Basically in this method we say that infinity to any higher power is so big that infinity to any lower power is negligible in comparison so we only keep the terms containing the highest power but ignore everything else as comparatively it will be very negligible
If the highest order of the denominator is same with numerator, you only need to divide the coefficient of the highest order (coef. numerator/coef. denominaror)
From what I remember, this rule only applies if you’re dealing with fractions. I’m having to review this for series and sequences in Calc 2, but I promise it’s not that bad despite what others will say!
he is 'sneakily' using LHopital's rule here, which is only for 0/0 and inf/inf form. depending on functions, there may be some limits that get 0/0 or inf/inf by approaching a constant too
Just took x ( or x 's higher power) common from both numerator and denominator. After that common x 's will be cancelled, after that put the limit directly. Simple 💁🏻♂️
When the difference between dominant exponents is odd, and X approaches negative infinity. If said difference is positive, the limit is always positive infinity, regardless of which infinity X approaches.
It is soooo obvious... They grilled us with the squeeze theorem, so I stopped paying attention at all, even when fancy limits started and got my worst grade at maths ever. 😊
It won’t be because x is approaching infinity, x will be a large value, but say x was approaching 3 with this same function. Then the limit would not exist because as it approaches from the left y goes to negative infinity, and from the right it goes to positive infinity.
Basically in this method we say that infinity to any higher power is so big that infinity to any lower power is negligible in comparison so we only keep the terms containing the highest power but ignore everything else as comparatively it will be very negligible however with 0 this is not true
F(X)>g(X)=infinite
F(X)
Yeah 😊
Basically in this method we say that infinity to any higher power is so big that infinity to any lower power is negligible in comparison so we only keep the terms containing the highest power but ignore everything else as comparatively it will be very negligible
I dont get this concepts
@@bibibinafnaf1638 i think it only works when the limit approaches infinity
You can also think of it as omitting the non-leading terms.
That ending nearly gave me a heart attack
LMFAO
jumpscare
Jumpscare outro 😂
I'm sorry for that 😁
@@SerBee_29 but it's so cool 😭💗 you're so cool
I have NEVER had someone explain this to me so simply. You, sir, are a legend and a hero.
Thanks ☺️❤️
I remember limit being much much much more difficult than this, thank you for this.
Thanks❤️
Most limits are not this easy 😂 Those are limits where x approaches infinity, they are the easiest
Bro this is wild. I wish my professor didn’t make us show work
Simplified this for me thanks!
Thanks 😊
You are exceptional, thanks a million 🙏
Welcome ☺️
thanks! clear and concise!
Thanks ☺️❤️
This is fantastic
@@user-qy3lm3qx3y thank you ☺️
I learn something very important today
Wow. Grateful for this😊
Brother love and respect from India ❤
😊❤️
U just helped me pass exams thanks
Wow. Nice ❤️
teaching more than my calculus teacher
Great explanation
Thank you ☺️
Thanks a lot . It is best trick I think 🤔 ❤❤❤❤
You're welcome.
Thank you very very much 👏👏
Hi , your a good #teacher, I #wish #I’d had you in my #classroom
Thanks ☺️❤️
Thanks for giving shortcut i was trying to solve methodologically
You're welcome ☺️
Thanks ❤
❤️😊
Good.🙏❤
Thanks ❤️
If the highest order of the denominator is same with numerator, you only need to divide the coefficient of the highest order (coef. numerator/coef. denominaror)
Yeah
amazing video
Thanks 😊
Thanks because you are very shorted and explained us the way very easy
Thanks for the compliment 😊
@@SerBee_29 sir you Know My teacher also teaches me this today . I am a class 12 th student from India . In which class you are studying this ?
@@alwaywithtech7560thanks. I am from the Philippines. I am teaching Calculus in the tertiary level.
This is really cool
Thanks ☺️
genius 👍
ans1 ♾️
ans2 0
and3 non zero finite
Can you please show me how to answer Limit in exam in a more simple way 🙏
Do these tricks work for all questions have limit x->∞ ?
From what I remember, this rule only applies if you’re dealing with fractions. I’m having to review this for series and sequences in Calc 2, but I promise it’s not that bad despite what others will say!
MENTALLY DEFINITELY 🎉🎉
❤ thanks dear
Welcome ❤️
much easier way to get the answer gl bro
sure
yourrrrr decrrreeee is nice
Thanks 😊
But this is only possible when the limit x tends to infinity.
otherwise it would be easier, but in that case it will almost always be a zero division. At least in school
Yes
he is 'sneakily' using LHopital's rule here, which is only for 0/0 and inf/inf form. depending on functions, there may be some limits that get 0/0 or inf/inf by approaching a constant too
U can do the same to -inf, doing a substitution. Or even with 0, if u wanna use negative coeficients
the is very similar to horizontal asymptotes
Finally
Just took x ( or x 's higher power) common from both numerator and denominator.
After that common x 's will be cancelled, after that put the limit directly.
Simple 💁🏻♂️
Yeah
Good explanation ,
Also, when does it equal negative infinity?
When the difference between dominant exponents is odd, and X approaches negative infinity. If said difference is positive, the limit is always positive infinity, regardless of which infinity X approaches.
Salamat💞
Thanks ☺️❤️
Wow!
Thanks 😊
hello! your native language is english? greetings from Colombia ❤
@@Danieltampo Nope. I am Filipino. Thanks for the comment. Hello Columbia ❤️
Wow
Wow I just learned it for about 15s.
Thanks 😊
عالی
So we use the Horizontal Asymptote rules for limits too 😅😅😅
Genius
Ok i got it
I just hope there is no step marking in exams for this
Nice man thanks
You're welcome. Thanks.
But when we have the same coefficients up and down...we just divide their coefficients ❤
Infinity, 0 and 4
Hahahahha gagiks nagulat si me
Haha 😅
You are a GOD
The slim Jim method!
damn bro,wtf, how did all my teachers not tell me something so simple 😭💔
thanks man 🙏
You're very welcome 😊
It is soooo obvious... They grilled us with the squeeze theorem, so I stopped paying attention at all, even when fancy limits started and got my worst grade at maths ever. 😊
Sir more videos pa po 🫡
infinity
2
Thank uu, i really got this but before i was a little bit confused
❤🙂
do the same rules apply when x approaches -infinity?
Yeah
The slim Jim method
So if the numerators power is more than the denominator it's infinite. ....but if the denominator's power is greater....then its =0
Yeah
Sir plz upload more video of the shot trick
does it only work if x approaches to infinity or does that mean any number?
If x approaches to infinity only
How about kung may sign?
When do i get negative infinity
Limit of a function makes me like the topic"calculus" but you almost put me in difficulty here😔😔
💙
As an Indian I confirm we can solve such ques while sleeping
Wow, nice. We Filipinos can't do that.
Solved all three que in 5 seconds
Where did you get the 4?
Coefficient of the leading term
Is this possible only when x tends to infinity?
This is good for multiple choice FE exams tho
Yeah, very effective ❤️
When is it - infinite then?
Please can we solve like this only when lim x is at infinity
limits are so easy
Thats for horizontal asymptotes tho
when does ot give negative infinity
When there is negative sign
this is just LHopitals here. when we keep applying LH rule, the highest power will remain, hence putting the limit as per LH rule.
4÷ 2 is 8
Sir in number 1, wat if x is equal to -3?
It won’t be because x is approaching infinity, x will be a large value, but say x was approaching 3 with this same function. Then the limit would not exist because as it approaches from the left y goes to negative infinity, and from the right it goes to positive infinity.
💀❤️
What happens when u use l hospitals rule ?
is this only when x ~> ♾️ ?
Yeah
○○/○○=undefined ?
Bes on continues
How about with square root?
is this for real? what my teacher taught me has many solutions
Yeah of course
Can you explain us
Why the limit of first problem is infinity ♾️ ?
It's not wrong we 4 - 2 : is 2
this looks alot like asymptotes :000
I wish u posted this a year ago
Show us the graphs
wtf I was literally about to look for a video on this and this popped up my in my feed
how bout when its negative infinity
do the same rule when x approaches to -0?
nope
rationalise it
No, try to calculate it. If you end up with the indeterminate forms 0/0 or inf/inf, use l'Hopital's rule, if you've learned it.
Basically in this method we say that infinity to any higher power is so big that infinity to any lower power is negligible in comparison so we only keep the terms containing the highest power but ignore everything else as comparatively it will be very negligible however with 0 this is not true
mental L'Hopital's rule
Why?! Isn't it workable??
L’ hopital
Is this legal