 52 explain kardo vai....plz
@@SoumaShubhraSarkar Req=R/n =1100/5=220 ohm
Then current nikal lo vo ayega 1A total current ayega ye
But humse pucha h current in ammeter
Ammeter ke right side R/3 and left side R/2 then loop rule se I1 nikalo then I=I1+I2 se solve kr lo
Potentiometer nhi h syllabus mein????
@@godbs3501 nhi
Ordinary students go for 5-6hr of one shot
Legend watch 2hr lec of mr sir 🗿
Content in mr class>>> in ordinary class 😂
Sahi kaha !!! Question level 🔥🔥
@@Bacterio7 phele se nhi bana rakhi ?
@@Bacterio7 agr ab banaoge toh padhoge kab usse lol 😂
Merako 50 marks chayee hojayagaa series se
Hey ,hi
Can we just go through this lecture nd make a formula list nd practise is it enough, will I be good at solving questions...or should I need to see one shot!!?
Would ge fearful for ur reply..😊
Anyone for 2025😂❤❤😅😅
Isme itna hasne waali kon si baat hai?
@T2222-k1j because my syllabus is complete. Just doing revision
@@coolcarsbyboby8028 bhai mera kabka ho chuka hai majors chl rhe😂🙏🏻
H bhai mai future se hu😅😂
Mai aj se start krungi
LUX NEET 2025 students attendence 👍
I am studying this first time is it enough
😅
@@amitkumarvashishtha450to br honest...no
Bilkul bhai NO@@amitkumarvashishtha450
Lux 😂😂😂
HW question SLIDE 22 41:53 new resistance of each wire will be 9R as the radius decrases by 3 times(R proportional to 1/ r^2 )and then 7 of these are added in parallel so 9R/7 comes 18 ohm
Multiple time I watch uthaan series i literally don't want ki koi isse dekhe nhi toh competition bad skta h😂😂
Hiiiii
How are you
Abe spammer dash Tera...@@RahulSahoo-fd1in
Dekhe bhi to bhi maximum ke sar se paar hai
Bhai qns ka level☠️🔥
Others: Detailed lecture
Reality: Crash course
PW: Crash course 😎
Reality: Detailed lecture
Bhai kya ye enough hai 130+ ke liye kyonki bhai padha hu lekin que jaada nhi practice hua hai
@@aman_600khud se ek acche book se practice kro...
woh behetar hai
agar tumhara syllabus complete hai toh
@@aman_600 pyq + this + some tests enough hai
@@aman_600 yupp... Revise krke question practice kro👍👍
@@Unknown-6ix9ine tysm bhai
1:36:32 WOW SIR WHAT A QUESTION !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!☺☺👌👌👌👌MR ⭐⭐ NAAM HI KAAFI H💪💪
Don't understimate the power of mr start😇🥰
Best Revision Lecture ever.......Thank You Gurudev✨
Sir ne voltmeter and ammeter padaya h?
hmmm
@@sagarpanwarpranyodha9900
@@sagarpanwarpranyodha9900haa
@@sagarpanwarpranyodha9900 yes
slide 22- 42:03 - (b) resistance ka formula laga ke 3mm ke wire ka resistance nikal lenge = 126 ohm then parallel comb se Req=126/7=18 ohm
slide 48 - 1:17:31 - (-25volt)
slide 52 - 1:24:33 - (c) 3/5amp
slide 71 - 1:57::28 - (b)
slide 75 - 2:01:07 - (c)
slide 76 - 2:01:11 - (c)
slide 77 - 2:01:17 -(a)
slide 85 - 2:12:35 - (b)
slide 86 - 2:12:38 - 1-(d);2-(b);3-(a);4-(c)
slide 87 - 2:12:54 - (d)
76 explain
1:57:31 ye wala kese Kiya Bhai?
75 &85 bta do
you are right
Power directly proportional to R due to I is constant
P=I²R@@ruturajbehera7244
46:44 ...as mobility proportional to e/m....then deutron : proton : alpha partical......e/2m : e/m : 2e/4m....
1/2 : 1 : 1/2 sabko 4 se mutiply krdo...to jo x h bo nikl ayega...jo ki 4 h...so ans [x=4]***
Yaha 4 se kyu multiply kiya ? Pls explain 🙏🏻
@@dharitripatel0613 see as per question ans to 1/2 : 1 : 1/2 h pr options me aisa option given nhi h to hme dekhna hoga options ke according kon s shi h isiliye 4 se multiply kr diya
@@Prapti5836okayy understood thanks 😊
Answer ke hisaab se chalna hai@@dharitripatel0613
@@dharitripatel0613 .isliye bhi ho skta hai R is proportional toh length square toh hum twice ka square krenge toh 4 hi aayega
slide 22 ..here resistance is inversly proportional to r² as l is constant
therefore resistance of new wire is 14 *9 =126 ...... connected in parallel hence 126/7 =18 ohm 😊
Hm ase he
Sirf 19 ka replace pe 9 loga typing error hai just
slide 52 answer is c , total I= 1 amp , ammeter se last k 3 lamps ka current hi pass krega so 3/5 amp
Bro can u explain y last k 3 ka hi current jayega?
Bro tuze lectures karne padege yaar Aisa nahi explain kar sakte sorry ?😞
Slide 75
IXVt=ms•80
Ans 6.3mins
41:52 slide 22- if 7 parts of the wire are joined in parallel series,the net resistance becomes 7 times divided,hence 2 ohm(14/7)
The radius decreases 3 times,the length remains const in 7 identical insulated wires.hence,resistance proportional to 1/r square..resistance increases 9 times(3×3)
Now, effective resistance is 2ohm×9=18 ohm(B)
If vol is const then R inversely proportional to r⁴ isnt it
the single copper wire is replaced by 7 identical wires of same length but 3 times less radius..length const. Not volume
Isme volume constant karke kyo nhi kiya
@@veerpurwar7568 the 1st single wire is replaced by 7 wires of each same length with the 1st one..
@@Richa_Biswas sorry, Jada jaldi me question hi shi se nhi pda oor volume constant karke pura solution kr dya.
Btw thank you
Do ghante ke lecture ko into two krke dekhne pr bhi 4 ghnte lgte 😂😂Thank uhh sir 😍
Sama😂
Who want to score 180 in physics 🎉🎉🎉
Like krke 180 aa jayenge kya phy me???🤔🤔🤔
azeeb scam h
Mera physics me 156 aaya full syllabus test me,😊
Konse Full test me @@hasnain_rishikesh
Nani babu sahasara kkd
😂 lekin kuch aise chapters Ki list Hai mere pss Jisse 150+ aasakte Sania ji 😂@@saniasheikh5120
This chapter is easy ( fake it till u make it)
2:12:48 slide 86....Option wrong hain i-d ii-b iii-a and iv-c hona chahiye
Dess
86 (ii) explain 😢
👍mera bhi same
Yaa
Pls explain 😢 mujhe yahi bss problem deta h resistance and capacitance calculate krna complex circuits ne 😭
41:46 18 ohm b.
46:40 x=4
Slide 48 : -25V
1:24:35 C
46:40 ka x= 4 kese aa rha Mera 1 kyo aa rha 🥲🥲
1/2: 1: 2/4 arha hai jb e/m ka ratio dekh rhe hai . Usse 1/2 ko 2 banado 4 se multiply karke sabko
@@CheemsDogesh-o3r But why it with 4 why not 2??
@@CheemsDogesh-o3r ni ho rha sab glt ho rha 🥲🥲
@@CheemsDogesh-o3r ni ho rha sab glt aa rha ni aa rha samjh 🥲🥲
Slide no. 22 done answer is 18 ohm
Because as length is same and area is changing
R=rho L/A
R inversely related to r^2
Then after solving resistance of single wire is 126 ohm
Now connected these 7 resistors in parallel
Resultant resistance if 18 ohm
🎉
thank buddy 🤠🤠🤠💞💞💞💞💞
🙏🙏
Thanks
Who said length of big wire is same as small wire.nothing is given about this in question.
Apne man se bana rahe ho bhai.
1:24:36 3/5 A
How bro ?
Collect
Pls anyone explain
@@SushmithaPeruvajefirst calculate the total current in circuit it will be 5 ampere then divide it by number of resistance it will be 1/5 ampere from first resister 1 / 5 ampere will be passed and the from second also 1/ 5 ampere current pass show remaining current through ammeter 5 - 2 / 5 is equal to 3 / 5 ampere
@@harshalsangpaltq u bro👍 how did total current become 5A i got 1/5 A iske aage ka ek step batao pls
Slide 71 Ans=(b)
Slide 75 Ans=(c)
Slide 76 Ans=(c)
Slide 77 Ans =(a)
Slide 85 Ans=(b)
Slide 86 Ans=(1)-D,(2)-B,(3)-A,(4)-C
Slide 87 Ans=(d)
❤❤❤
Bhai 77 main no change hoga
77 no change hoga since bulb parallel me indipendently apne across current flow kara rahi hai
@@AyushLaskar-hq4og lag to mujhe bhi yhi rha h
Pahle parallel mein resistance R/2 tha bad mein resistance R ho jaega jiski vajah se potential drop across the B2 bulb is increase then incandescence of B2 will increase
Slide-48 :- -25Volt👍🏻
Kaise aaya
Total resistent(R)= 4+2=6(addition bcz same current is passing )
And total emf 8-3=5
Vp= emf-iR
= 5-30
=-25V
@@DrPritamChakraborty thanksss
Sir..UTHHAN series...is a revolutionary series....Thank You Sir for such great quality questions....Love U sir...ThE MR StAr... ⭐ ⭐ ⭐
1:57:29 B
P directly proportional to I^2
I²R hoga bhai , tu R likhna bhul gya
@@mihirs.chaudhari4416 Bhai Woh Proportional Bol rahe hai...
@@sayedali2337 are bhai us sawal me R se hi question solve hoga I to sab me same jayega is wajah se R likhna jaruri hai
Plzz/. Koi mujhe ye qn... Smjha doo
@@sanatan-dharma4.o are bhai sun , power ma comparison hai. Power = I²R , ab sab me I same hai , to jisme Resistance jyada hoga usme power jyada , to tu sabke R nikal de .....
Slide 48 ans -25V
Yup same
Koun koun 2025 ke liye dekh rha h😂
Me also
🖐🖐
Notes kse download honge....
slide 22
radius decreased by 3mm and length remains constant
so resistance increases by 9 times
new resistance = 9*14 = 126
but 7 wires are in parallel so final resistance = 126/7
R= 18 ohm ....OPTION B IS THE CORRECT ANSWER 😇
slide 48
Vp= -25 volt
Radius to r^4 ke proportional hota h na??
@@stutiraj1507 radius nhi resistance hota hai r^4 ke inversely proportional lekin tb jab volume constant ho ..is ques me length constant hai toh inversely proportional to r2 hoga
Hnn mai resistance hi khna chah rhii thi😅
@@futuredoctor2507thanks a lot for clearing my doubt 😇
@@stutiraj1507 your welcome 😊
Sir agr offline mai pdate toh 2-4 bacho ko ese hi peet dete 😂😂 ese ek dum se darra dete h
😂😂
Slide 22). B
R is inversely proptional to area
.... 14/7x = 9/81
X= 18
👑
Can u explain plz
8:13 Iavg=□Q/□t
❤11:13 quick recap question
17:33🎉 revise formulas of conductivity resistivity and all
22:48 mobility order
23:29 electric field outside conductor applied by external battery is zero kyuki
25:06 mobility does not depend on vd or E uska bas formula mai hai m=vd/E
25:33 explained why mobility does not depend on vd kyuki agar vd double toh E bhi double kyuki vd=eEtau/m and vd is directly proportional to electric field
😮
I needed that ...thank you!❤
42:03 Slide 22 => R proportional to (R1/R2)^2
So R2= R1x(r1/r2)^2
= 1/9×14
7 same wires are in parallel combi
Therefore ...
R(final)= 9*14/7 = 18
Have a nice day
Slide 48 = -25V
Slide 52 = C
Slide 71 = B
Slide 75 = C
Slide 76 = C
Slide 77 = A
Slide 85 = B
Slide 86 = A
Slide 87 = D
Thankyou so much sir 🙏🙏🥹
Slide52 keae
Slide 77 kaise
@@Zuki454 I=V/R se ek resistance ka current calculate Kroge to 1/5 ayega… is hisab se total 5 me 5 Ampere aayega… but ammeter Jaha laga hai uske pehle bas 2 resistance hai.. means 2/5 A will be used remaining 3/5 will go further hence in ammeter reading it will be 3/5
76 kese hua plz bta do
@@garimagupta8258 because RESTISANCE of the circuit is increased to 2R from 2R/3 hence bulb B2 will glow more
Sabzi mein swad namak anusar,MR SIR ki class aukad anusar🔥🔥🔥
सब्जी में नमक स्वाद अनुसार और MR सर ki class औकात अनुसार 😂😊
Lame
Slide 75 Ans C
Sir bohut hi acha lecture tha...sab questions naye ...Sara concept clear hogaya..yeh chapter mera hota hi nhi tha...but apse padhke questions karke laga ki yeh bhi hojayega...todha practice aur mehnat lagega but it's not impossible...thank you so much sir itne crucial time par hamare sath rehne ke liye...guide aur motivation ke sath itna acha padhane ke liye...app teachers itna mehnat karte h toh lagta h...agar app hamare liye kar sakte h...toh hum khud ke liye toh kar hi sakte h...Dil se shukriya sir❤
Hello exam kaisa gaya snr can u let me know ye series se aaye the kya ques
@@devilgirl9809 yup...this series helped a lot..
Selection hua??
Slide 71 : b
Slide 75 : c
Slide 76 : c
Slide 77 : a
Slide 85 : b
Slide 86 : a
Slide 87 : d
Yes❤
Bhai 77 wale me incandescence ky h
Brightness
77 kaa b hai
@@138-fyscia-vishalgupta5 bhai vo b1 ka h Google m lakin yaha b2 ka pucha h
Good luck
Slide 48): -25Volt
Haa
Maja aaya sir sab sahi hua. Thanks u sir
ek vo semiconductor wala galat hua tha aapne bola selection nhi hoga. Thoda bura laga but mai bhi aapka ramlal hu last tak haar nhi manunga.
Overall is dedication ka liye thanks u sir next time i will improve my self
2:01:07 slide 75 ans c
Bro eska nhi aa rha hai kaise kiea ho
ms◇T=vit se kr rha hu
1:24:29 Slide 52 answer C
yes u r right 😄
🙂Finally done...!!!💫
✨ Thank u sir...)♥️🩺
This series is just like Ashish Arora sir's Revision Checklist... Thank you so much for this Neet oriented series ❤❤❤❤
45:29 watch this in 0.25x LOL😂
Also watch in 2x 😂
🤣🤣🤣🤣🤣🤣
2:01:14 2:04:50 1:20:17 29:31 23:22 1:26:31 1:35:55 1:48:57
SLIDE 77 option B decreases as in both Resistance of B2 is same but the current in the circuit is different. current in the second case will be less because the overall resistance of the circuit increases in the second case so power dissipated in B2 will decrease .
Are you sure
@@rabiasiddika8006 I have corrected my ans plz check
@@sunflower291
pehle resistance 3 R/ 2 tha (overall resistance )after that resistance 2R ho jayega to current decrease hoga to power is directly proportional to I^2 na so b2 ka brightness will decrease
Bi should decrease us hisab se but b2 will increase because pehle b2 m i/2 tha na ki i
Slide 52
#1:24:37
Option a
Not it's not balanced wheat stone bridge
Kaise
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Sahi bola..😂 me toh last bench direct
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34:55 on decreasing temperature no of electron in conduction band decreases hence conductivity decreses and resistivity increses
Thank you so much sir fabulous lecture may Allah reward you your efforts making this type of lecture also one of the my favourite chapter again Th
ank you
Thank you sir for this amazing session ❤
Mr sir ab n padhayenge kisi bhi batch me kuki 😢😢.......👇🏻👇🏻👇🏻👇🏻👇🏻👇🏻.....
NTA wale lekr ja rhe h unhe paper bnane ke liye 😂😂😂😂😂😂😂 mjak se ht kr amazing lecture sir ❤❤❤
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Slide 22:ANSWER 18 ohm
Slide 22: First for one wire pl have to find (14×4π×81)
Then for seven identical wire , Have to find resistance of one wire pl replace karke (14×4π×81/4π×9)=(14×9)
Then equivalent resistance for identical seven wire =(14×9/7)=18ohm❤
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ye lecture se pyq or allen module solve ho gye yar
Slide no.. 22
7 wire ke liye nikalna hai Resistance to pahle ek wire ke liye nikalenge isme length ko constant rakhenge jis se R invortionaly proportional r^2 ho jayega iska answer 126 ohm aayega phir isko 7 se divide kr denge to 18 ohm aa jayega..
Slide kaha milte hai..
@@ShankarK-wd4wv comment me link mention hai pw download krke es link pr jao notes mil jayega
Sir, if possible uthaan series ki questions aap solve karne ki pehle eek version bhi upload karwa dunga? Like non-annotated version, question eek baar bhi revise karna aasan hoga aise, aur us questions ke eek copy print bhi kar sakta hu, thank you sir ❤
jaise ki tera comment padhkr reply dege 🤣🤣🤣
Slide 22 : B
R = 126
Req 126/7 = 18 ohm
Great session for revision.
Thnku so much sir❤
1:17:40 sir itna sach kyun bola😭😭😭
1:42:35 mast que tha sirr 🔥🔥🔥🔥
Slide 22-
we will compare the first wire and take one wire from the 7 insulated copper wire combination
so here l is constant and rho is constant and we know that R=rho*l/A we can write this as rho*l=R*A
now since Rho*l is constant so R1*A1=R2*A2
now putting the values we will get R2= R1*(r1)^2/(r2)^2
now we get R2=126ohm
now the r equivalent of combination of 7 such wires will be 126/7= 18 ohm answer
hence b is the right option!!
Thanks dear bahut acchese samjah aagaya
r eq kya manke lagyi h
App
Matlb series ya parallel
Aur ku..?😢
@@suhanisingh6094 parallel questions Mai bola hai
Slide 71 bb 1:57:36
Slide 76 - ( C ) hoga as current is same in series and resistance is inversely proportional to power to jismein resistance jaada to potential drop bhi jaada 🫡
Slide 48 1:17:23
Can u tell me how
Slide22-b
Slide48-=-25 v
Slide 52-c
Slide71-b
Slide75-c
Slide76 c
Slide77 a
Slide 85 b
Slide 86 a
Slide 87 d
Haar nehi manege!!!! Abhi toh nehi
HW 86-A
87 - D😇😇
Slide 52
Ans is option C
3/5 A
How ?
@@Rohanrautsjpahle2 resistance across current nikal do to agar. 2 identical resistance parallel me h R/2 = 1100÷2 = 550 aur phir i =v/r = 220÷550 =2/5
2:1:18-b)decrease
Re-neet student attendance.....😢😢😢😢
Me
I am also in the queue 😊
Nhi hoga
@@fahadkhatir2258 me chahata hu ki na hi par fir bhi dar lag raha he
@@DeepRaiyani-ez8ce same situation
Slide 22 - b
Slide 48- -25v
Slide52- c
Slide 71- b
Slide 75- c
Slide 76 -b
Slide 77- a
Slide 86- a
Slide 87- d
Thank you sir
Hey can you explain slide 52 ans
at 33:00 Sir ne ek cheez galat boli hai, Electric field same thodi rahega!!.......
J=I/A....as A1>A2, So J1
Sir current bolna chah rhe honge... Anyway, thanx for pointing out... Hope it gets pinned!
@@satwiksachi2895 probably yes!, Jaldi-jaldi me ho jata hai
Yhi lecture enough h kay for neet
@@rubeenaahad2506 Revision ke liye theek hai, pehle baar padh rhe ho toh kuch samajh nahi aayega
@@rubeenaahad2506 revision point of view se more than enough for NEET4+JEE MAINS also i guess
Itne toh medical seat nhi hai jitna views hai 😮
Answer to HWs
Slide 48: -25v
Slide 52: 3/5A
Slide 71: (B) D>A>B>C
Slide 75: 6.3 min
Slide 76: (c) 60w bulb potential drop = 125 volt
100w bulb potential drop = 75 volt
Slide 77: (B) decreases
Slide 85: (B) 6π
Slide 86: (A) i-D 𝗶𝗶-𝗕 𝗶𝗶𝗶-𝗔 iv-C
Plz can u explain slide 71s answer?
In that question we just have to check the net resistance of circuits....aur firr jb har circuit ko ek equivalent resistance se represent krke dekhenge to jis circuit ka resistance jada hoga ussme power dissipation jada hoga kyuki I to sb me same hai so P=I²R se P directly proportional to R
Can u explain me slide 86 ...Mera 4 ka R/3 aa ra h
Hnn to 4th ka to R/3 hi to aayega @@Yuganshi_agrawal_
@agrwal866nhi switch off krne se resistance increase ho jaayega (kyuki remaining do bulb series me ) Aur resistance increase hone ki vajah se current decrease hoga ab kyuki series me hai bulbs to power I pe depend krega so I decrease hence power dissipation also decrease i.e. brightness decreased
Revision start 😊😊
Slide 22) R=pL/A
pL=constant
Resistance inversely propational to area
R/R'=A'/A=πR'²/πR²=3²/9²
R'=9×R=9×14 =126
Now if we use 7 resistance in parallel then Req=R'/7=126/7=18ohm. Ans.
41:50 R inversely proportional to A
Then new R = 126 ohm
But seven wires in parallel so new R = 126÷ 7= 18ohm (B) ans
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2:12:36 ...6π Ohm
D
Iska Solutions kese Kia bta do
@@poojapooja6845 R/L diya hua hai =120 toh ...phele length of wire nikaal lo
2πR= L ...toh yaha se L ayega 0.2π ...ab is value ko R/L=120 wale me daalo toh Resistance of wire aa jayega 24π ohm
Ab esko bent kr diya hai toh R/2 and R/2 parallel combination me h ...R/2=12 π ohm ayega
Toh...req 12π/2= 6π Ohm answer
Sir apne bilkul sahi kaha Aisa question pehle kabhi nhi dekha Isley neet mai bhi Aisa nhi dekhne ko milega .😊😂
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Sir main ek genuine cheez btata hun...
Meri neet mein 646 ayi hai but as we all know due to paper leak bht koi k nhi hua itne number pr bhi....
Sir jo student pyq bola plz uske ye bol digiyega ki 146 physics mein neet mein lane pr bhi apke current ke aaj ke question poore nhi bne...
Sir your content is just like pretty awesome for 180 on 180 in neet❤️❤️
Thank you sir 🙇🏻♀️💫💯
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42:00 slide 22
R is inversely proprtional to A ..so R1/R2= 7 r2^2/r1^2 ..solving this ans will be 18 ohm
46:45
u=et/m ..ud:up:ua=2:4:2 ..x=4(ans)
1:17:34
Vp= -25 V
1:24:36 slide 52
ans 3/5 A
2026 main kon neet ka exam dega ❤❤❤
Slide 52:- 1 R ka current 1/5 aega usko 3 se multiply karke ans 3/5 aega
Option - C
pakka?
@@diashaikh693 Ab kya stamp leker manogi 🤣
@@diashaikh693ammeter me right side ke 3 resistance se current pass hoga
1 branch me Current 1/5 A hi to 3 ka 3/5 A hoga
Thanku sir ji 🙏
Sabji m namak aukad anusar and mr ki class swad anusar🤤🤤
Ulta ho gilou 😃
2:12:35-b)6πohm
It's gonna my 5th and final drop...in 2025😊😊
Where are you from
@sujatasahu5407 kashmir
THANK YOU SIR 🔥..
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Neet 2025 attendance ❤
Level sabke niklenge
Pr niklega uska jo खड़ा रहेगा 😂
MR sir ka lecture dekh na ka baad
Me be like- Think Without INK ✍️
Medicine ( med easy physic) must take before coming in class and after class🔥🔥
Sir slide 22 ka atora sukha diya 👍👍