1. Highway Runnery 2. Clippety Clobbered, Highway Runnery, Chariots of Fur, Shot and Bothered 3. Chaser on the Rocks, Coyote Falls, Chaser on the Rocks, Shot and Bothered, Coyote Falls, Boulder Wham!
0:36 I'm going to be extremely pedantic: technically the 2nd law is `F ∝Δp / Δt`, or `F = k * Δp / Δt`. In words, 'the force is proportional to the change in momentum over the change in time'. k is defined as 1 (i.e. a change in momentum of 1 kg ms^-1 over 1 second requires 1 newton of force), so `F = Δp / Δt`. From this, `F = ma` can be derived: p = mv, so Δp = `mv₂ - mv₁ = m(v₂ - v₁)`. This means `F = m(v₂ - v₁) / Δt = ma`. (My excuse for being pedantic is practise for my physics A-level paper 1 in 3 days :P.)
1. Highway Runnery
2. Clippety Clobbered, Highway Runnery, Chariots of Fur, Shot and Bothered
3. Chaser on the Rocks, Coyote Falls, Chaser on the Rocks, Shot and Bothered, Coyote Falls, Boulder Wham!
0:48
None of this explains how the Roadrunner is able to run through this brick wall without any harm to itself or the wall...
Quantum Tunneling
Road runner said goodbye now…
οπως πάντα:καταπληκτικό!
0:36
I'm going to be extremely pedantic: technically the 2nd law is `F ∝Δp / Δt`, or `F = k * Δp / Δt`. In words, 'the force is proportional to the change in momentum over the change in time'. k is defined as 1 (i.e. a change in momentum of 1 kg ms^-1 over 1 second requires 1 newton of force), so `F = Δp / Δt`. From this, `F = ma` can be derived: p = mv, so Δp = `mv₂ - mv₁ = m(v₂ - v₁)`. This means `F = m(v₂ - v₁) / Δt = ma`.
(My excuse for being pedantic is practise for my physics A-level paper 1 in 3 days :P.)